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  • 4 answers
Hi bro

Sourav Keshri 5 years, 1 month ago

Hai bhai

Shailesh Gond 5 years, 1 month ago

I am the student of class 10 I am on Telegram

Shailesh Gond 5 years, 1 month ago

Hiii bro
  • 2 answers

Sourav Keshri 5 years, 1 month ago

X =(2+15y)/7 Y =19/17

Shubham Kumar 5 years, 1 month ago

Here your answer goes Step :-1 Take one equation from the two equations and represent it in the form of x and y by replacing 7x - 15y = 2----- > 1 x + 2y = 3------- > 2 Take equation 2 x = 3 - 2y ------>> 3 Step :- 2 Now , Substitute the value of x in equation 1 7 ( 3 - 2y ) - 15 = 2 21 - 14y - 15y = 2 21 - 29y = 2 -29y = 21 - 2 y = 29/19 ​ Step :- 3 Put the obtained value of y in equation 3 x = 3 - 2yx=3−2y x = 29/49 Hope you like this answer ​
  • 1 answers

Sourav Keshri 5 years, 1 month ago

Sin square 60°+2tan 45°- cos square 30° (√ 3/4)square + 2x1- (√ 3/4)square 3/4 + 2/1 -3/4 (+3/4 or -3/4 cut ho jayega) +2/1 = (2 Ans)
  • 3 answers
99999

Sourav Keshri 5 years, 1 month ago

316

Yogita Ingle 5 years, 1 month ago

We know that the largest 5 digit number is 99999.  

So here we can see that 99999 is not a perfect square as it leaves 143 as the remainder while finding it s square root.

So for finding 5 digit perfect square we will have to subtract 143 from 99999

=> 99999-143 = 99856

Hence 99856 is a perfect square whose square root is √99856 = 316.

  • 0 answers
  • 2 answers

Sourav Keshri 5 years, 1 month ago

(Ans) :- X square + 3x + 4

Sumit Choudhury 5 years, 1 month ago

x^2-x-12=0
  • 1 answers

Yogita Ingle 5 years, 1 month ago

we know that if there is no solution then lines must be parallel and if lines are parallel than

 ≠ c1/c2

so,a1/a2=3/6= 1/2

b1/b2=1 / k

now

so k=2

  • 4 answers

Spoorti Shrinivas 5 years, 1 month ago

the square of the hypotenuse side is equal to the sum of squares of the other two sides is know as phythagoras theorem Formula : Hypotenuse2 = Perpendicular2 + Base2  c2 = a2 + b2

Jobanjot Kaur 5 years, 1 month ago

The square of two the hypotenuse is the sum of the other two sides is known as pythagoras theorem FORMULA: H2 =B2+P2 H Square =B Square +P Square

Shuvendu Kumar 5 years, 1 month ago

The square of two the hypotenuse is the sum of other two sides is known as pythagoras therom

Harshali Vilhekar 5 years, 1 month ago

The square of the hypotenuse is equal to the sum of squares of other two sides is known as Pythagoras theorem
  • 1 answers

Gaurav Seth 5 years, 1 month ago

In figure, a circle touches all the four sides of a quadrilateral ABCD/ whose sides AB = 6 cm, BC = 7 cm and CD = 4 cm. Find AD. 

<hr />

Since, length of two tangents drawn from an external point of circle are equal.
So,    AP = AS
BP = BQ DR = DS
and    RC = CQ
Adding all, we get
(AP + BP) + (DR + RC) = AS + BQ + DS + CQ
⇒ (AP + BP) + (DR + RC)
= (AS + DS) + (BQ + CQ)
⇒    AB + DC = AD + BC
⇒    6 + 4 = AD + 7
⇒    10 = AD + 7
AD = 10 – 7 = 3 cm
Hence, AD = 3 cm.

  • 3 answers

Ekta Sirohi 5 years, 1 month ago

Good afternoon

Neha Kakkar ?? 5 years, 1 month ago

Good afternoon.

