CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5
= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)
= 10/1 = constant/x² coefficient

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In an arranged series of 4n terms , which term is median?

Posted by Fahad Noor 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

an arranged series of 4n terms

Total term are even Hence

Median will be mean of 4n/2 & 4n/2 + 1 term

Median Would be Mean of 2n & 2n+ 1 Term

Median = (2n term + (2n+1) term) / 2=( 4n+1)/2

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Find the values of k for which following equation has real roots kx ( x-3) + 9 = 0

Posted by Manthan Singhal 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Manthan Singhal 5 years, 1 month ago

This is for real and equal I want to know for real roots so it can be distinct also

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Yogita Ingle 5 years, 1 month ago

Given, Quadratic Equation is kx(x - 3) + 9 = 0.

⇒ kx² - 3kx + 9 = 0

On comparing with ax² + bx + c = 0, we get a = k, b = -3k, c = 9.

Given that the equation has real equal and real roots.

∴ D = 0

b² - 4ac = 0

⇒ (-3k)² - 4(k)(9) = 0

⇒ 9k² - 36k = 0

⇒ 9k² = 36k

⇒ 9k = 36

⇒ k = 36/9

⇒ k = 4

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√2 is irratiinal

Posted by Prince Kunar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Charu Gupta 5 years, 1 month ago

Yes √2 is irrational..plz correct your question..

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Anjali Singh 5 years, 1 month ago

Hmm we know that Tell your question

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Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 1 month ago

yes √2 is irrational ?✌

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If m times the m terms of an AP is equal to n times the n terms of the same AP .then prove that (m+n)th term of AP is zero. Bhai jaldi and jar dena

Posted by Rajan Singh 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Rajan Singh 5 years, 1 month ago

Thanks

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Gaurav Seth 5 years, 1 month ago

Let the first term of AP = a
common difference = d
We have to show that (m+n)th term is zero or a + (m+n-1)d = 0

mth term = a + (m-1)d
nth term = a + (n-1) d

Given that m{a +(m-1)d} = n{a + (n -1)d}
⇒ am + m²d -md = an + n²d - nd
⇒ am - an + m²d - n²d -md + nd = 0
⇒ a(m-n) + (m²-n²)d - (m-n)d = 0
⇒ a(m-n) + {(m-n)(m+n)}d -(m-n)d = 0
⇒ a(m-n) + {(m-n)(m+n) - (m-n)} d = 0
⇒ a(m-n) + (m-n)(m+n -1) d = 0
⇒ (m-n){a + (m+n-1)d} = 0
⇒ a + (m+n -1)d = 0/(m-n)
⇒ a + (m+n -1)d = 0

Proved!

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Is 2+√3 a monomial?

Posted by Roushan Kumar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Manya Mahajan 5 years, 1 month ago

No nahi hai

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Shubham Pandey 5 years, 1 month ago

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Which is the best reference book can u suggest me for maths?

Posted by Rajan Singh 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Rudraksh Rai Udaiwal 5 years, 1 month ago

RD Sharma

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Anjali Singh 5 years, 1 month ago

Just study ncert properly and solve previous year papers That's enough ?

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If the sum of the zeroes of the polynomial p(x) = (a + 1)x2 + (2a + 3)x + (3a + 4) is -1, the find the product of the

Posted by Asmita Belapurkar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If tan theta equal to 1 by root 7 show that cosec square theta minus sec square theta by cosec square theta plus sec square theta equal to 3 by 4

Posted by Komal Shrivastava 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

Given:

To find:

The value of

Solution:

Therefore,

Opposite side = 1 and Adjacent side

By Pythogoras theorem

Therefore,

Now,

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If sin theta=cos theta,then the value of sin6theta+cos6theta=dash

Posted by Joshika Das 5 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Use Euclid's division algorithm to find the HCF of: 135and225

Posted by Rudrakshi Waghmode 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Shambhavi Kumari 5 years, 1 month ago

225=135×1+90 135=90×1+45 90=45×2+0 So HCF of 135 and 225 is 45

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ANSWER

LCM of 325

Posted by Divyanshu Rawat 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Swarnima Verma 5 years, 1 month ago

325=5*5*13

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Which of the following list of numbers form an AP? If they form an AP, write the next two terms : (1) 8 12 16 20 (2) 5, 3, 0, -3, ... (3) 8, 3, -2, -7, ... ( 4) 3, 3+ 2, 3+ /8, 3+ V18,..

