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Gaurav Seth 5 years, 3 months ago
Prime factors are those prime numbers which constitute to the formation of a number by multiplication of smaller prime numbers.
Now, let us first take the prime factors of the number 250, we get
Now the prime factor grouped together can be written as
Hence, the exponents for 2 and 5 are 1 and 3 respectively; therefore the sum of the exponent is
Hence, the sum of exponents of prime factors in the prime factorization of 250 = 4.
Posted by Kratagya Rathore 5 years, 3 months ago
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Gaurav Seth 5 years, 3 months ago
let the two angle be /x and /y
according to given condition-
/x+/y = 180 ----(1)
/x = /y + 18 -----(2)
substituting the value of (2) in (1)
(1) - /x+/y = 180
- (/y+18)+/y = 180
- 2/y+ 18 = 180
-2/y = 162
-/y= 81
substituting the value of y in (2)
/x=/y+18
/x=81+18
/x=99
Yash Gupta 5 years, 3 months ago
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Gaurav Seth 5 years, 3 months ago
A point on the line segment divides it into two parts which may equal or not. The ratio in which the point divides the given line segment can be found if we know the coordinates of that point. Also, it is possible to find the point of division if we know the ratio in which the line segment joining two points has given. These two things can be achieved with the help of a section formula in coordinate geometry.
Section formula is used to determine the coordinate of a point that divides a line segment joining two points into two parts such that the ratio of their length is m:n.
Let P and Q be the given two points (x1,y1) and (x2,y2) respectively, and M be the point dividing the line-segment PQ internally in the ratio m:n, then form the sectional formula for determining the coordinate of a point M is given by examole
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Archita Sinha 1204 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
6 = 2 × 3
72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
120 = 2 × 2 × 2 × 3 × 5 = 2³ × 3¹ × 5¹
HCF(6,72,120) => 2¹ × 3¹ = 6
LCM(6,72,120) => 2³ × 3² × 5¹ = 360
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Anuja Panwar 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Let the speed of Ritu in still water and the speed of stream be x km/h and y km/h.
Upstream = (x – y) km/h
Downstream = (x + y) km/h
⇒ 2(x + y) = 20
⇒ x + y = 10 ... (i)
⇒ 2(x – y) = 4
⇒ x – y = 2 ... (ii)
Putting this equation in (i), we get
⇒ y = 4
Ritu’s speed in still water is 6 km/h
The speed of the current is 4 km/h.
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Atul Kumar 5 years, 3 months ago
Atul Kumar 5 years, 3 months ago
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Madhu Kaushik 5 years, 3 months ago
1Thank You