CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Your answer : Mode-The most repetitive number! - Median:The number in the MIDDLE when they are IN ORDER! - Mean- The AVERAGE OF ALL NUMBERS: You add up all the numbers then you divide it by the TOTAL NUMBER of NUMBERS!

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The least no. That is divisible by all the no. from 1 to 5(both inclusive) is

Posted by Shambhavi Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Nidhi Jain 5 years, 2 months ago

I think 120

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The 5 term and 15 term of an ap is 13 and - 17

Posted by Priyanshu Arora 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Ncert lesson 1 example no. 5.

Posted by Vicky Kumar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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All the formulas of maths of all chapter of class X cbse

Posted by Prabhjot Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Subhalaxmi P 5 years, 2 months ago

Linear Equations One Variableax+b=0a≠0 and a&b are real numbersTwo variableax+by+c = 0a≠0 & b≠0 and a,b & c are real numbersThree Variableax+by+cz+d=0a≠0 , b≠0, c≠0 and a,b,c,d are real numbers Pair of Linear Equations in two variables: a1x+b1y+c1=0 a2x+b2y+c2=0 Where a1, b1, c1, a2, b2, and c2 are all real numbers and a12+b12 ≠ 0 & a22 + b22 ≠ 0 It should be noted that linear equations in two variables can also be represented in graphical form. Algebra or Algebraic Equations The standard form of a Quadratic Equation is: ax2+bx+c=0 where a ≠ 0 And x = [-b ± √(b2 – 4ac)]/2a Algebraic formulas: (a+b)2 = a2 + b2 + 2ab (a-b)2 = a2 + b2 – 2ab (a+b) (a-b) = a2 – b2 (x + a)(x + b) = x2 + (a + b)x + ab (x + a)(x – b) = x2 + (a – b)x – ab (x – a)(x + b) = x2 + (b – a)x – ab (x – a)(x – b) = x2 – (a + b)x + ab (a + b)3 = a3 + b3 + 3ab(a + b) (a – b)3 = a3 – b3 – 3ab(a – b) (x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2xz (x + y – z)2 = x2 + y2 + z2 + 2xy – 2yz – 2xz (x – y + z)2 = x2 + y2 + z2 – 2xy – 2yz + 2xz (x – y – z)2 = x2 + y2 + z2 – 2xy + 2yz – 2xz x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz) x2 + y2 =½ [(x + y)2 + (x – y)2] (x + a) (x + b) (x + c) = x3 + (a + b +c)x2 + (ab + bc + ca)x + abc x3 + y3= (x + y) (x2 – xy + y2) x3 – y3 = (x – y) (x2 + xy + y2) x2 + y2 + z2 -xy – yz – zx = ½ [(x-y)2 + (y-z)2 + (z-x)2] Click here to check all algebra formulas Basic formulas for powers pm x pn = pm+n {pm}⁄{pn} = pm-n (pm)n = pmn p-m = 1/pm p1 = p P0 = 1 Arithmetic Progression(AP) Formulas If a1, a2, a3, a4, a5, a6,… are the terms of AP and d is the common difference between each term, then we can write the sequence as; a, a+d, a+2d, a+3d, a+4d, a+5d,….,nth term… where a is the first term. Now, nth term for arithmetic progression is given as; nth term = a + (n-1) d Sum of the first n terms in Arithmetic Progression; Sn = n/2 [2a + (n-1) d] Trigonometry Formulas For Class 10 Trigonometry maths formulas for Class 10 cover three major functions Sine, Cosine and Tangent for a right-angle triangle. Also, in trigonometry, the functions sec, cosec and cot formulas can be derived with the help of sin, cos and tan formulas. Let a right-angled triangle ABC is right-angled at point B and have ∠θ. Sin θ= SideoppositetoangleθHypotenuse=PerpendicularHypotenuse = P/H Cos θ = AdjacentsidetoangleθHypotenuse = BaseHypotenuse = B/H Tan θ = SideoppositetoangleθAdjacentsidetoangleθ = P/B Sec θ = 1cosθ Cot θ = 1tanθ Cosec θ = 1sinθ Tan θ = SinθCosθ Trigonometry Table: Angle0°30°45°60°90°Sinθ01/21/√2√3/21Cosθ1√3/21/√2½0Tanθ01/√31√3UndefinedCotθUndefined√311/√30Secθ12/√3√22UndefinedCosecθUndefined2√22/√31 Swipe left Other Trigonometric formulas: sin(90° – θ) = cos θ cos(90° – θ) = sin θ tan(90° – θ) = cot θ cot(90° – θ) = tan θ sec(90° – θ) = cosecθ cosec(90° – θ) = secθ sin2θ + cos2 θ = 1 sec2 θ = 1 + tan2θ for 0° ≤ θ < 90° Cosec2 θ = 1 + cot2 θ for 0° ≤ θ ≤ 90° Get complete Trigonometry Formulas list here Circles Formulas For Class 10 Circumference of the circle = 2 π r Area of the circle = π r2 Area of the sector of angle θ = (θ/360) × π r2 Length of an arc of a sector of angle θ = (θ/360) × 2 π r (r = radius of the circle) Surface Area and Volumes Formulas For Class 10 The common formulas from the surface area and volumes chapter in 10th class include the following: Sphere Formulas Diameter of sphere2rSurface area of sphere4 π r2Volume of Sphere4/3 π r3 Cylinder Formulas Curved surface area of Cylinder2 πrhArea of two circular bases2 πr2Total surface area of CylinderCircumference of Cylinder + Curved surface area of Cylinder = 2 πrh + 2 πr2Volume of Cylinderπ r2 h Cone Formulas Slant height of conel = √(r2 + h2)Curved surface area of coneπrlTotal surface area of coneπr (l + r)Volume of cone⅓ π r2 h Cuboid Formulas Perimeter of cuboid4(l + b +h)Length of the longest diagonal of a cuboid√(l2 + b2 + h2)Total surface area of cuboid2(l×b + b×h + l×h)Volume of Cuboidl × b × h Here, l = length, b = breadth and h = height In case of Cube, put l = b = h = a, as cube all its sides of equal length, to find the surface area and volumes. Statistics Formulas for Class 10 In class 10, the chapter statistics mostly deals with finding the mean, median and mode of grouped data. (I) The mean of the grouped data can be found by 3 methods. Direct Method: x̅ = ∑ni=1fixi∑ni=1fi, where ∑fi xi is the sum of observations from value i = 1 to n And ∑fi is the number of observations from value i = 1 to n Assumed mean method : x̅ = a+∑ni=1fidi∑ni=1fi Step deviation method : x̅ = a+∑ni=1fiui∑ni=1fi×h (II) The mode of grouped data: Mode = l+f1–f02f1–f0–f2×h (III) The median for a grouped data: Median = l+n2–cff×h

