CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Sum of the zeroes= -1. Polynomial is 6x3+x2-4x-1 Product of the zeroes = 1/2 Sum of product of the zeroes = 1/3 Sum of the zeroes = -b/a Alpha+bita+gamma = -b/a -1+1/2+1/3 = -1/6 -6+3+2/6 = -1/6 -6+5/6 =-1/6 -1/6 = -1/6 Product of the zeroes = d/a Alpha×bita×gamma = d/a -1×1/2×1/3 = -1/6 -1/6 = -1/6 Sum of product of the zeroes = c/a Alpha×bita+bita×gamma+gamma×alpha = c/a (-1)×1/2 + 1/2×1/3 + 1/3×(-1) = -4/6 -1/2+1/6+(-1/3) = -4/6 -1/2+1/6-1/3 = -4/6 -3+1-2/6 = -4/6 -5+1/6 = -4/6 -4/6 = -4/6

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Arshdeep Kaur 4 years, 8 months ago

Verfdgh

4Thank You

ANSWER

find distance of (2,3) from origin

Posted by Palak Gupta 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

Distance of (2,3)from the origin =root under 2square+3square Root under 13 Ans.

1Thank You

Saurabh Kumar 4 years, 8 months ago

Under root 13

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ANSWER

Compare the rainfall of Punjab and andhra pradesh by bar graph and find their probability of minimum and maximum rainfall and compare it

Posted by Noor Pandher 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

एक 5 सेंटीमीटर त्रिज्या वाले वृत्त पर बिंदु P पर एक स्पर्श रेखा PQखींची गई है यदिOQ=13cmहै तोPQकी लम्बाई ज्ञात करो 15 13 12 16

Posted by Shizu 5121 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Shizu 5121 4 years, 8 months ago

1Thank You

ANSWER

X-1=8(y-1),x=y^2 solve for value of x and y

Posted by Arpita .9 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Kiran Kumari 4 years, 8 months ago

Then x=y^2 X=(1)^2 X=1

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Kiran Kumari 4 years, 8 months ago

X_1=8y_8 (1) ,x=y^2 Put the value of x^2 in eq (1) Y^2_1=8y_8 Y^2_8y+7=0 Y^2_7y_y+7=0 Y (y_7) _1 (y_7)=0 (Y_7) (y_1)=0 Y=7 ,y=1

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Aachal Satwan 4 years, 8 months ago

x - 1 = 8(y - 1) y^2 - 1 = 8y - 8 (∵x=y^2) y^2 - 8y -1 +8 = 0 y^2 - 8y +7 = 0 y^2 - y -7y + 7 = 0 y (y-1) -7(y-1) = 0 (y -7) (y-1) = 0 ∴ either (y-7) =0 OR (y-1) = 0 ∴ y = 7 OR y= 1 i) If y= 7 , then x = y^2 = (7)^2 = 49 ii) If y = 1, then x = y^2 = (1)^2 = 1

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ANSWER

X^2+46x+62 find factors

Posted by Prerana Dhumal 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

9AD^2=7AB^2

Posted by But Bahadur Singh Vir Bahadur Singh 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

King Adithya H M... 4 years, 8 months ago

In an equilateral ABC, D is a point on side BC such that BD equals 1 third BC. Prove that 9AD2 = 7AB2. Given : An equilateral triangle ABC such that To Prove : 9AD2 = 7AB Given : An equilateral triangle ABC such that BD equals 1 third BC.To Prove : 9AD2 = 7AB2 Const: Draw AE ⊥ BC. Proof: In right triangles ABE and ACE, we have AE = AE [common] ∠AEB = ∠AEC [90°] and AB = AC [∆ABC is an equilateral] Therefore, by using RHS congruent condition space space increment ABE approximately equal to increment ACE rightwards double arrow BE = CE [by CPCT] rightwards double arrow BE equals CE equals 1 half BC In right triangle ADE, we have space AD squared space equals space AE squared plus DE squared rightwards double arrow AD squared space equals space AE squared plus left parenthesis BE minus BD right parenthesis squared rightwards double arrow space space space AD squared equals AE squared plus BE squared plus BD squared minus 2 BD. BE rightwards double arrow AD squared space equals space left parenthesis AE squared plus BE squared right parenthesis plus BD squared minus 2 BD. BE open square brackets because space space BD equals 1 third BC space and space BE space equals space CE space equals space 1 half BC close square brackets rightwards double arrow space space space AD squared space equals space AB squared plus open parentheses 1 third BC close parentheses squared minus 2 cross times 1 third BC cross times 1 half BC rightwards double arrow space space space AD squared space equals space AB squared plus 1 over 9 BC squared minus BC squared over 3 rightwards double arrow AD squared equals fraction numerator 9 AB squared plus BC squared minus 3 BC squared over denominator 9 end fraction rightwards double arrow 9 AD squared space equals space 9 AB squared minus 2 BC squared But AB = BC = CA rightwards double arrow <pre>uncaught exception: mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied

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0Thank You

Gaurav Seth 4 years, 8 months ago

In an equilateral ABC, D is a point on side BC such that Prove that 9AD² = 7AB².

