CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Here, A = (a² + b²), B = - 2(ac + bc) and C = (c² + d²). As roots are equal, D ⇒ b² - 4ac = 0 B² = 4ac ⇒ [- 2(ac + bd)]² = 4(a² + b²) (c² + d²) ⇒ (a²c² + 2abcd + b²d²) = 4(a²c² + a²d² + b²c² + b²d²) ⇒ 2 abcd = a²d² + b²c² ⇒ 0 = a²d² - 2abcd + b²c² ⇒ 0 = (ad - bc)² ⇒ 0 = ad - bc ⇒ ad = bc ⇒ a/b = c/d. HOPE IT HELPS YOU?✌

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Rohit Kumar 5 years, 2 months ago

Answer :- Here, A = (a² + b²), B = - 2(ac + bc) and C = (c² + d²) As roots are equal, D ⇒ b² - 4ac = 0 B² = 4ac ⇒ [- 2(ac + bd)]² = 4(a² + b²) (c² + d²) ⇒ (a²c² + 2abcd + b²d²) = 4(a²c² + a²d² + b²c² + b²d²) ⇒ 2 abcd = a²d² + b²c² ⇒ 0 = a²d² - 2abcd + b²c² ⇒ 0 = (ad - bc)² ⇒ 0 = ad - bc ⇒ ad = bc ⇒ a/b = c/d

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Riya Philip 5 years, 2 months ago

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Solve the equation by elimination method X - 5y = 11 2x +3y=4

Posted by Poorvi Poorvika 5 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Riya Philip 5 years, 2 months ago

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? Yang ? 5 years, 2 months ago

2x+3y+4=0 x-5y=11 multipy 2nd equation with 2 then you get 2x-10y=22 now subtract this equation from equation 1 2x+3y+4=0 2x-10y. =22 by solving we get y=-2 and substitute y value in above equation and get x=1. HOPE IT HELPS YOU?✌

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Dikshant Sharma 5 years, 2 months ago

2x+3y+4 =0 And x-5y-11=0 now multiply second equation by 2 then you'll get

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Yogita Ingle 5 years, 2 months ago

2x+3y+4=0
x-5y=11
multipy 2nd equation with 2 then you get
2x-10y=22
now subtract this equation from equation 1
2x+3y+4=0
2x-10y. =22
by solving we get
y=-2
and substitute y value in above equation and get
x=1

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Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.

Posted by Aditya Shejal 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Rohit Kumar 5 years, 2 months ago

K= 27

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Find the tow consitive integer sum shoes square is 365

Posted by Jahnavi .T 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Hmmmmmmmmmm, Okkkkkkkkkkkkk.

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4k-5y=k 2k-3y=k

Posted by Mahak Solanki 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Find the area of the quadrilateral whose vertices taken in order are (–4, –2), (–3, –5), (3, –2) and (2, 3).

Posted by Surya Kumar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Rohit Kumar 5 years, 2 months ago

Let the vertices of the quadrilateral be A ( - 4, - 2), B ( - 3, - 5), C (3, - 2), and D (2, 3). Join AC to form two triangles ΔABC and ΔACD. Area of a triangle = 1/2 {x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2)} Area of ΔABC = 1/2 [(-4) {(-5) - (-2)} + (-3) {(-2) - (-2)} + 3 {(-2) - (-5)}] = 1/2 (12+0+9) = 21/2 square units Area of ΔACD = 1/2 [(-4) {(-2) - (3)} + 3{(3) - (-2)} + 2 {(-2) - (-2)}] = 1/2 (20+15+0) = 35/2 square units Area of ☐ABCD = Area of ΔABC + Area of ΔACD = (21/2 + 35/2) square units = 28 square u

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Prove cos square theta+1/1+cot square theta =1

Posted by Lehashree Srinivasan 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Kumar 5 years, 2 months ago

Cos²A + 1/(1+cot²A) Cos²A + 1/(1+ cos²A/sin²A) Cos²A + 1/{(sin²A+cos²A) /sin²A} Cos²A + 1/1/sin²A Cos²A + sin²A =1

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The sum and product of the zeroes of the polynomial 9xpower2-5 respectively are:

Posted by Anurag Maurya 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Omkar Bhongale 5 years, 2 months ago

Sum = 5/9, Product = 0

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Anurag Maurya 5 years, 2 months ago

Ask someone else

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Anurag Maurya 5 years, 2 months ago

I don't know

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Factorise x^2-270x -1800000

Posted by Tanishq Rai 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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If sec theta is equal to 5.4 so that 2 cos theta minus sin theta upon cos theta minus 10 theta

Posted by Prashant Yadav 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Q. If sinA+cosA=x,Prove that sin^6A+cos^6A=4-3(x^2-1)^2/4

Posted by Rohit Kumar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Riya Philip 5 years, 2 months ago

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Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively 1/4, -1

Posted by Yash Sahu 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Yash Sahu 5 years, 2 months ago

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Prove that.cot A-cos A/cot A+cos A=cosecA-1/cosecA+1

Posted by S. Gautham 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Samraat Sahil Verma 5 years, 2 months ago

LHS CotA-cosA/cotA+cosA Divide numerator and denominator by cosA =(cotA/cosA-cosA/cosA)/(cotA/cosA+cosA/cosA) =(cosA/sinA•1/cosA-1)/(cosA/sinA•1/cosA+1) (1/sinA-1)/(1/sinA+1) =(cosecA-1) /(cosecA+1)(since 1/sinA=cosecA) =RHS

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Find the area of circle whose cicumferrence is 22cm.