Posted by Harsh Solanki 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Naveen Dho2 5 years, 1 month ago

Hiiii

1Thank You

ANSWER

Tignomantry

Posted by Adarsh Mehta 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Itachi Uchiha ? 5 years, 1 month ago

Tignomantry ni trigonometry....mei kya puchna h btao to

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Which of the following list of numbers form an AP? If they form an AP, write the next two terms : (1) 8121620 (2) 5, 3, 0, -3, ... (3) 8, 3, -2, -7, ... ( 4) 3, 3+ 2, 3+ /8, 3+ V18,..

Posted by Harsh Solanki 5 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Maths kyu hota hai

Posted by Chirag Mody 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Chirag Mody 4 years, 11 months ago

Silai me hai na aaap cos or sin theta nikal thike

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Itachi Uchiha ? 5 years, 1 month ago

Maths hamre liye imprtnt isliye h q ki vo agr tumhe contrater bnna h to usmei calculation or formula lagte h or silai karni h to usmei bhi calculation lagti h

3Thank You

Ajay Patel 5 years, 1 month ago

Kyuki maths ke bina calculations nahi ki ja sakti.

4Thank You

ANSWER

2÷1+2×1+2-2=98-94+4-5-1+001

Posted by ~Huzaifa ! 5 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Check whether -150 is a term of the A.P : 11,8,5,2

Posted by Abhay Abhay 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Paru ? 5 years, 1 month ago

The `n'th term of this AP is not a positive integer so -150 is not the term of this AP

1Thank You

Sonali Pathak 5 years, 1 month ago

1Thank You

ANSWER

Firstly tnx for everyone who gave me ans for which book should I buy in class 10 RS or rd . Now I am clear I must go with RS but can anyone tell me is it enough for standard maths

Posted by Manya Mahajan 5 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

Anjali Singh 5 years, 1 month ago

If you want the book which is just enough for standard mathematics then, no need of refreshers just study ncert properly and solve previous year question papers Hope this helps ?

2Thank You

Manya Mahajan 5 years, 1 month ago

Tnx everyone

1Thank You

Ajay Patel 5 years, 1 month ago

If you are going for standard level mathematics of course you can go with RS but , I my opinion you should also practice RD sharma because it has a lot of questions and examples to learn and practice.

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Chirag Mody 5 years, 1 month ago

No u must refer rd sharms

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in triangle pqr right angle at q pr+ qr = 25 cm and pq = 25 cm determine the values of sinp, cosp, and tanp

Posted by Shalini Negi 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

Pythagorus's theorem gives,

PR² = PQ² + QR²

PR²- QR²= PQ² = 5² = 25

(PR + QR)(PR - QR) = 25

(PR - QR) = 25/25 = 1

PR - QR = 1

and PR + QR = 25,

Solving the two equations,

PR = 13 and QR = 12.

Hence sin P = 12/13

cos P = 5/13

and tan P = 12/5

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Sec theta ( 1-sin theta) ( sec theta+tan theta)=1

Posted by Anu Choudhary 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 5 years, 1 month ago

= secA (1-sinA) (secA+tanA)

= secA (secA + tanA - sinA secA - sinA tanA)

= 1/cosA [1/cosA + sinA/cosA - sinA/cosA - sin²A/cosA]

= 1/cosA [1/cosA - sin²A/cosA]

= 1/cosA [(1-sin²A)/cosA]

= 1/cosA [cos²A/cosA]

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Aadarsh Raj Chaudhary 5 years, 1 month ago

I have solved this questio,but how can I send it to you?

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ABC is a right angled triangle AB=3cm , BC=5cm and AC=4cm, then the inradius of the circle is? Circle is inside the triangle.

