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Shubham Saxena ???? 5 years, 2 months ago
Maahi ......♾ 5 years, 2 months ago
Priya ✧*。٩(๑˙╰╯˙๑)و✧*。 5 years, 2 months ago
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Shubham Saxena ???? 5 years, 2 months ago
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Posted by Shubham Saxena ???? 5 years, 2 months ago
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Posted by Shubham Saxena ???? 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
If sinA = 12 / 13 , so find 1 / cos A = ?
sin2A + Cos2A = 1
(12/13)2 + cos2A = 1
144/169 + cos2A = 1
cos2A = 1 - 144/169
cos2A = (169-144)/169
cos2A = 25/169
cos A = 5/13
1/cosA = 13/5
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Shubham Saxena ???? 5 years, 2 months ago
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Shubham Saxena ???? 5 years, 2 months ago
2Thank You