<hr />

Given : An equilateral triangle ABC such that To Prove : 9AD² = 7AB²

Const: Draw AE ⊥ BC.
Proof: In right triangles ABE and ACE, we have
AE = AE    [common]
∠AEB = ∠AEC    [90°]
and    AB = AC
[∆ABC is an equilateral]
Therefore, by using RHS congruent condition

BE = CE [by CPCT]

In right triangle ADE, we have








But AB = BC = CA

2Thank You

ANSWER

cot θ(sec θ−1) 2 (1+sin θ) sec θ(sin θ−1) 2 (1+sec θ)

Posted by Manshi Raj 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

One specific you is in the shape of a come mounted on a cylinder total height of conicalpartis

Posted by Surya Karthikeyan 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Case study base question as per New pattern introduction by CBSE

Posted by A A 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Cos2A-3CosA+2/Sin2A=1

Posted by Dattatraya Jagtap 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

Sorry cosA=1 Proved

1Thank You

Kiran Kumari 4 years, 8 months ago

Cos2A_3CosA+2=2sin2A Cos2A_3cosA+2=2 (1_cos2A) Cos2A_3cos +2=2_2cos2A 3cos2A_3cosA=0 3cosA (cosA_1)=0 CosA_1=0 CosA=0 L.H.S=R.H.S

1Thank You

ANSWER

Chapter 9 exercise 9.1 m say kon sa question cut h . Please tell me

Posted by Krazy Girl 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Malaika Sharma 4 years, 8 months ago

Nothing is deleted in Chapter-9(Maths)

0Thank You

Ff_Girl Tannu 4 years, 8 months ago

Kuch bhi cut nhi hua

0Thank You

Sunny Ghorriwal 4 years, 8 months ago

Koi nhi Hua Hai cut

1Thank You

ANSWER

If the angle between two tangents drawn from an external point P to a radius a and centre O, is 60° then find the length of OP. [CBSE 2017] Ans: a√3

Posted by Laxmi Narayan 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

Ap=BP ....(length of tangents from external point to circle are equal)

∠A=∠B=90o .... (Tangent is ⊥ to radius)

OP=OP .... (common side)

∴△AOP≅△BOP ....(RHS test of congruence)

∠APO=∠BPO=30o→c.a.c.t

∠AOP=∠BOP=60o→c.a.c.t

△AOP is 30o−60o−90o triangle.

∴△AOP,

cos60=OPOA

OP= a/ 1/2=2a

1Thank You

ANSWER

in US in a sports day celebration Ravi and Amit are standing at position y and z whose coordinates R2 - 2 and 4 respectively the teacher asked to fix the country flag at the midpoint of the line joining points y and z first find the coordinates of the distance the midpoint find the distance between Ravi and Amit

Posted by Kaur Reet 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Happy new year to all.https://www.tenor.co/buUF0.gif

Posted by Aryan Tiwari 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Baisa Hkm ?? 4 years, 8 months ago

Sm2u ???

0Thank You

Kaur Reet 4 years, 8 months ago

Same to you ?

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Meena Gupta 4 years, 8 months ago

Same to you

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Sunita Devi 4 years, 8 months ago

0Thank You

ANSWER

Please tell which exercise have been deducted from maths

Posted by Abhimanyu Singh 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Ncert exercise 1.1 exam me aayega ki na

Posted by Aryan Tiwari 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Sunny Ghorriwal 4 years, 8 months ago

1Thank You

Krazy Girl 4 years, 8 months ago

0Thank You

Aryan Tiwari 4 years, 8 months ago

Thanks

0Thank You

Lokesh Appu 4 years, 8 months ago

0Thank You

ANSWER

Congratulations ,my frnds , our education minister announced that our board exam will start on 4th may and end on 10th June ,and results will announce on 15 July and ,,,,,our practicals will start on 1 march .....??✌️??????? Now guys we have all 4 months to study

Posted by Sumaila Ali Choudhary??? 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Abhimanyu Singh 4 years, 8 months ago

Thank you for this info...