Posted by Vandana 🇮🇳 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Vandana 🇮🇳 5 years, 1 month ago

Please send the solution.

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Navdeep Saini 5 years, 1 month ago

1.5

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ANSWER

Side AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of triangle PQR. Show that ∆ABC ~ ∆ PQR

Posted by Ashish Kumar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Chandu G 5 years, 1 month ago

AB/PQ = BC/QR = AD/PM To Prove: ΔABC ~ ΔPQR Proof: AB/PQ = BC/QR = AD/PM AB/PQ = BC/QR = AD/PM (D is the mid-point of BC. M is the mid point of QR) ΔABD ~ ΔPQM [SSS similarity criterion] Therefore, ∠ABD = ∠PQM [Corresponding angles of two similar triangles are equal] ∠ABC = ∠PQR In ΔABC and ΔPQR AB/PQ = BC/QR ———(i) ∠ABC = ∠PQR ——-(ii) From above equation (i) and (ii), we get ΔABC ~ ΔPQR [By SAS similarity criterion] Hence Proved

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32760 place value

Posted by Riti Singh 5 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The 4th term of an A. P. Is zero.. Prove that the 25th term of an A. P. Is three times it's 11th term

Posted by Navneet Kaur 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

Let first term of an A.P=a

common difference of A.P=d

According to the question,

a+3d=0.......(1)

25th term =a+24d

from (1)...a=−3d

=> −3d+24d

=> 21d.....(2)

11th term=a+10d

=−3d+10d

=7d.....(3)

By (3) and(2) 25th term=3× 11th term

3Thank You

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man observes from the top of a 50m high lighthouse from the sea level, the angles of depression of two ships are 45°and 60° . if one ship is exactly behind the other on the same side of the light house, then find the distance between the two ships.

Posted by S Sibiraj 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Prakhar Pare 5 years, 1 month ago

Sorry but not been able to attach photo In ∆ABC tan60°= AB\BC √3 = 50\ BC BC= 50/√3 BC=50\√3 *√3/√3 ( by rationalisation) BC=50√3/3 meter In∆ABD tan 45° = AB/DB 1= AB/DB y= 50/1 y=50 meter BC+x = y 50√3/3+x = 50 x=50-50√3/3 x=150-50√3/3 ( by taking LCM) x=50(3-√3)/3 ( by taking common) ANS: 50(3-√3)/3 meter

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Maths chapter 1 exercise 1.1 question 1

Posted by Ankit Kumar 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Anjali Singh 5 years, 1 month ago

(i) HCF of 135 and 225: Applying the Euclid’s lemma to 225 and 135, (where 225 > 135), we get 225 = (135 × 1) + 90 Since, 90 ≠ 0, therefore, applying the Euclid’s lemma to 135 and 90, we have: 135 = (90 × 1) + 45 But 45 ≠ 0 ∴ Applying Euclid’s Lemma to 90 and 45, we get 90 = (45 × 2) + 0 Here, r = 0, so our process stops. Since, the divisor at the last step is 45, ∴ HCF of 225 and 135 is 45. (ii) HCF of 196 and 38220: We start dividing the larger number 38220 by 196, we get 38220 = (196 × 195) + 0 ∵ r = 0 ∴ HCF of 38220 and 196 is 196. (iii) HCF of 867 and 255: Here, 867 > 255 ∴ Applying Euclid’s Lemma to 867 and 255, we get 867 = (255 × 3) + 102 Since, 102 ≠ 0, therefore, applying the Euclid’s lemma to 255 and 102, we have: 255 = (102 × 2) + 51 But 51 ≠ 0 ∴ Applying Euclid’s Lemma to 102 and 51, we get 102 = (51 × 2) + 0 Here, r = 0, so our process stops. Since, the divisor at the last step is 51, ∴ HCF of 867 and 255 is 51.

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Kartik Singh 5 years, 1 month ago

Pata nhi kya answer hai ?

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in triangle ABC right angled at B,angle A =angleC find value of sinA cosC+cosA sinC

Posted by S Sibiraj 5 years, 1 month ago

CBSE > Class 10 > Mathematics