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  • 3 answers

Kanishk K 2 years ago

X²+3x+2

Alfiya💫💫💫 . 2 years, 1 month ago

Let -3= be (ã+ß) & 2=(ã+ß) by Quadratic formula....→ x²-(ã+ß)x+àß=0 x²-(-3)x+2=0 [x²+3x+2=0]..... 👍👍👍

Gurjot Kaur 2 years, 1 month ago

:》Sum of zeros = -3 ; Product of zeros = 2 :》Quadratic polynomial = k[x2 - ( Sum of zeros)x + ( Product of zeros)] :》k [ x2 - (-3)x + 2] :》k [ x2 + 3x + 2] ,where k =1 :》 Quadratic Polynomial = x2 + 3x +2
  • 1 answers

Harsh Verma 2 years, 1 month ago

-5
  • 2 answers

Neeraj Varshney 2 years ago

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Mahir Patel 2 years, 1 month ago

• hence, angle TPO + angle PTQ + angle TQO +angle QOP =180 degree • angle poq + angle
  • 1 answers

Anany Utkarsh Roll No 4 2 years, 1 month ago

If we take the discriminant b²-4ac it will come in negative therefore it has no real roots
  • 4 answers

Arshdeep Singh 2 years ago

a²+b²+2ab

Himanshu Kumar Modi 2 years, 1 month ago

a2+2ab+b2

Arshdeep Kaur 2 years, 1 month ago

a²+b²+2ab

Vansh Giri 2 years, 1 month ago

A square+b square+2ab
  • 0 answers
  • 1 answers

Anas Shaikh 2 years ago

Ok jaan
  • 1 answers

Kishan Ojha 2 years, 1 month ago

0000
  • 3 answers

Vijayant Choudhary 2 years, 1 month ago

Answer key

Sanjeev Kumar Singh 2 years, 1 month ago

You will in this app

Ayush Kushwah 2 years, 1 month ago

Please search that : Previous Year Maths Questions Paper Class X 2023-2024
  • 1 answers

Ayush Kushwah 2 years, 1 month ago

On the Right - hand side/between , a option is given that Download as PDF or JPG , so you can download as your choice
  • 1 answers

Shreya Panwar 2 years, 1 month ago

The answer is Let 3+2√2 be a rational number and it can be written in the form of : p/q = 3+2√2 p/q -3 = 2√2 p-3q / q =2√2 Rational = irrational Therefore our assumption was wrong. Hence 3+2√2, is an irrational number.
  • 1 answers

Kaushik Verma 2 years, 1 month ago

x²+(x+1)²=421 x²+x²+1+2x=421 2x²+2x=420 2x²+2x-420=0 2(x²+x-210)=0 x²+x-210=0 D=b²-4ac =1²-4×1×(-210) =1+840 =841 underoot841=29 x=14 x=-15(it is neglected)
  • 1 answers

Spoorti Izare 2 years, 1 month ago

X=13 and 12 and y= 13 and 12
  • 5 answers

Deepanshu Garg 2 years, 1 month ago

It's ok bro

Abhinav Raj Singh 2 years, 1 month ago

its ok brother

Naman Sisodiya 2 years, 1 month ago

Thank

Abhinav Raj Singh 2 years, 1 month ago

S7 = 7/2{2a+(n-1)d} => 49= 7/2{2a+(n-1)d} => 14= 2a + (7-1)d =>14 = 2a +6d => a + 3d = 7 ---------------(dividing by 2) => a = 7-3d -----------------(i) for S17:- S17 = 17/2 {2a+(n-1)d} => 289= 17/2 {2a+(17-1)d} => 34 = 2a + 16d => a = 17- 8d ---------------(ii) by eq(i) and eq(ii):- 17 - 8d = 7-3d =>10=5d =>d=2 again by eq(i):- a =1 by Sn:- Sn = n/2 {2a+(n-1)d} =>Sn = n/2{2+(n-1)2} => Sn = n + n^2 - n => Sn = n^2

Abhinav Raj Singh 2 years, 1 month ago

n^2
  • 2 answers

Kaushik Verma 2 years, 1 month ago

D=b²-4ac=0 =k²-4×2×k=0 = k²-8k=0 =k(k-8)=0 = k-8=0 =k=8

Aniket Singh 2 years, 1 month ago

Given : b²-4ac=0 So, (-k)²-4×2×k=0 k²-8k=0 k(k-8)=0 k=8
  • 1 answers

Abhinav Raj Singh 2 years, 1 month ago

d is the common difference and a is the first term this series forms A.P. as it has common difference and a2-a1 = a3-a2=3 d =a2-a1 = 3 a =2 and given Sn = 155 also Sn =n/2 {2a+(n-1)d} => 155 = n/2{ 4 + (n-1)3} => 310= 4n +3n^2 - 3n => 3n^2 +n -310 =0 => 3n^2 -30n +31n -310 =0 =>3n(n-10)+31(n-10)=0 =>(3n+31)(n-10)=0 since number of terms (n) cant be negative so n=10
  • 2 answers

Kaushik Verma 2 years, 1 month ago

2x²-16=0 2(x²-16)=0 x²-16=0 x²=16 x=+4 x=-4

Tanuj Bera 2 years, 1 month ago

2x²-16 (√2x)²-(4)² (√2x-4)² that's the answer
  • 0 answers

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