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Vicky Kumar 5 years, 2 months ago

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Gopal Chaudhary 5 years, 2 months ago

Chapter ya question ke photo bhejo thabhi to bta payenge

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Rishika Sharma 5 years, 2 months ago

Konsa ch ka ek ek kr k pucho aise to aap v confused hoge aur hm sb v

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All the formulas of maths ofball chapter pf cbse board

Posted by Prabhjot Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Find the value of y for which the distance between point A(3,-1) and B(11,y) is 10 minutes

Posted by Ambika Ambika 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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If that tan theta 15 /8 find the volume of the of all t ratio of theta book name r s agrwal

Posted by Sonam Kumari Paswan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Rishika Sharma 5 years, 2 months ago

Solution: Tan theta =15/8(given) We know that, Tan theta=p/b Now, we use Pythagoras theorem So, (Hypo)²=(perpendicular)²+(base)² Therefore, H²=(15)²+(8)² =225+64 = 289 H=√289 = 17 Hence, Sin theta=15/17 Cos theta=8/17 Tan theta=15/8 Cot theta=8/15 Cosec theta=17/15 Sec theta =17/8 I hape it is helpful for you

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Sonam Kumari Paswan 5 years, 2 months ago

ch 10 ex 10 Question number 3 please help me

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Show that square of any positive odd integer is of the form 8q+1, for some interger q

Posted by Deepu Singh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Ambika Ambika 5 years, 2 months ago

8(8m2+14m+6)+1=8q+1

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Suggest me channel for the maths on YouTube

Posted by Akshita Akshita 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Neha Kakkar ?? 5 years, 2 months ago

Mathematics class 10.

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Vicky Kumar 5 years, 2 months ago

Maths solver

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Helper . 5 years, 2 months ago

Maths teacher and maths padho sir

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Aayush Raj 5 years, 2 months ago

Green board

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Aditya Srivastav 5 years, 2 months ago

Green board and Mathematics class 10.

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Find the hcf of 272 and 148 and express it as 272p+148q

Posted by Palak Tanwani 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Palak Tanwani 5 years, 2 months ago

How do we get the value of p and q

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Yogita Ingle 5 years, 2 months ago

272 = 2 × 2 × 2 × 2 × 17

148 = 2 × 2 × 37

Therefore ,

HCF ( 272 , 148 ) = 2 × 2 = 4

By using Euclid's algorithm :

Since , 272 > 148 , we apply the division lemma to 272 and 148 , to get

272 = 148 × 1 + 124

Since the remainder 124 ≠ 0 , we apply the division lemma to 148 and 124 , to get

148 = 124 × 1 + 24

We consider the new divisor 124 and the new remainder 24 , and apply the division lemma to get

124 = 24 × 5 + 4

We consider the new divisor 24 and the new remainder 4 , and apply the division lemma to get

24 = 4 × 6 + 0

The remainder has now become zero , so our procedure stops , since the divisor at this stage is 4 , the HCF of 272 and 148 is 4

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Aditya Kumar 5 years, 2 months ago

P=(6) , q=(-11)

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Find the coordinates of the circumcentre of the tringle whose vertices are (3, 0), (-1, -6), (4, -1). Also, find it's circumradius.