Nisha???????? Bharti 5 years, 1 month ago

Good afternoon
  • 5 answers

Chirag Sharma 5 years, 1 month ago

SecA= 4√7/7

Bhai Se Sikho Sikho 5 years, 1 month ago

sin A = 3/4 P = 3 H= 4 B=? H² = P² + B² B²= 16 - 9 B = √7 Sec A = H/B = 4/√7 4/√7 × √7/√7 = 4√7/7 So, Sec A = 4√7/7

Nisha???????? Bharti 5 years, 1 month ago

Sin A= 3/2=p/h b²=h²-p²= b²=4-9=-5 b=√-5 SecA=h/b=2/-√5

Maniya Jain 5 years, 1 month ago

Sec A = h / b = 4/√7

Taniya 5 years, 1 month ago

secA = 4/√7
  • 3 answers

Ekta Sirohi 5 years, 1 month ago

LCM(6,20)= 60

B.Aishwarya 203 Kalyannagar 5 years, 1 month ago

60

Yogita Ingle 5 years, 1 month ago

6 = 21 × 31

20 = 22 × 51

LCM(6,20) = 22 × 31 × 51
LCM(6,20) = 60

  • 1 answers

Yogita Ingle 5 years, 1 month ago

The common point of a tangent to a circle and the circle is called___

Point of contact

  • 2 answers

Sourav Keshri 5 years, 1 month ago

Value of α2+ β2.

Yogita Ingle 5 years, 1 month ago

Value of α2+ β2

  • 2 answers

Maniya Jain 5 years, 1 month ago

2x-y=2 2x-2=y ....(1) x+3y=15 ....(2) By substituting the value from 1 and 2 eq. x+3(2x-2)=15 x+6x-6=15 7x-6=15 7x = 21 x= 21÷7 x=3 From 1 eq we can find out the value of y ..... 2x-2=y 2(3)-2=y 6-2 =y x=3 and y=4

Yogita Ingle 5 years, 1 month ago

2x - y = 2

y = 2x - 2 ...(1)

x + 3y = 15 ...(2)

Substituting the value of y from (1) in (2), we get,

x + 6x - 6 = 15

7x = 21

x = 3

From (1),

y = 2  3 - 2 = 4

  • 1 answers

Gaurav Seth 5 years, 1 month ago

Given, the capacity of 1st tank =850 liters

And the capacity of 2nd tank= 680 liters

Now, the maximum capacity of a container which can measure the kerosene oil of both the

tankers when used an exact no.of times = HCF of 850 and 680

850 = 2 * 5 * 5  * 17

680 = 2 * 2 * 2 * 5 * 17

HCF(850, 680) = 2 * 5 * 17 = 170

Hence, the container which can measure petrol of either tank exactly must be of 170

liters.

  • 4 answers

Sourav Keshri 5 years, 1 month ago

Sin Square θ + cos square θ = 1.

Agriya Atri 5 years, 1 month ago

1

Maniya Jain 5 years, 1 month ago

Sin^2A + Cos ^2A =1

B.Aishwarya 203 Kalyannagar 5 years, 1 month ago

1
  • 1 answers

Gaurav Seth 5 years, 1 month ago

We have been given, x2 - 2x + 1 = 0

Now we also know that for an equation ax2 + bx + c = 0, the discriminant is given by the following equation:

D = b2 - 4ac

Now, according to the equation given to us, we have,a = 1, b = -2 and c = 1.

Therefore, the discriminant is given as,

D = (-2)2 - 4(1)(1)

= 4 - 4

= 0

Since, in order for a quadratic equation to have real roots, D ≥ 0.Here we find that the equation satisfies this condition, hence it has real and equal roots.

Now, the roots of an equation is given by the following equation,

x=-b± underroot D / 2a

Therefore, the roots of the equation are given as follows,

x=-(-2)±0 / 2(1)

=2 / 2

= 1

Therefore, the roots of the equation are real and equal and its value is 1.

