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Ask QuestionPosted by Palak Chaudhari 5 years, 1 month ago
- 5 answers
Dhanusri V 5 years, 1 month ago
Yogita Ingle 5 years, 1 month ago
A tangent to a circle is a line which intersects the circle at only one point. The common point between the tangent and the circle are called the point of contact.
Line AB touches the circle exactly at one point, P. Such a line is called the tangent to the circle.
Krishna Varshney 5 years, 1 month ago
Posted by Endla Gurucharan 5 years, 1 month ago
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Posted by Soniya Rana 5 years, 1 month ago
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Open Beast 5 years, 1 month ago
Vandana 🇮🇳 5 years, 1 month ago
Posted by Cheshta Dhawan 5 years, 1 month ago
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?Suhani Arora? 5 years, 1 month ago
Posted by Tanay Shirke 5 years, 1 month ago
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Yogita Ingle 5 years, 1 month ago
Examples of abiotic factors include sunlight, water, air, humidity, pH, temperature, salinity, precipitation, altitude, type of soil, minerals, wind, dissolved oxygen, mineral nutrients present in the soil, air and water, etc.
Posted by Dishanth Mondal 5 years, 1 month ago
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Posted by Aditya Chauhan 5 years, 1 month ago
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Yogita Ingle 5 years, 1 month ago
Given tan2A=cot(A−180)
⇒cot(90−2A)=cot(A−180)[∵tanθ=cot(90−θ)]
Comparing angles we get
90−2A=A−18
⇒90+18=A+2A
⇒3A=108
⇒A=108/3
⇒A=36∘
Posted by Yaju Tatak 5 years, 1 month ago
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Posted by Vaishnavi Shukla 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
Putting Value of X and Y , in LHS we get,
→ (2/x+y)² + (x-y/2)²
→ (2/secA + sinA + secA - sinA)² + (secA + sinA - (secA - sinA)/2)²
→ (2/2secA)² + (secA + sinA - secA + sinA)/2)²
→ 1/sec²A + (2sinA/2)²
[using 1/secA = cosA ]
→ cos²A + sin²A
[ Now , we know that, cos²A + sin²A = 1 ]
Hence,
→ 1 = RHS ( Proved )
Posted by Piyush Tiwari 5 years, 1 month ago
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Anushika Singhal 5 years, 1 month ago
Posted by Shivansh Yadav 5 years, 1 month ago
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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago
Posted by M. Srimathi 5 years, 1 month ago
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Posted by Paru ? 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
first term of Ap=1
common difference=4
hence nth term (tn)=a+(n-1) d
only that number is ppossible in AP which gives integer value of n
now calculate n for each number,
(1) 7881=1+(n-1) 4
7880/4=1970=n
n gain integer value so , 7881 is In Ap
(2) 13531=1+(n-1) 4
13530/4=3382.5 =n
this is not possible
(3) 10091=1+(n-1) 4
10090/4=2522.5 =n
this is also not possible
(4) 4551=1+(n-1) d
4550/4=1137.5 =n
hence this is not possible
Posted by Sahiti Pavani 5 years, 1 month ago
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Posted by Sahiti Pavani 5 years, 1 month ago
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Posted by Manya Mahajan 5 years, 1 month ago
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Divyam Mishra 5 years, 1 month ago
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Piyush Tiwari 5 years, 1 month ago
Ayush Pandey 5 years, 1 month ago
Manya Mahajan 5 years, 1 month ago
Posted by Vandana 🇮🇳 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
Given - AB and AC are two equal words of a circle, therefore the centre of the circle lies on the bisector of 
BAC.
OA is the bisector of BAC.
Again, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the angle.
P divides BC in the ratio = 6 : 6 = 1 : 1.
P is mid-point of BC.
OP 
BC.
In 
ABP, by Pythagoras theorem,
In right OBP, we have
Equating (1) and (2), we get
Putting AP in (1), we get
or,alternate method:
Area of AOB by Heron's formula
arAOB) = 
Also arAOB = 
BM = h = 4.8 cm
BC = 2 BM = 9.6 cm.
Posted by Shubh Patel 5 years, 1 month ago
- 1 answers
Yogita Ingle 5 years, 1 month ago
(sin72° + cos18°)(sin72° − cos18°).
= (sin2 72° – cos2 18°)
= (sin2 72° – cos2 (90° – 72°)
= sin2 72° – sin2 72°
= 0
Posted by G Mahesh Gadla 5 years, 1 month ago
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Posted by Daxita Jain 5 years, 1 month ago
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Swarnima Verma 5 years, 1 month ago
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Pragati Verma 5 years, 1 month ago
Posted by Manish Agarwal 5 years, 1 month ago
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Gaurav Seth 5 years, 1 month ago
Given diameter of the circular pipe = 2 cm
So, the radius of the circular pipe = 2/2 = 1 cm
Height of the circular pipe = 0.7 m = 0.7 * 100 = 70 cm
Now, volume of the water flows in 1 second = πr2 h
= 3.142 * 12 * 70
= 3.142 * 70
Volume of the water flows in 1/2 hours = 3.142 * 70 * 30 * 60
Now, volume of the water flows = Volume of the cylinder
=> 3.142 * 70 * 30 * 60 = πr2 h
=> 3.142 * 70 * 30 * 60 = 3.142 * (40)2 h
=> 70 * 30 * 60 = 40 * 40 * h
=> h = (70 * 30 * 60)/(40 * 40)
=> h = (70 * 3 * 6)/(4 * 4)
=> h = 1260/16
=> h = 78.85 cm
So, the level of water rise in the tank in half an hour is 78.75 cm
Posted by Rohit Yadav 5 years, 1 month ago
- 2 answers
Vaishu ? 5 years, 1 month ago
Yogita Ingle 5 years, 1 month ago
x2 - 3 = 0
x2 - ( √ 3)2 =0
(x - √ 3) (x + √ 3)=0
x - √ 3=0 and x + √ 3=0
x = √3 and x = - √3
Posted by Bollapelli Sathwika 5 years, 1 month ago
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Posted by Femi Femi 5 years, 1 month ago
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Yogita Ingle 5 years, 1 month ago
Given numbers: 135 and 225
Here, 225>135.
So, we will divide greater number by smaller number.
Divide 225 by 135.
The quotient is 1 and remainder is 90.
225=135×1+90
Divide 135 by 90
The quotient is 1 and remainder is 45.
135=90×1+45
Divide 90 by 45.
The quotient is 2 and remainder is 0.
90=2×45+0
Thus, the HCF is 45.
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Navneet Kaur 5 years, 1 month ago
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