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Let there are two pipes A and B and diameter of A is larger than B. Now suppose that Pipe A take x hours and Pipe B takes y hours to fill the pool separately . In 1 hour pipe A can fill the pool = x 1 In 1 hour pipe B can fill the pool= y 1 If both pipe are together then they take 12 hour to fill the pool. If the are togther then in 1 hour they fill the pool. x 1 + y 1 = 12 1 −−−−(1) Now In 4 hour pipe A can fill the pool is= x 4 In 9 hour pipe B can fill the pool is= y 9 than they fill half of the pool,so x 4 + y 9 = 2 1 −−−−−(2) Now Let x 1 =P & y 1 =Q and puuting in equation 1 &2, than P+Q= 12 1 ⇒12P+12Q=1−−−−(3) And 4P+9Q = 2 1 ⇒8P+18Q=1−−−−−(4) Now solving equation 3 & 4 Equation (3) multiplying by 2 and (4) multiplying by 3 and substract. ⇒−30Q=−1 ⇒Q= 30 1 now put value of Q in equation 3 We get P= 20 1 So we found P= 20 1 & Q= 30 1 So x=20 and y=30 Hence the A pipe would take 20 hours and the pipe B would take 30 hours separately .

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What is division algorithm?

Posted by Bibeka Nanda Chhatri 4 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Sanskriti Pancheswer 4 years, 3 months ago

If p(x) and g(x) are any two polynomials with g(x) ≠ 0, then we can find polynomials q(x) and r(x) such that p(x) = g(x) × q(x) + r(x). Dividend = Divisor × Quotient + Remainder Steps to divide Polynomials Arrange terms of dividend & divisor in decreasing order of their degrees Use Euclid formula to divide

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Nikky Dubey 4 years, 3 months ago

p(x)=g(x)*q(x)+r(x) Dividend=divisor*quotient+remainder

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Sum of the first twenty terms of an ap is -240 and its first term is 7. Find it's 24th term

Posted by Fai Tabs_246 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sanskriti Pancheswer 4 years, 3 months ago

Given : Sum of 20 terms of an AP =−240 and First term 7 Sum of first n terms of an AP is given as S= 2 n [2a+(n−1)d] n=20,S=−240,a=7 ⇒−240= 2 20 [2×7+(20−1)d] ⇒−240=10[14+19d] ⇒−240=140+190d ⇒−190d=140+240 ⇒−190d=380 ⇒d= −190 380 =−2 n th term of an AP =a n =a+(n−1)d ⇒a 24 =7+(24−1)(−2) ⇒a 24 =7−46 ⇒a 24 =−39

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Use euelids division algorithm to find the hcf of..

Posted by Pradeep Jat 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Santosh Terli 4 years, 3 months ago

?????'? ??? ???????? ????? ??????? ?????? ???? ???

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If Sn = 5n - n^2 Find A7 and A10

Posted by Rimjhim Rai 4 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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The angle between two altitudes of a parallelogram through the same vertex of an obtuse angle of the parallelogram is 30°. The measure of the obtuse angle is

Posted by Praveena Oviya 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Chethas Reddy 4 years, 3 months ago

120,60,120,60 is this u r answer

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Using prime factorization find the HCF andLCM 36 84

Posted by Haleema Khatoon 4 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Haleema Khatoon 4 years, 1 month ago

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Lalan Shah 4 years, 3 months ago

Prime factorization: 36 = 22 × 3. 84 = 22 × 3 × 7. HCF = product of smallest power of each common prime factor in the numbers = 22 × 3 = 12 .LCM = product of greatest power of each prime factor involved in the numbers = 22 × 32 × 7 = 252.

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Solution for 9x²+14x-8 using completing square method

Posted by Pavan K Anchan 4 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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What is the common difference of four terms in A.P. such that the ratio of the product of the first fouth term to that of the second and third term is 2 3: and the sum of all four terms is 20?

