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  • 2 answers

Bhupendra Kumar Singh 2 years, 1 month ago

√(0-6)^2+(5-y)^2=√(-4-0)^2+(3-y)^2 =>36+25+y^2-10y=16+9+y^2-6y=>61+y^2-10y=25+y^2-6y=>36-4y=0........y=9..... required coordinates are (0,9)

Abhishek Kumar Ranjan 2 years, 1 month ago

=> cood.of y=(0,y) . => Cood.of y=(-4+6/2 , 3+5/2). =( 1,4) On comparing, (1=0, 4=y) Cood.of y=(0,4)
  • 2 answers

Mangu Singh J 2 years, 1 month ago

H

Bharatram Gurjar 2 years, 1 month ago

H
  • 1 answers

Aneek Bera 2 years, 1 month ago

Rewrite the question
  • 4 answers

Kanu Choudhary 2 years, 1 month ago

Upper limit+ lower limit divided by 2

Aman Poonia 2 years, 1 month ago

L+(f1+f2/2f1-f2-f3)*H

Rajat Tanna 2 years ago

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Ayush Dubey 2 years, 1 month ago

2+3
  • 1 answers

S Aashay 2 years, 1 month ago

we know!!
  • 0 answers
  • 1 answers

Sujal Jiratee 2 years, 1 month ago

E
  • 2 answers

Pratiksha Limbu 2 years, 1 month ago

222228

Apurva Sharma 2 years, 1 month ago

222228
  • 3 answers

Navya Bedi 2 years, 1 month ago

LCM(280,x)=14HCF(280,x)------1 LCM+HCF=600 LCM=600-HCF--------2 From 1 and 2 600-HCF=14HCF 600=15HCF HCF=40 LCM=14×40 LCM=560 Now, LCM×HCF=280×x 560×40=280x x=80 Hope this helps

Ahana Khanna 2 years, 1 month ago

600-280=320 So the other no. Is 320

Joban Preet 2 years, 1 month ago

?
  • 1 answers

Pratiksha Limbu 2 years, 1 month ago

4.5
  • 1 answers

Aneek Bera 2 years, 1 month ago

Squaring both side we get sin²+cos²+2sincos=4 Sincos=3/2 A.T.C (Sin⁴+cos⁴)²-2sin⁴cos⁴ =[(sin²+cos²)²-2sin²cos²]²-3⁴ =(1-9)²-81 =64-81 =-17
  • 2 answers

Rupshree Singh 2 years, 1 month ago

By squaring both side SinA.CosA=1

Ishika Chouhan 2 years, 1 month ago

Square both side (SinA cosA)²= (√3)² Sin²A + cos²A + 2sinA.cosA = 3 We know that - Sin²A + Cos²A =1 So, 1+ 2sinA.cosA =3 2sinA.cosA = 3-1 2sinA.cosA =2 SinA.CosA = 2/2 SinA.CosA=1
  • 5 answers

Rupshree Singh 2 years, 1 month ago

ap4= 7+ 3 d ap4=-1+3d In apz ap4-ap4= ay-a+3d ay-8+3d -1+3d-(-8-3d) -1+34+8-30 = 7

Avani Cho 2 years, 1 month ago

7

Ashish Gupta 2 years, 1 month ago

7

Yash Singh 2 years, 1 month ago

7 is correct answer

Yash Singh 2 years, 1 month ago

2 ans
  • 1 answers

Ak Vijeesh Vijeesh 2 years, 1 month ago

X-y-y =9
  • 1 answers

Student Pro 2 years, 1 month ago

3x/2-5y/3=-2----1 x/3+y/2=13/6---2 take the Icm of 6 in 1 and2 therefore, 9x-10y=-12----3 from this x=-12+10y/9---5 and 2x+3y=13-----4 putting 5 in 4 therefore, y=3 and from 5 x=2 {byputting thevalue of y in it}
  • 1 answers

Pratham Maurya 2 years, 1 month ago

Given distance=360 km. Let the speed of the train be x km/hr. Speed when increased by 5 km/hr =(x+5) km/hr 360x−360(x+5)=1 [360x+1800−360x]x(x+5)=1 x2+5x−1800=0 x2+45x−40x−1800=0 x(x+45)−40(x+45)=0 (x−40)(x+45)=0 x=40,−45 The speed of the train is 40 km/hr.
  • 1 answers

Student Pro 2 years, 1 month ago

3sin30=1/2*3=3/2 4cos^2 45=4(1/2)^2=4*1/2=4/2 cot^2 30=√3^2=3 cos^2 30 = √3/2^2=3/4 Sin2 60^= (√3/2)2=3/4 3(1/2)+4/2-3/3/4+3/4 [ by cutting 3 by 3cand 4by 4] 3/2+4/2-3[ now take the lcm of -3 multiply it by 2] = 3+4-6/2=7-6/2= 1/2 ans is 1/2

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