Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Krishna Chaudhary 5 years, 1 month ago
- 2 answers
Posted by Parneet Kaur 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
ABCD is a trapezium with AB || DC, E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB show that 
Given trap. ABCD in which AB || DC and EF || AB.
To prove: 
Const: Join A-C.
Proof: ∵ AB || DC and EF || AB
⇒ AB || EF || DC
Now, in ∆ADC, we have
...(i)
[using Basic proportionality theorem]
Now, in ∆ABC, we have
...(ii)
Comparing (i) and (ii), we get
Posted by Riya Tiwari 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
We have,
2x + 3y = 11 ….(1)
2x – 4y = – 24 ….(2)
From (1), we have 2x = 11 – 3y
Substituting 2x = 11 – 3y in (2), we get
11 – 3y – 4y = –24
⇒ –7y = – 24 – 11
⇒ –7y = – 35
⇒ y = 5
Putting y = 5 in (1), we get
2x + 3 × 5 = 11
2x = 11 – 15
⇒ x = –4/2 = – 2
Hence, x = – 2 and y = 5
Again putting x = – 2 and y = 5 in y = mx + 3, we get
5x = m(–2) + 3
⇒ –2m = 5 – 3
⇒ m = – 1
Posted by Sarandeep Singh 5 years, 1 month ago
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Posted by Aman Thind 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
Let the positive square root be 'x'
The number is x^2
x^2 +x = 90
x^2+x-90=0
x^2 +10x-9x-90= 0
x(x+10)-9(x+10) =0
X=9, x=-10
x cannot be -10 because square root is positive number.
there x = 9
The number is 81.
Posted by ☆°••(Prateek)••° ☆ 5 years, 1 month ago
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Malaika Sharma 5 years, 1 month ago
Posted by Charu Arora 5 years, 1 month ago
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Manthan Singhal 5 years, 1 month ago
Gaurav Seth 5 years, 1 month ago
Let the sides of the two squares be x cm and y cm where x > y.
Then, their areas are x2 and y2 and their perimeters are 4x and 4y.
By the given condition:
x2 + y2 = 400...(1)
and 4x - 4y = 16
4(x - y) = 16 x - y = 4
x = y + 4... (2)
Substituting the value of x from (2) in (1), we get:
(y + 4)2 + y2 = 400
y2 + 16 + 8y + y2 = 400
2y2 + 16 + 8y = 400
y2 + 4y - 192 = 0
y2 + 16y - 12y - 192 = 0
y(y + 16) - 12 (y + 16) = 0
(y + 16) (y - 12) = 0
y = -16 or y = 12
Since, y cannot be negative, y = 12.
So, x = y + 4 = 12 + 4 = 16
Thus, the sides of the two squares are 16 cm and 12 cm.
Posted by Manual Khan 5 years, 1 month ago
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Posted by Dilraj Kâlêsh 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear
<hr />Let the given points be A( 1, 5), B(2, 3) and C(-2, -11). Then
Here, we see that AB + BC ≠ AC, BC + AC ≠ AB and AB + AC ≠ BC.
Hence, the points A, B and C are not collinear.
Posted by Meenakhsy Majhi 5 years, 1 month ago
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Posted by Simran Rani 5 years, 1 month ago
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Simran Rani 5 years, 1 month ago
Posted by Dilraj Kâlêsh 5 years, 1 month ago
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Ashish V 5 years, 1 month ago
Posted by Ayush Prashar 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
The fact is that the question paper revolves around the NCERT textbook and the concepts explained therein. Hence, in theory, the NCERT textbook should be more than enough. However, in practice, students have found that referring to a good reference book acts as an aid or supplement. For example, if you use a reference book in Mathematics, you get the advantage of going through a number of solved problems and also get a lot of unsolved problems for practice. In subjects such as Physics or Chemistry, some topics are explained in greater detail than the class X NCERT textbooks. You would definitely have referred to a number of such books when you were in the IX standard, and it does make sense to follow a uniform strategy in classes IX and X.
Toppers normally advise their classmates to make the NCERT textbook the main study material, and supplement their efforts with reference books. The reason for this is that the examination is based on NCERT books, and if you know your NCERT textbook well, you don’t need any supplementary material for the Class X boards. In short, study your NCERT textbook really well, and use reference books only as supplements.
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Malaika Sharma 5 years, 1 month ago
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