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4X + 5Y =14 , 2X+5Y=12

Posted by Raj Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Reema Janu 4 years, 8 months ago

By elimination method - 4x + 5y = 14-------1 2x + 5y = 12-------2 By subtracting eq 1 and 2 2x = 2 X = 2/2 x = 1 Putting x=1 in eq 2 2(1) + 5y = 12 Y = 12 - 2 / 5 Y = 10/ 2 Y = 5

ANSWER

2¾×⅘

Posted by Sujal Patil 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Tanu Choudhary # 4 years, 8 months ago

2⅗

.Acircularparkhas8radialroadsequallyinclinedtoeachother.Agirldecidesto takehergrandfatheroutonawheelchairtothecentreofthepark.Shestartsfrom herhouseatH&followstheroadalongHAwhichisatangenttothecircularparkat A&takesaturnatAtoreachthecentreO.Onherreturntripsheoptstogoalong theradialroadOB&continuesalongthepathBCinthesamedirectiontobeableto reachpointContheroadAH.ShethenfollowsthepathCHtoreachhome.Radius ofcircularparkis15m. I. Whatisthelengthofwirerequiredtofencethepark? a)84.7m b)94.2m c)79.5m d)47.1m II. Whatistheareaofpark? a)607.50m 2 b)916.71m 2 c)304.15m 2 d)706.50m

ANSWER

Posted by Charu Saini 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Harshraj Prajapat 4 years, 8 months ago

Reema Janu 4 years, 8 months ago

Please again write the question properly...as there is no space bar nothing else...it is very difficult for all to read this and to give you the answer

ANSWER

The value of k for which the system of equations x+y-4=0 and 2x+ky=3,has no solution, is. a) -2. b) not equal 2. c) 3. d) 2.

Posted by Arjun Suryavanshi 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Bhoomika Verma 4 years, 8 months ago

Option d

Reema Janu 4 years, 8 months ago

I think it would be d) 2

Arjun Suryavanshi 4 years, 8 months ago

ANSWER

A card is drawn at random from a pack of 52 cards. Find the probability that the cards drawn is: (a) neither a heart nor a king (b) neither an ace nor a king (c) neither a red card nor a queen (d) neither a king nor a queen

Posted by Pihu ✨ 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Anu Sharma 4 years, 8 months ago

a) Total no. of cards :- 52 No. of cards that are neither a heart nor a king :- 36 Probability :- 36/52 = 9/13 b) no. of cards that are neither a ace nor a king :- 44 Probability :- 44/52 = 11/13 c) no. of cards that are neither red card nor a king :-24 Probability :-24/52 = 6/13 d) No. of cards that are neither a king nor a queen :- 44/52 = 11/13

Gaurav Seth 4 years, 8 months ago

Total no. of outcomes = 52 {52 cards}

(i) E⟶ neither a heart nor a king
Heart cards = 13
Kings = 3 [Heart king is already included in counting heart cards]

No of favourable outcomes = 52 - 13 - 3 = 36

We know that, P(E) = (No. of favorable outcomes)/(Total no.of possible outcomes) = 36 / 52 = 18 / 26 = 9 / 13

ANSWER

a tree due to the storm and the broken part bends so that the tree top touches the ground making an angle 30 with it.the distance between the foot of the tree to the point where the top touches the ground is 8m. find the height of the tree from where it is broken

Posted by Palika Chandra Swaroop 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Anu Sharma 4 years, 8 months ago

Answer :- 8√3m

Gaurav Seth 4 years, 8 months ago

Let BD be the tree broken at point C such that the broken part CD takes the position CA and strikes the ground at A. It is given that AB = 8 m and ∠BAC = 30°.
Let BC = x metres and CD = CA = y metres
In right triangle ABC, we have

Now, height of the tree

Hence, the height of the tree

ANSWER

Sec theta/ cot theta+tan theta =

Posted by Tae Shah 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Secret ??? 4 years, 8 months ago

Sec@/cot@+tan@ = 1/cos@(cos@/sin@+sin@/cos@) = 1/cos@/(sin²@+cos²@)/sin@cos@ (:- sin²@+cos²@=1) 1/cos@/1/sin@cos@ = sin@cos@/cos@ = sin@ ans

ANSWER

ABC is a traingle right angled at B and BD perpendicular to AC. If AD=4 cm and CD=5 cm. Then find BD and AB.

