No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Nidhi Jain 5 years, 2 months ago

Firstly make quadratic equation of -2 and -1 Like this x²-sx+p, where s=sum of zeroes and p=product of zeroes. Quadratic equation=x²+3x-2 Then divide x²+3x-2 with p(x)=2x⁴+x³-19x-6 The quotient you get after division, do the middle splitting of that equation you will get the 2 values of x which are the remaining zeroes.
  • 1 answers

Nikki Malik 5 years, 2 months ago

sn=n/2+(2a+(n-1)d
  • 0 answers
  • 2 answers

Rohit Panchal 5 years, 2 months ago

Your and is wrong ?

Naman Karwa 5 years, 2 months ago

When x=-1 Equation1: p(-1)^2 + 3(-1) +q=0 p - 3 + q = 0 => q = 3 - p.......a Equation2: p(-2)^2 + 3(-2) + q = 0 4p - 6 + q = 0 From eq a: 4p - 6 + 3- p = 0 .°. p = 1 So, q =3-p q = 2 Now, q - p = 2-1 = 1.......ans.
  • 1 answers

Bharti Kumari 5 years, 2 months ago

Underroot7 = a/b [ where a and b are co prime ] 7 = a^2 /b^2 [ squaring both side ] 7b^2 = a^2 ------(1) 7 divides a^2 7divides a Then , a can be written as 2m , where m is an integer . a = 7m 7b^2 = (7m)^2 [ from equation 1] 7b^2 =49m^2 b^2 =7m^2 7 divides b^2 7 divides b Thus, 7 is a common factor of a and b . a and b have no common factor other than 1. Hence , underroot 7 is irrational.
  • 1 answers

Gaurav Seth 5 years, 2 months ago

 it has no linear term and the constant term is negative.

Let      p(x) = x2 + ax + b.
Put a = 0, then,  p(x) = x2 + b = 0
⇒    x= -b
⇒  x = ± ±-b
[∴b < 0]
Hence, if one of the zeroes of quadratic polynomial p(x) is the negative of the other, then it has no linear term i.e., a = O and the constant term is negative i.e., b< 0.
Alternate Method
Let   f(x) = x2 + ax+ b
and by given condition the zeroes area and – α.
Sum of the zeroes = α- α = a
=>a = 0
f(x) = x2 + b, which cannot be linear,
and product of zeroes = α .(- α) = b
⇒ -α2 = b
which is possible when, b < 0.
Hence, it has no linear term and the constant term is negative.

  • 1 answers

Gaurav Seth 5 years, 2 months ago

By Euclid's division algorithm
b = aq + r,0 ≤ r < a [∵ dividend = divisor × quotient + remainder]
⇒ 117 = 65 × 1 + 52
⇒ 65 = 52 × 1 + 13
⇒ 52 = 13 × 4 + 0
∴ HCF (65,117) = 13             ...(i)     
Also, given that, HCF (65,117) = 65m - 117  ...(ii)
From Eqs.(i) and (ii),
65m - 117 = 13
⇒ 65m = 130
⇒ m = 2

  • 1 answers

Sia ? 4 years, 6 months ago

So, from the factorisation of 3 and 9, we can say that 9 is the LCM of 3 and 9. Hence, we can say that the HCF and LCM of the smallest odd composite number and the smallest odd prime number are 3 and 9 respectively.

  • 0 answers
  • 1 answers

Sia ? 4 years, 6 months ago

As given, when the original time is 10, it shows 9.10 on the watch, hence we can conclude that the watch is running 50 minutes slow( the time shown is 50 minutes behind the actual time). Hence, when the watch shows 11, the actual time should be 50 minutes ahead, which is 11.50.

  • 2 answers

Billu Pagi 5 years, 3 months ago

Hello

Amrita Kumari 5 years, 3 months ago

By solving quadratic equations
  • 1 answers

Rachit Sharma 5 years, 2 months ago

By your mind and some tactics ?
  • 3 answers

Akarsh Singh 5 years, 2 months ago

Have 2 zeroes

Payal Yadav 5 years, 2 months ago

Have two zeroes and it's a unique solution

Amrita Kumari 5 years, 3 months ago

Have two zeroes
  • 2 answers
https://chat.whatsapp.com/Gt8MJfdaS4RBpFaot9KmMb

Amrita Kumari 5 years, 3 months ago

No -150 is not any term of the given ap
3.5
  • 1 answers

Atul Raman 5 years, 2 months ago

Kay
  • 2 answers

Amrita Kumari 5 years, 3 months ago

√(6-3)^2+(5-2)^2 =3√2

Manvendra Runthala 5 years, 3 months ago

3√2
  • 0 answers
  • 0 answers
  • 0 answers
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App