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Ask QuestionPosted by Tanmay Wani 7 years, 8 months ago
- 3 answers
Prateek Chawla 7 years, 8 months ago
13(7*11+1)
as the no. can be represented as product of two numbers , so it is a composite no.
Posted by Pawan Sharma 7 years, 8 months ago
- 2 answers
Soch Sapne Se Badhkar 6 years, 4 months ago
Soch Sapne Se Badhkar 6 years, 4 months ago
Posted by Kashish Choudhary 7 years, 8 months ago
- 1 answers
Posted by Shweta Kumari 6 years, 5 months ago
- 1 answers
Sia ? 6 years, 5 months ago
The largest positive integer that will divide 398, 436 and 542 leaving reminders 7, 11 and 15 respectively is the HCF of the numbers (398 – 7), (436 – 11) and (542 – 15) i.e. 391, 425 and 527.
HCF of 391,425 and 527:
HCF of 425 and 391:
425 = 391 × 1 + 34
391 = 34 × 11 + 17
34 = 17 ×2 + 0
HCF of 425 and 391 = 17
527 = 17 × 31
Similarly, HCF of 17 and 527 = 17
So, HCF of (391,425 ,527) = 17
∴ Required number is 17.
Posted by Jai Chand 7 years, 8 months ago
- 0 answers
Posted by Radhika :) Mishra:} 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by its property i² = −1.
Posted by Amit Saini 7 years, 8 months ago
- 1 answers
Sagar Raj Singh 7 years, 8 months ago
Posted by Saswat Saidutta 7 years, 8 months ago
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Shweta Kumari 7 years, 8 months ago
Posted by Shruti Mishra 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html
Posted by Anurag Kumar 7 years, 8 months ago
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Sia ? 6 years, 5 months ago
The given polynomial is
p(x) = 6x2 -7x -3
Factorize the above quadratic polynomial, we have
6x2 -7x -3 = 6x2 -9x + 2x - 3
= 3x(2x - 3) + 1(2x - 3)
= (3x + 1)(2x - 3)
For p(x) = 0, either 3x + 1 = 0 or 2x - 3 = 0
{tex}\Rightarrow \quad x = \frac { - 1 } { 3 } \text { or } x = \frac { 3 } { 2 }{/tex}
Verification:we have a = 6, b = -7, c = -3
Sum of zeroes = {tex}\frac { - 1 } { 3 } + \frac { 3 } { 2 } = \frac { 7 } { 6 }{/tex}
Also, {tex}\frac { - b } { a } = \frac { - ( - 7 ) } { 6 } = \frac { 7 } { 6 }{/tex}
Now, product of zeroes= {tex}\left( - \frac { 1 } { 3 } \right) \times \frac { 3 } { 2 } = \frac { - 1 } { 2 }{/tex}
Also, {tex}\frac { c } { a } = \frac { - 3 } { 6 } = \frac { - 1 } { 2 } {/tex}
Posted by Animesh Rajawat 7 years, 8 months ago
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Posted by Shreya Sharma 7 years, 8 months ago
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Priyanshu Kumar 7 years, 8 months ago
Posted by Aman Ankit Aman 7 years, 8 months ago
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Debasish Roy 7 years, 8 months ago
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Debasish Roy 7 years, 8 months ago
Sanskriti Roy 7 years, 8 months ago

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Bharti Goyal 7 years, 8 months ago
0Thank You