2Thank You

Sunidhi Chahar 4 years, 8 months ago

Yes we know that

2Thank You

Aryan Tiwari 4 years, 8 months ago

2Thank You

Lokesh Appu 4 years, 8 months ago

Yeah

2Thank You

ANSWER

Sin squared theta divided by cos squared theta

Posted by Syed Hyder 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Bhoomika Verma 4 years, 8 months ago

Sin2@/cos2@=tan2@

0Thank You

Syed Hyder 4 years, 8 months ago

sec squared theta minus cos square theta whole divided by sin square theta minus cos square theta into cos square theta minus sin square theta divided by sin square theta minus cos square theta

0Thank You

ANSWER

Find the solutionof the equation x2_6x+5=0

Posted by Raga S.L 4 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Kunwar Dev Singh 4 years, 8 months ago

X^2 - 6x +5 =0 X^2 - 5x - x +5=0 X(x -5 ) -1(x-5)=0 (X-1)(x-5)=0 X=1 or x=5

0Thank You

Kiran Kumari 4 years, 8 months ago

X2_5x_x+5 X (x_5)_1 (x_5) (X_5) (x_1) X=5 or x=1

0Thank You

Pardeep Jindal 4 years, 8 months ago

X = 5;1

0Thank You

Sumit Rathi 4 years, 8 months ago

X²+6x+5 X²+5x+x+5 X(x+5) +1(x+5) (x+1) (x+5) take x+1=0 and x+5=0 Hence x=-1, -5

0Thank You

Yogita Ingle 4 years, 8 months ago

given, x²−6x+5=0

x²−5x−x+5=0

x(x−5)−1(x−5)=0

(x−5)(x−1)=0

x=5,1

2Thank You

ANSWER

If alpha and beta be the zeores and polynomial 2x²-5x+8 evaluate alpha/beta+ beta/alpha

Posted by Sumit Rathi 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Kunwar Dev Singh 4 years, 8 months ago

α +β= (-b/a),α+β=5/2, αβ=c/a,αβ=8/2=4, (α+β)^2 = α^2+β^2+2αβ,(5/2)^2=α^2+β^2+8 25/4-8=α^2+β^2,α^2+β^2=(-7/4) Then, α/β+β/α = α^2+β^2/αβ=(-7/4)/4=(-7/16)

0Thank You

ANSWER

Proof That 2 root 5 irrational

Posted by Alok Gupta 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Bhoomika Verma 4 years, 8 months ago

Let as assume that to the contrary ,that 2√5 is rational. 2√5 =a/b (a and b is coprime and integers and q is not equal to 0 ) √5=a/2b a and b are integers , a/2b is rational , and so √5 is rational . But this contradicts the fact that √5 is irrational . This contradiction has arisen becz of our assumption was wrong that 2√5 is rational. Hence 2√5 is irrational number.

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Basant Kumar Mahto 4 years, 8 months ago

Let 2√5 be rational number.it can be written in the form of p/q. 2√5=p/q √5=p/q. 1/2 We know that √5 is irrational number. It has arisen our assumtion is worng that 2√5 is rational number. Hence 2√5 is irrational number.

0Thank You

ANSWER

P(x)3x2+x-2

Posted by Tosif Ansari 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Preeti 4 years, 8 months ago

3x^2 +x -2 3x^2 +3x -2x -2 3x(x-1) - 2(x+1) (3x-2) (x-1) So, Either x= 2/3 Or x= 1

1Thank You

Tanu Choudhary # 4 years, 8 months ago

Ask the question properly we are unable to understand

1Thank You

ANSWER

A fraction becomes 1/3 when 1 is subtracted from the numerator and it becomes 1/4 when 8 is added to its denominator . Find the fraction.

Posted by Baisa Hkm ?? 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Tanu Choudhary # 4 years, 8 months ago

x-1/y=1/3 X/y+8=1/4 3x-3=y 4x=y+8(substitute value of y) 4x-3x=-3+8 X=5

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Yogita Ingle 4 years, 8 months ago

Let us assume thenumerator to be =x

Let us assume thedenominator to be =y

Hence the fractionbecomes=x/y

Accordingtothe given condition

(x−1)/y=1/3

⇒y=3x−3 ———-(i)

Accordingtothesecond givencondition,

x/(y+8)=1/4

⇒y+8=4x

⇒y=4x−8 ————(ii)

Combining(i)and(ii) we get,

3x−3=4x−8

⇒3x−4x=−8+3

−x=−5

⇒x=5

from(i)

y=15−3=12

So,the fraction is =5/12

2Thank You

ANSWER

Advanced happy new year my dear friend ??