Posted by Gajendra Prasad Mallick 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Q1.WriteReena's1st,2nd,3rdand4thyearssalariesandthedifference betweenthesalariesofanyofthetwoconsecutiveyears.Thelistofsalaries soformedisknownas__________andthedifferenceiscalled__________. Whatistheformulaforhernthyearsalary?

Posted by Divyansh Chaurasia 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Howmanytermsofabovelistofsalaries(fromtheme)mustbetakento giveasum ofRs12,9000.Findthesum offirst22yearssalariesofoneone monthiftheincrementisRs600insteadofRs500andwhatwillbeher22 yearssalary?

Posted by Anmol Gupta 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Thesum offirst6yearssalariesofoneonemonthisRs60,000.Which formulawillbeusedtocalculatethesumdirectly,thenfindthesumoffirst18 yearssalariesofoneonemonths.

Posted by Anmol Gupta 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Sunaina Sahu 5 years, 2 months ago

Please use space key

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Writeher2nd,3rdand4thyearsalarybeforelastyear.Alsowritedownthe formulaforit.Findher11thyearsalaryfromthelastbyusingformula.

Posted by Anmol Gupta 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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CheckwhetherRs9200canbehersalaryinanyoftheyearornot.After howmanyyearssheleftthejobifhersalarywasRs32,500atthattime?

Posted by Anmol Gupta 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Samarth Tembhurnikar 5 years, 2 months ago

Please give some space between words ?

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WriteReena's1st,2nd,3rdand4thyearssalariesandthedifference betweenthesalariesofanyofthetwoconsecutiveyears.Thelistofsalaries soformedisknownas__________andthedifferenceiscalled__________. Whatistheformulaforhernthyearsalary?Usingthisformulafindher25th yearssalary.

Posted by Anmol Gupta 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Determine whether the given quadratic equation have real roots so find root xsquare+x+2=0

Posted by Shivanah Verma 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Omkar Bhongale 5 years, 2 months ago

No real roots

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Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides

Posted by Yash Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Rohit Kumar 5 years, 2 months ago

Given:- A right triangle ABC right angled at B. To prove:- AC2=AB2+BC2 Construction:- Draw BD⊥AC Proof:- In △ABC and △ABD ∠ABC=∠ADB(Each 90°) ∠A=∠A(Common) ∴△ABC∼△ABD(By AA) ACAB=ABAD(∵Sides of similar triangles are proportional) ⇒AB2=AD⋅AC.....(1) Similarly, in △ABC and △BCD ∠ABC=∠BDC(Each 90°) ∠C=∠C(Common) ∴△ABC∼△BCD(By AA) ∴BCDC=ACBC ⇒BC2=DC⋅AC.....(2) Adding equation (1)&(2), we have AB2+BC2=AD⋅AC+DC.AC ⇒AB2+BC2=AC(AD+DC) ⇒AB2+BC2=AC2 Hence proved.

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Find the value of k such that the polynomial x2 -(k + 6)x + 2(2k - 1) has sum of its zeros equal to half of their product.

Posted by Yash Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditya Kumar 5 years, 2 months ago

K=7

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Prove that in a right angle triangle, the square on the hypotenuse is equal to sum of squares on other two sides using above prove the following in △ ABC, ∠ A = 90o and AD ⊥ BC. Prove that AB2 + CD2 = BD2 + AC2.

Posted by Yash Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Find all Zeros of the polynomial x4 + x3 – 9x2 – 3x + 18, if it is give that two of its zero’s are - and.

Posted by Yash Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of ⊡ABCD. Find its area.

Posted by Yash Mishra 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Yogita Ingle 5 years, 2 months ago

by joining B to D,you will get two Triangles ABD and BCD the area of triangle A b d

1/2[-5(-5-5)+(-4)(5-7)+4(7+5)]=0

1[50+8+48]0×2

=106/2

=53square.units

also the area of triangle BCD

=1/2[-4(-6-5)-1(5+5)+4(-5+6)]

=1/2[44-10+4]

=19 square.units

area of triangle ABC + area of triangle BCD

so the area of quadrilateral ABCD =53+19=72square.units

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Which term of AP is 21,41,63.....is 210.

Posted by Aman Aditya Kumar ... 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 5 years, 2 months ago

In the given A.P ;
a = 21
d = 42-21 = 21
l = 210
n = ?
l = a +(n-1)d
210 = 21+(n-1)21
n-1 = 189/21
n = 9+1
n = 10
hence 210 is the 10th term of given A.P

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Saurabh ???? 5 years, 2 months ago

I think about it is not good question. Something is wrong in this question

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How do we find mean by assume mean method in exercise 14.2question no.3

Posted by Sunaina Sahu 5 years, 2 months ago

CBSE > Class 10 > Mathematics