  • 1 answers

Ankit1976 Mohit 5 years, 1 month ago

Hdjc ok
  • 1 answers

Simran Shira 5 years, 1 month ago

Solution: Given:- AB।। EF To prove:- AE/ED = BF/FC Construction:- draw AC Now in ∆ ADC , EP ll DC By basic proportionally theorem AE/ED = AP/PC ------- (1) Similarly in ∆ ABC AP/PC = BF/ FC --------- (2) From equ. (1) and (2) AE/ED = BF/FC Hence proved
  • 1 answers

Simranpreet Kaur 5 years, 1 month ago

(X+X+2+X+4+X+6+X+8)/5=11 (5X+20)/5=11 5X+20=11×5 5X=55-20 5X=35 X=35/5 X=7
  • 3 answers

Maniya Jain 5 years, 1 month ago

246÷2=123÷3=41÷41=1

Amit Bhadouriya 5 years, 1 month ago

246÷2=123÷3=41÷41=1

Princy Singh 5 years, 1 month ago

246÷2=123÷3=41÷41=1
  • 3 answers

B.Aishwarya 203 Kalyannagar 5 years, 1 month ago

45 degrees

Aashvi Singh 5 years, 1 month ago

Sin x =cos x(as given) =>We can write sin x as cos (90-x) =cosx =>now ,cos from both the sides will b canceled and you would be getting as (90-x) =x =>on solving, 90=x+x 90=2x 90/2=x 45=x Hence your answer is x=45

Madhura Dighikar 5 years, 1 month ago

X=45°
  • 1 answers

Gaurav Seth 5 years, 1 month ago

2. A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.

Solution:

Using given instructions, draw a figure. Let AC be the broken part of the tree. Angle C = 30°

BC = 8 m

To Find: Height of the tree, which is AB

From figure: Total height of the tree is the sum of AB and AC i.e. AB+AC

In right ΔABC,

Using Cosine and tangent angles,

cos 30° = BC/AC

We know that, cos 30° = √3/2

√3/2 = 8/AC

AC = 16/√3 …(1)

Also,

tan 30° = AB/BC

1/√3 = AB/8

AB = 8/√3 ….(2)

Therefore, total height of the tree = AB + AC = 16/√3 + 8/√3 = 24/√3 = 8√3 m.

  • 3 answers

Tanya Dhama 5 years, 1 month ago

After 4decimal places

Sushruth H 5 years, 1 month ago

14587/2×5⁴ =14587×2³/2×5⁴×2³ =116696/10⁴ =116696/10000 =11.6696 (It will terminate after 4 decimal places)

Sushruth H 5 years, 1 month ago

=14587/2²×5⁴ =14587×2²/2²×5⁴×2² =58348/10⁴ =58348/10000 =5.8348 (It will terminate after 4 decimal places)
  • 3 answers

Ekta Sirohi 5 years, 1 month ago

LCM =60

Parul Ailawadi 5 years, 1 month ago

LCM×HCF=Product of two numbers LCM×3=180 LCM=180÷3 LCM=60

Anuj Mathpal 5 years, 1 month ago

LCM =180/3 LCM=60
  • 1 answers

Gaurav Seth 5 years, 1 month ago

(iv) Meena went to a bank to withdraw Rs.2000. She asked the cashier to give her Rs.50 and Rs.100 notes only. Meena got 25 notes in all. Find how many notes of Rs.50 and Rs.100 she received.

Solution:

Let the number of Rs.50 notes be A and the number of Rs.100 notes be B

According to the given information,

A + B = 25 ……………………………………………………………………….. (i)

50A + 100B = 2000 ………………………………………………………………(ii)

When equation (i) is multiplied with (ii) we get,

50A + 50B = 1250 …………………………………………………………………..(iii)

Subtracting the equation (iii) from the equation (ii) we get,

50B = 750

B = 15

Substituting in the equation (i) we get,

A = 10

Hence, Manna has 10 notes of Rs.50 and 15 notes of Rs.100.

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