Posted by Pranav Krishna 4 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

the graph of a quadratic polynomial is a ____________

Posted by Ahova William 4 years, 3 months ago

CBSE > Class 10 > Mathematics

5 answers

Satyajit Samal 4 years, 3 months ago

Parabola

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Asiya? Shanavas 4 years, 3 months ago

Parabola

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Anjali Joshi 4 years, 3 months ago

Parabola

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Monu Muskan 4 years, 3 months ago

Parabola

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Sia ? 4 years, 3 months ago

parabola

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Solve for x and y by elimination method : 4x-3y=7 x+2y=3

Posted by Stuti Purohit 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Hetvi Tandel 4 years, 3 months ago

(x, y) =(5/2, 1)

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P(x)= 3x^4+5x^3-7x^3-2x+2,g(x)=x^2+3x+1

Posted by Ranveer Singh 4 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

2x2+3X+1=0

Posted by Ashish Meena 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

Given 2x²+3x+1=0
On comparing this equation with ax²+ bx + c = 0, where a = 2, b = 3, c = 1
∴ b²− 4ac = (5)²− 4 × 2 × 1
= 9 − 8
= 1
x = −b±b2−4ac / 2a
= −3±1 / 2×2
x = −3+1 / 4 or x = −3−1 / 4
x = −2 / 4 or x = −4 / 4
x = −1/2 or x = −1

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Polynomial ex. 2.2

Posted by Komal Patel 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Chethas Reddy 4 years, 3 months ago

What is question about

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The third zero of the polynomial x³-8x²+19x-12 if it's one zero is x=1 are

Posted by Reddem Bhanu 4 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

5root is irrational

Posted by Jyoti Singh 4 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

User ....???.... 4 years, 3 months ago

Root 5 is an irrational number.

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Reddy Patnam 4 years, 3 months ago

Yes , it's true

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Madhav Taneja 4 years, 3 months ago

Yes √5 is irrational

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Nsheo

Posted by Naveen Chhikara 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

Please ask question with complete information.

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Find 2 consecutive positive integers ,sum of whose squares is 925.

Posted by Naveen Chhikara 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

let first integer be x
then its consecutive integer be (x+1)
according to question
x^2 + (x+1)^2 = 925
2x^2 + 2x - 924 = 0
x^2 + x - 462 = 0
x = -1 +- √1 + 4*462 / 2
x = -1 +- 43/2
x = -1 + 43 /2 = 21
x = -1 - 43/2 = -22
x = 21 , -22

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Solve... 0.2x + 0.3y =1.3 0.4x + 0.5y = 2.3

Posted by Chhaya Dubey 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Saloni Harinkhede 4 years, 3 months ago

Answer Let 0.2x+0.3y=1.3 ....(1) 0.4x+0.5y=2.3 ....(2) Multiply eqn(1) by 10 we get 2x+3y=13 ....(3) Multiply eqn(2) by 10 we get 4x+5y=23 ....(4) Solving equations (3) and (4) 5×(3)⇒10x+15y=65 3×(4)⇒12x+15y=69 Subtracting we get 12x+15y−10x−15y=69−65=4 or 2x=4 or x=2 Substituting x=2 in eqn(3) we get 2x+3y=13⇒2×2+3y=13 or 3y=13−4=9 or y=3 Hence x=2,y=3

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4052 and 12579 division algorithm

Posted by Sakshi Madheshiya 4 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 3 months ago

According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r which satisfies the condition a = bq + r where 0 ≤ r ≤ b.

HCF is the largest number which exactly divides two or more positive integers.

Since 12576 > 4052

12576 = (4052 × 3) + 420

420 is a reminder which is not equal to zero (420 ≠ 0).

4052 = (420 × 9) + 272

271 is a reminder which is not equal to zero (272 ≠ 0).

Now consider the new divisor 272 and the new remainder 148.

272 = (148 × 1) + 124

Now consider the new divisor 148 and the new remainder 124.

148 = (124 × 1) + 24

Now consider the new divisor 124 and the new remainder 24.

124 = (24 × 5) + 4

Now consider the new divisor 24 and the new remainder 4.

24 = (4 × 6) + 0

Reminder = 0

Divisor = 4

HCF of 12576 and 4052 = 4.

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