Posted by Aditi Ringusia 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditi Ringusia 4 years, 8 months ago

Sir please can u explain how it is 90degree - angle c

Gaurav Seth 4 years, 8 months ago

Given,

∆ABC in which ∠B = 90° and BD ⊥ AC

Also, AD = 4 cm and CD = 5 cm

In ∆ADB and ∆CDB,

∠ADB = ∠CDB [each equal 90°]

∠BAD = ∠DBC [each equal to 90°-∠C]

∴ ∆DBA ∼ ∆DCB [by AAA similarity criteria]

Then,

In right angled ∆BDC,

BC² = BD² + CD² [by Pythagoras theorem]

= BC² = (2√5)² + (5)²

= BC² = 20 + 25 = 45

= BC = √45 = 3√5

Again,

Hence, BD = 2√5cm and AB = 6cm.

ANSWER

Find the roots of the quadratic equations 2x^2+x+4.

Posted by Shreya Kumari 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Reema Janu 4 years, 8 months ago

2x^2 + x + 4 D = b^2 - 4ac D = (1)^2 - 4(2)(4) D = 1 - 32 D = -31 < 0 So it has not real roots

ANSWER

Case study questions for 10th

Posted by Vp V 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 4 years, 8 months ago

CBSE has introduced the Case Study Questions in class 10 and class 12 this year. The annual examination of 2021 will have case-based questions in almost all major subjects. This article will help you to find sample questions based on case studies and <a href="https://play.google.com/store/apps/details?id=in.techchefs.MyCBSEGuide">model question papers</a> for CBSE Board Exams 2021.

Case Study Question in Mathematics

Here is an example of a case study based question for class 10 Mathematics. To get more questions and model question papers for the 2021 examination, download <a href="https://play.google.com/store/apps/details?id=in.techchefs.MyCBSEGuide">myCBSEguide Mobile App</a>.

Vp V 4 years, 8 months ago

1st row 3 jars, 2nd row 6 jars.....

ANSWER

Square ADBC are lies on the same base in the picture. AD intersects BC at O. AL T BC and DM T BC. Prove that

Posted by Roopa Roopa 4 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Q.3. In Fig. given below two tangents TP and TQ are drawn to a circle with centre O from an external OPQ. L

Posted by Mohit Bhashani 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Vedant Rai 4 years, 8 months ago

No figure

ANSWER

2 or 2 4 kyu ho tai ha

Posted by Vansh Gupta 4 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Secret ??? 4 years, 8 months ago

How could it be fluorine?

Manshi H... 4 years, 8 months ago

The is wrong, it would be like 2 and 2. 2 and 2=22 and (1+1)+(1+1)=4

Sachin Rajmukti 4 years, 8 months ago

Fluorine

Tanuj Kumar 4 years, 8 months ago

Vansh Gupta 4 years, 8 months ago

ANSWER

Construct a tangent to a circle of radius from a point on the concentric circle of radius 6 cm and measure its length verify the measurement by actual calculation.

Posted by Shristi Patnaya Patnayak 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Vansh Gupta 4 years, 8 months ago

Good question

4Thank You

Vansh Gupta 4 years, 8 months ago

ANSWER

Measure the heights of students of students of your class and form a grouped frequency distribution table of the data. Find the mean with appropriate method

Posted by Kavya Harini 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Mohit Bhashani 4 years, 8 months ago

I love you and your boobs

ANSWER

Prove that ( 2,2),(-2,1),(5,2) are the vertices of right angle triangle

Posted by Pranayee Padhi 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

P Srinivas 4 years, 8 months ago

Distance between (2,2)&(-2,1) is root 17 Distance between (-2,1)& (5,2) is Root 50 Distance between (5,2)&(2,2) is Root 9 So as per this Question is mistake

ANSWER

Find the value of 2cos67°/sin23°+tan 40°/cot 50°+cos0°

Posted by Rupakshi Indwar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

2cos(90_23)/sin23+tan (90_50)/cot50+1 ( cos0=1) 2sin23/sin23+cot50/cot50+1 2×1+1+1 4 ans.