Posted by Ranvijay Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Malaika Sharma 4 years, 8 months ago

Crafty Queen mein aapki maid nahi hun so don't be so rude And Maine aapko yeh hi kaha tha ki aap apni stories mat share karo because its not allowed.You can check the guidelines.Also tell me how can I help you??? *For eg*-I live in Punjab and you live in Uttar Pradesh Should I come to your place,request your teacher not to force you or call your teacher??You are wasting your as well as our time.Only your parents and Principal can help you. We are helpless.If they don't support you its not our fault.We feel bad for u but we are helpless.Thanks Jai Shri Krishna

2Thank You

Jagrati Sharma 4 years, 8 months ago

Same to u

1Thank You

Krazy Girl 4 years, 8 months ago

Same to you☺

2Thank You

Saurabh ???? 4 years, 8 months ago

You to ?

2Thank You

Sumaila Ali Choudhary??? 4 years, 8 months ago

Same to u

4Thank You

ANSWER

4 men and 6 boys can finish a piece of work in 20 days, while 3 men and 4 boys can finish it in 28 days. Find the time taken by 1 man alone and 1 boy alone.

Posted by Charvi Sangwan 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

The time taken by one man alone is 140 days and the time taken by one boy alone is 280 days .

Step-by-step explanation:

Let time taken by one man alone be = x days

Let time taken by one boy alone be = y days

According to question

.......(1)

and .......(2)

Solve equation (1) and (2) by eliminating,

Multiply equation (1) by 2 and equation (2) by 3 then subtract

...... (3)

.......(4)

Subtract equation (4) from equation (3)

so, the time taken by one man alone is 140 days

Put value of x in equation (1)

Subtract both the sides by

Multiply both the sides by

Multiply both the sides by 280,

so, the time taken by one boy alone is 280 days

Therefore, the time taken by one man alone is 140 days and the time taken by one boy alone is 280 days .

0Thank You

ANSWER

The sum of 2 number is 8 and the sum of their reciprocal is 8/15. Find the numbers.

Posted by Charvi Sangwan 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

Let one number be X. The other number be Y.

GIVEN,

x+y=8

x=8-y ---------------(1)

1/x+1/y=8/15

BY SIMPLIFING 1/x+1/y=8/15 WE GET,

(x+y)/xy=8/15

FROM (1) WE GET,

8/8y-y²=8/15

y²-8y+15=0

(y - 3)(y - 5) = 0

y = 3 or 5

WE KNOW THAT x+y=8

When y=5, x=3

When y = 3, x = 5

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ANSWER

A sum of Rs.1000 is invested at 8% simple interest per year. Calculate the interest at end of each year. Do these interests form AP? If so find the interest at the end of 30 years making use of this fact.

Posted by Eucharist Lover 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 4 years, 8 months ago

Simple Interest = P × R × T ÷ 100
So S.I in first yr. ⇒ P x R x T / 100
⇒ 1000 x 1 x 8 ÷ 100
⇒ 80
In second Yr. ⇒ 1000 x 2 x 8 ÷ 100
⇒ 160
Similarly in third Yr. ⇒ 240
So , we get the A.P. like this i.e. 80, 160, 240
Therefor a= 80 , d= 80.
we have to find out the interest at the end of 30 yr.
⇒ a = a + ( n-1 ) d
⇒ 80 + ( 30 - 1 ) 80
⇒ 80 + 29 × 80
⇒ 2400
There fore , the Interest at the end of 30 yrs is 2400

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ANSWER

If your father gave you 10Rs in which 5rs for you and 5rs for your brother but your brother have spent all the money then how much you will you rupees you will take from your father option is 5 or 10 plz give answer in comment

Posted by Ayush Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Secret ??? 4 years, 8 months ago

I think this is your own problem and asking us about what to do next

0Thank You

Secret ??? 4 years, 8 months ago

Some may say ₹10 as brother has got 10 Rs then we should get equal money but for some people like me it's better not to take money from father bur from brother whenever he have money

0Thank You

Sumesh ☺️☺️☺️ 4 years, 8 months ago

May be 5️⃣

0Thank You

ANSWER