Posted by S. Gautham 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

Circumference of circle = 22 cm
Let the radius of the given circle be 'r'
Circumference of a circle = 2πr
⇒ 22 = 2 × 22/7 × r
⇒ r = (22 × 7)/(22 × 2)
⇒ r = 154/44
⇒ r = 3.5 cm
Area of circle = πr²
⇒ 22/7 × 3.5 × 3.5
⇒ 269.5/7
= 38.5 cm²
So, the area of the given circle is 38.5 cm²

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Find the zeroes of the following quadratic polynomial 4u^2+8u

Posted by Priyanshu ?✌??? 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Samraat Sahil Verma 5 years, 2 months ago

4u^2+8u=4u(u+2) Either 4u=0 =u=0/4=0 Or u+2=0 =u=-2 Zeros are 0,-2 Sum of zeros=o+(-2)=-2=-8/4=-(Coefficient of u)/(Coefficient of u^2) Product of zeros=0×(-2)=0=0/4=constant term/Coefficient of u^2

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What is the formula to get roots of a quadratic equation?

Posted by Anshuman Omm 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Sandeep Navtiya 5 years, 2 months ago

x = -b±√b²-4ac/2a It's a correct formula ?

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Prakhar Mishra 5 years, 2 months ago

-b+under root b^2-4ac/2a

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If the zeroes of x cube-6x square+ 3x + m are (a-d), a and (a+d) then m =?

Posted by Davinder Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Kumar 5 years, 2 months ago

1st step Sum of zeros ka formulae lagao isse tumhara ; a=2 niklega 2nd step alpha. bita+bita × gama+gama × alpha ka formulae lagao aur a ka value put karo to ; d=3 niklega 3rd step Product of zeroes ke formulae me A or D ka value put karo to m= 10 ayega

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Aditya Kumar 5 years, 2 months ago

M=10

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How many two digit number are divisible by 6 ?

Posted by Ankit Kumar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Anjali Prajapati 5 years, 2 months ago

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Saurabh ???? 5 years, 2 months ago

an=a+(n-1) d 96=6+(n-1) 6 96=6+6n-6 96=6n n=96/6=16

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Anmol Dwivedi 5 years, 2 months ago

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? Yang ? 5 years, 2 months ago

12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90 & 96. HOPE IT HELPS YOU?

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? Yang ? 5 years, 2 months ago

15(FIFTEEN). HOPE IT HELPS YOU?✌

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[3^(x+2)]+[3^(-x)]=10

Posted by Pawan Ramse 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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For any positive real number 'a' ,prove that there exists an irrational number b such that 0<b<a

Posted by Balanagasri Thota 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Show that 1/2-√3 is irrational

Posted by Balanagasri Thota 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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Prove that 3√7(cube root 7) is an irrational

Posted by Balanagasri Thota 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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2x+2y=0

Posted by Aditya Patil 5 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Shraddha Panchbhai 5 years, 2 months ago

x+y=o Or y=-x

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Yuvraj Rathore 5 years, 2 months ago

Linear equation in two variables

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Linear equation in two variables

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Q. The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle.

Posted by Rohit Kumar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 5 years, 2 months ago

Exterior angle bisector theorem : The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle.

Given : A ΔABC, in which AD is the bisector of the exterior ∠A and intersects BC produced in D.

Prove that : BD / CD = AB / AC

Construction : Draw CE || DA meeting AB in E.

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1) CE \|\| DA	1) By construction
2) ∠1 = ∠3	2) Alternate interior angle
3) ∠2 = ∠4	3) Corresponding angle (CE \|\|DA and BK is a transversal
4) AD is a bisector of ∠A	4) Given
5) ∠1 = ∠2	5) Definition of angle bisector
6) ∠3 = ∠4	6) Transitivity (from 2 and 4)
7) AE = AC	7) If angles are equal then side opposite to them are also equal
8) BD / CD = BA/EA	8) By Basic proportionality theorem(EC \|\|AD)
9) BD /CD = AB/AE	9) BA = AB and EA = AE
10) BD /CD = AB /AC	10) AE = EC and from(7)

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Krishna Kumawat 5 years, 2 months ago

Exterior angle bisector theorem : The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle. Given : A ΔABC, in which AD is the bisector of the exterior ∠A and intersects BC produced in D.

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What is the smallest LCM

Posted by Ramna Kulriya 10Th B 5 years, 2 months ago

CBSE > Class 10 > Mathematics