K Buwa 4 years, 8 months ago

This topic is deleted

ANSWER

If bcosx = a then prove cosecx + cotx = √ b + a / b - a

Posted by Maths With Monmohan Borah 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

P Srinivas 4 years, 8 months ago

Given bcosx=a Cosx=a/b. Equation (1) From identity Sinx=√1-cos²x Sinx=√1-(a/b)² Sinx=√b²-a²/b. Equation (2) Now Cosecx+cotx=1/sinx. + Cosx/sinx =(1+cosx)/sinx From equation (1)&(2) =(1+a/b)÷(√b²-a²)/b =(b+a)÷(√b²-a²) =√(b+a)²÷(√b²-a²) =√(b+a)²/(b²-a²) =√(b+a)(b+a)/(b+a)(b-a) =√(b+a)/(b-a) Hence proved

ANSWER

If a line segment AB is to be divided in the ratio 5:8 internally, we draw a ray AX such that ∠BAX is an acute angle. What will be the minimum number of points to be located at equal distances on ray AX?

Posted by Shivi Verma 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

Minimum no.of point on Ax=5+8=13

Abcd Xyz 4 years, 8 months ago

ANSWER

A box contains 30 cards out of which Y cards are blue if one

Posted by Siddharth Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Kiran Chaudhri 4 years, 8 months ago

What is the question complete the question

ANSWER

Write a quadratic polynomial the sum of whose zeroes is -3 and product is -10.

Posted by Shivi Verma 4 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Reema Janu 4 years, 8 months ago

X^2 + 3x -10

Kiran Kumari 4 years, 8 months ago

Sum of zero = _3 Products of zero =_10 Then the quadratic polynomial =x^2_( a+b )x+ab X^2+3_10

Bhoomika Verma 4 years, 8 months ago

Sum of the zeroes = -3 Product of the zeroes = -10 X2 -(sum of the zeroes)x+(product of the zeroes) x2-(-3)x+(-10) X2 + 3x-10

Hari Prasath 4 years, 8 months ago

Hope this helps u X^2-x(sum of zeros )+product of zero X^2-x(-3)+(-10) X^2+3X-10 is required qudatric polynomial

3Thank You

ANSWER

Sample paper 2020-21 solution

Posted by Pihu Yadav 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 8 months ago

This year, CBSE has made too many changes in the question paper pattern. As per the revised curriculum document issued by CBSE for session 2020-21, there will be 50% MCQ and objective type questions. The unseen passages in CBSE Class 10 English Sample Paper 2020-21 will have only MCQs. In the same way, there are many other segments in CBSE model question papers for class 10 English that have been completely changed. So, it is very important to understand the class 10 English question paper 2020-21 pattern and prepare for exams accordingly.

Click on the given link for paper and answer:

<a data-ved="2ahUKEwij9daNmP_tAhXNfX0KHXECA6YQFjATegQIHxAC" href="http://cbseacademic.nic.in/SQP_CLASSX_2020-21.html" ping="/url?sa=t&source=web&rct=j&url=http://cbseacademic.nic.in/SQP_CLASSX_2020-21.html&ved=2ahUKEwij9daNmP_tAhXNfX0KHXECA6YQFjATegQIHxAC" rel="noopener" target="_blank">Class X 2020-2021 SQP and MS - CBSE | Academics Unit</a>

ANSWER

Case studies question

Posted by Lovepreet Hanjra 4 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Kiran Chaudhri 4 years, 8 months ago

Practice the questions of case study from sample paper

ANSWER

Posted by Vipin Kumar 4 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Kiran Chaudhri 4 years, 8 months ago

What is this ?

Gaurav Seth 4 years, 8 months ago

The question you are asking is not clear or incomplete.
You can add more details like chapter name or book name.
Ask specific question which are clear and concise.
Ask properly stated queries for the answer.

Ff_Girl Tannu 4 years, 8 months ago

Yee kya hai ??

ANSWER

Find the area of shaded region in the figure, if ABCD is a square of 14 cm and APD and BPC are semi circles

Posted by Rajat Arora 4 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kiran Kumari 4 years, 8 months ago

Area of shaded region =area of square_area of 2 semicircle =14×14_(22/7×7×7) 196_154 42cm^2

Yogita Ingle 4 years, 8 months ago

Area of shaded region = Area of square − Area of two semicircles
Area of square ABCD =14×14 = 196cm²
Area of two semicircles = Area of 1 complete circle =22/7 ×7×7 =154cm2
∴ Area of shaded region = 196−154 =42 cm2