CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

d = 5

S9 = 75

By applying the formula

S_n = n / 2 + ( 2a + ( n - 1 ) × d

75 = 9 / 2 + (2a + ( 9 - 1 ) × 5

75 = 9 / 2 + ( 2a + 40 )

75 × 2 / 9 = 2a + 40

50 / 3 = 2a + 40

50 / 3 - 40 / 1 = 2a

by taking LCM we will get

- 70 / 3 = 2a

a = - 70 / 3 × 2

a = - 35 / 3.

a₉ = a + 8d

= -35 / 3 + 8 × 5

= - 35 / 3 + 40

= -35 + 120 / 3

= 95 / 3.

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Avada Kedavara

Posted by Arnav Agarwal 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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3/3+3/3

Posted by Satendra Singh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Yangzee Sherpa 5 years, 2 months ago

?TWO(2)?. HoPe It HeLpS yOu??

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Shubham Saxena ???? 5 years, 2 months ago

3/3+3/3 = 2 .

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Amit Tanwar 5 years, 2 months ago

2/3

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Vaishali Yadav 5 years, 2 months ago

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Nehal Arora 5 years, 2 months ago

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Which exercises is deleted from from triangles as per new syllabus?

Posted by Asmita Belapurkar 5 years, 2 months ago

CBSE > Class 10 > Mathematics

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a circus artist is climbing a20 long frock which established stretched from the top of a vertical poles the ground find the height of the pool if the angle made by the rope with the ground level is 30 degree

Posted by Aditya Pandey A 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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I have recently asked questions. Answer my questions .

Posted by Shubham Saxena ???? 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Gayatri Singh 5 years, 2 months ago

What is your question

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Determine sin A, cos A

Posted by Sandhiya Ramesh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Saxena ???? 5 years, 2 months ago

Sin A = p / h ( perpendicular / hypotenuse) = 1 / cosec A .,, Cos A = b / h ( base / hypotenuse ) = 1 / sec A .... Thank you.

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Sanjana R 5 years, 2 months ago

sinA=opp/hyp=1/cosecA cosA=adj/hyp=1/secA

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Find the sum of first 22 terms of the AP 8,3,-2,....

Posted by Yashoda Hp 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Saxena ???? 5 years, 2 months ago

A = 8 ,, d = 3 - 8 = - 5 ,, S22 = 22 / 2 [ 2 ( 8 ) + ( 22 - 1 ) - 5 ,, S22 = 11 [ 16 + 21 × - 5 ] ,, S22 = 11 [ 16 + ( - 105 ) ] ,,,, S22 = 11 [ - 121 ] ,, S22 = - 1331 . = - 1331 . Thank you.

2Thank You

Yogita Ingle 5 years, 2 months ago

a=8

d=3−8=−5

S₂₂=n/2[2a+(n−1)d]

S₂₂=22/2[2a+21d]

S₂₂=11[2(8)+21(−5)]

S₂₂=11(−89)

=−979.

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ANSWER

The value of k the following pair of linear equations has no solution x-2y =3,3x+ky=1

Posted by Deepali Dhandhi 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sanskriti Mathur 5 years, 2 months ago

K=-6 & k is not equal to -2/3

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If sinA +cosA =1 then cos A-sin A=

Posted by Deepali Dhandhi 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

If sinA +cosA =1

cos A = 1 - sin A

then cos A-sin A= 1 - sin A - sin A = 1 - 2 sin A

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(1+cosA)(1-cosA)(1+cot2A )

Posted by Deepali Dhandhi 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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In Fig. 3, APB and AQO are semicircles, and AO = OB. If the perimeter of the figure is 40 cm, find the area of the shaded region. Use π =227

Posted by Shristi Thapa 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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Determination the nth term of the AP whose 7th term is -1 and 16th term is 17. Please help to solve this question.

Posted by Smriti Prabha 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Nitesh Jogi 5 years, 2 months ago

A+6d=-1 /A+15d=17 A=-1-6d /-1-6d+15d =17 A=-1-6d /-1+9d=17 A=-1-6d /9d=18 ". /d=2 Putting the value of d in a, we get. A=-1-6(2) A=-13 An=a+(n-1)d An=-13 + (n-1) 2 An=-13 +2n-2 An=-15+2n Hence, the nth term of the ap is - -15+2n.

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Jamna Thakur 5 years, 2 months ago

Gggdhdhyttg gggdhdhyttg FF FF and joyful

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A wire 112 cm long is bent to form a right-angled triangle. If the hypotenuse is 50 cm long, find the area of the triangle.

Posted by Subasree Dhanasekaran 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 2 months ago

Let the other 2 sides be x, y
Length of hypotenuse = 50 cm
Total length =112cm
x + y +50 =112
x + y =112 - 50
x + y = 62
By pythagorous theorem
x² + y² = 50²
x² + y² = 2500
(x + y)² - 2xy = 2500
-2xy = 2500 - 3844
= - 1344
xy = 1344/2
= 672
Area of triangle = 1/2xy
= 1/2*672
= 336
Therefore, area of the triangle = 336cm²

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How will you show that silver is less reactive than copper ??

