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  • 1 answers

Yatharth S 7 years, 8 months ago

We know that a=bq+r So 3 can be written in divided a=3q+r Where 0<=R<3 REMAIder can be, 0,1,2 Putting r=0 a=3q+0 a=3q Square both side a2=(3q)2 a2=9q2 A2= 3(3q2) A2= 3m where m= 3q2 Then put r= 1 and 2 Thanks Now do it yourself
  • 1 answers

Yash Pansari 7 years, 8 months ago

2a+2b
  • 4 answers

Shruti Mishra 7 years, 8 months ago

Maha tricks subject but interesting

Khushi K 7 years, 8 months ago

He..he???

Khushi K 7 years, 8 months ago

Meri aatma tumhe hamesha sataegi...maths fullform

Aahna Pushpa 7 years, 8 months ago

Mentally unstable tension
  • 1 answers

Anurag Shaw 7 years, 8 months ago

5a+5b is the answer
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  • 2 answers

Aahna Pushpa 7 years, 8 months ago

4

Praveena Praveena 7 years, 8 months ago

The answer is 4
  • 1 answers

Pratyush Kumar 7 years, 8 months ago

Euclid is name of mathematician who have many theoram in maths
  • 1 answers

Sia ? 6 years, 5 months ago

According to the question, {tex}\sin (A - B) = \frac{1}{2}{/tex}, therefore, {tex}A - B ={/tex} 30o ........ (1)
{tex}\cos (A + B) = \frac{1}{2}{/tex}, therefore, A + B = 60o ........ (2)
Solving (1) and (2), we get
A = 45o and B = 15o

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Sia ? 6 years, 6 months ago

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

  • 1 answers

Yash Pansari 7 years, 8 months ago

0is nir even nir odd no.
  • 1 answers

Yatharth S 7 years, 8 months ago

A no which is divided by 1 or the no itself is called prime number Ex .. 3= 1x3 A no which has two or more than 2 factors are composite numbers. Ex.. 4= 1x4 2x2 2 is only a even prime no..
  • 1 answers

Anirudh Neeeaja 7 years, 8 months ago

Kyonke decimal ke bad 3 digits hone ka karan islea ham 1000 se multiply kartae hai
  • 1 answers

Sia ? 6 years, 6 months ago

0.001 kg

  • 1 answers

Samiksha Khandelwal 7 years, 8 months ago

HCF=6&LCM=2160
  • 1 answers

Sia ? 6 years, 6 months ago

{tex}12576 = 4052 \times 3 + 420{/tex}
{tex}4052 = 420 \times 9 + 272{/tex}
{tex}420 = 272 \times 1 + 148{/tex}
{tex}272 = 148 \times 1 + 124{/tex}
{tex}148 = 124 \times 1 + 24{/tex}
{tex}124 = 24 \times 5 + 4{/tex}
{tex}24 = 4 \times 6 + 0{/tex}
HCF of 12576 and 4052 is '4'.

  • 2 answers

Samiksha Khandelwal 7 years, 8 months ago

HCF=4,LCM=9696

Samiksha Khandelwal 7 years, 8 months ago

HCF=4 ,LCM=9686
  • 1 answers

Sia ? 6 years, 6 months ago

The given equation is 4x2 - 4x + 1 = 0

Here a = 4, b = - 4, c= 1

{tex}\therefore D=b^2-4ac = (-4)^2-4(4)(1) = 16-16=0{/tex}

So, the given equation has equal roots

{tex}x = {-b \pm \sqrt{D} \over 2a} = {-(-4) \pm0 \over 2(4)}{/tex}

{tex}\implies x={4 \over 8}= {1 \over2}{/tex}

{tex}Hence,\, x={1 \over 2}, \,{1 \over 2}{/tex}are the required roots.

  • 1 answers

Sia ? 6 years, 6 months ago

Given, {tex}3x -{/tex} {tex}\frac{y+7}{11}{/tex} {tex}+ 2 = 10{/tex}
{tex}\Rightarrow \frac{33 x-(y+7)+22}{11}=10{/tex}
{tex}\Rightarrow{/tex} {tex}33x - y - 7 + 22 = 110{/tex}
{tex}\Rightarrow{/tex} {tex}33x - y = 95{/tex} ..(i)
Also, {tex}2 y+\frac{x+11}{7}{/tex} = 10
{tex}\Rightarrow \quad \frac{14 y+x+11}{7}{/tex} = 10
{tex}\Rightarrow{/tex} {tex}14y + x + 11 = 70{/tex}
{tex}14y + x = 59{/tex}
{tex}14y = 59 - x{/tex}

 {tex}\Rightarrow{/tex} y = {tex}\frac{59-x}{14}{/tex}
eq. (i) becomes
33x - {tex}\left(\frac{59-x}{14}\right){/tex} = 95
{tex}\Rightarrow \quad \frac{462 x-59+x}{14}{/tex} = 95
{tex}\Rightarrow{/tex} 463x - 59 = 1330
{tex}\Rightarrow{/tex} x = 3
When x = 3 eq. (i) becomes
33(3) - y = 95
{tex}\Rightarrow{/tex} y =4

  • 1 answers

Shruti Mishra 7 years, 8 months ago

I think science because commerce is easy in only class 11 and12 but if we face competitive exam we find difficulty in commerce That is not possible To learn properly about commerce in 2 years only and we are familiar with science so we can do best
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  • 1 answers

Sia ? 6 years, 6 months ago

Assume A has x mangoes and B has y mangoes.
As per given condition if B gives 30  then A will have twice as many as left  by B.
(x + 30) = 2(y - 30)
{tex}\Rightarrow{/tex}x + 30 = 2y - 60
{tex}\Rightarrow{/tex} x = 2y - 90....(1)
And if A gives 10 mangoes to B, then B will have thrice as many as left by A.
3(x - 10) = (y + 10)
{tex}\Rightarrow{/tex} 3x = y + 40 ....(2)
{tex}\Rightarrow{/tex} 3(2y - 90) = y + 40 (using x from Eq. 1)
{tex}\Rightarrow{/tex} 6y - 270 = y + 40
{tex}\Rightarrow{/tex} 6y - y = 310
{tex}\Rightarrow{/tex}  y = 62
Put y = 62 in (1)
So, x = 124 - 90 = 34
Therefore A has 34 mangoes and B has 62 mangoes.

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Sia ? 6 years, 6 months ago

A real number x will be called a solution or a root if it satisfies the equation.

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