Posted by Shubham Saxena ???? 5 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Shubham Saxena ???? 5 years, 2 months ago

Ok thanks.

3Thank You

Tapish Sharma 5 years, 2 months ago

Take copper sulphate in a test tube and place a silver few granules in it... this show silver is less reactive than copper.

2Thank You

Shubham Saxena ???? 5 years, 2 months ago

Ok thanks for answering. Good answer.

2Thank You

Yogita Ingle 5 years, 2 months ago

Silver is chemically less reactive than copper can be shown by displacement reaction. If a piece of silver is placed in a solution of CuSO4 no reaction will take place as Ag is less reactive than Cu and can't replace Cu from CuSO4 solution. ... This shows Ag is chemically less reactive than copper.

2Thank You

Maahi ......♾ 5 years, 2 months ago

Take copper sulphate in a test tube and place a silver few granules in it... this show silver is less reactive than copper.

2Thank You

ANSWER

Children get opportunities paragraph error correction

Posted by Piyush Aggarwal 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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R D solutions

Posted by Rakshit Keswani 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Rakshit Keswani 5 years, 2 months ago

I need R D solutions

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1/cosec theta -cot theta -1/sin theta=1/sin theta-1/cosec theta+cot theta

Posted by Sahil Hussain 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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A line drawn through the midpoint of one side of a triangle parallel to another side bisect the third side

Posted by Abhijit Jagtap 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhijit Jagtap 5 years, 2 months ago

Given:- In triangle abc D is midpoint on the line ABand c is midpoint on line AC DE parallel to Bc to prove:-AE = EC PROOF:- IN ∆ABC DE||BC AD/DB=AE/EC. (1)[BY BPT] D is midpoint AD=DB AB/ DB=1. (2) FROM 1 AND 2 , WE GET AE=EC HENCE PROVED

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the coordinates of one endpoint of a diameter a b of a circle are A4 and -1 and the coordinates of the centre of the circle r c is equals to 1 and minus 3 then the coordinates of point b r

Posted by Raman Sharma 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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If angle pba =30 pt is a tangent and ab is a diameter then find angle pta in circle

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CBSE > Class 10 > Mathematics

1 answers

Yashsvee Kumar 5 years, 2 months ago

Hey Sneha plz reply kr I have a good news for scholarship

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Prove that x ( x + 1 ) = 2 ( x - 1 ) is a quadratic equation ??

Posted by Shubham Saxena ???? 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Saxena ???? 5 years, 2 months ago

Ok thanks for answering. Welldone

1Thank You

Yogita Ingle 5 years, 2 months ago

x ( x + 1 ) = 2 ( x - 1 )

x² + x = 2x - 2

x² + x - 2x + 2 = 0

x² - x + 2 = 0

It is quadratic equation.

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Ncert ch 7 sloutions

Posted by Anshika Sheoran Sheoran 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the mean of the following distribution as assumed method? x ,12,16,20,24,28,32 f,5,7,8,5,3,2

Posted by Mohd Sahil 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

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The value of expressions cosec(75°+A)-sec(15°-A) - tan (55°-A)+ cot (35°-A)

Posted by Nahid Shekh 5 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If 1+tanA=30 then find the value of sinA+cos^2A

Posted by Nihal Asati 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Tarannum Jahan 5 years, 2 months ago

Given: 1+tanA= 30 tanA=30/1 We know that tanA=sinA/cosA Now, sinA =30 and CosA=1 Here sinA+cos^2A =30 +(1)^2 =30+1 = 31 Ans

2Thank You

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Find the positive root of 3xsquare +6x-9=0

Posted by Gurdeep Kaur 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Saxena ???? 5 years, 2 months ago

3x² + 6x - 9 = 0 ,, 3x² + 9x - 3x - 9 = 0 ,, 3x ( x + 3 ) - 3 ( x + 3 ) ,, = (3x - 3 ) ( x + 3 ) = 0 ,, = x = 3/3 = 1 . ,,,, x = - 3 .,,,, First root is [ x = 1] ,, second root is [ x = - 3 ] . So , the positive root of. 3x² + 6x - 9 = 0 is 1 Ans . Thank you.

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Yogita Ingle 5 years, 2 months ago

3x² + 6x = 9
3x² + 6x - 9 = 0
3x² + 9x - 3x - 9 = 0
3x(x + 3) - 3 (x +3) = 0
(x + 3) ( 3x - 3)= 0
x + 3 = 0 or 3x - 3 = 0
x = -3 or 3x = 3
x = -3 or x = 3/3 = 1

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Please provide my practical file work of mathematics

Posted by Shreepriya Sharma Sharma 5 years, 2 months ago

CBSE > Class 10 > Mathematics