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  • 1 answers

Kanchana Raja 7 years, 8 months ago

use splitting midle term method 6x2-7x-3 =6x2 -2x + 9x - 3 =2x(3x - 1) +3(3x -1) = (3x -1)(2x+3)
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Vigneshwaran S 7 years, 8 months ago

Use heron's formula

Vigneshwaran S 7 years, 8 months ago

Where is it given
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Jaya Pundir 7 years, 8 months ago

Because herbivores eats grass with contain cellulose and cellulose takes much time to be digest while carnivorous eat meat which contains Protein and protein can be easily digested. Thus herbivores have larger intestine than carnivorous.

Venkatesh 7 years, 8 months ago

Because herbivores eat food that offs rich in starch. And starch is mainly digested on small intestine.
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Sia ? 6 years, 5 months ago

Consider two right triangles ABC and PQR in which {tex} \angle B{/tex}  and {tex}\angle Q{/tex}  are the right angles.
We have,

In {tex}\triangle ABC{/tex}
{tex}\sin B=\frac{AC}{AB}{/tex} 
and, In {tex}\triangle PQR{/tex} 
{tex}\sin Q=\frac{PR}{PQ}{/tex}
{tex} \because \quad \sin B = \sin Q{/tex}
{tex} \Rightarrow \quad \frac { A C } { A B } = \frac { P R } { P Q }{/tex}
{tex} \Rightarrow \quad \frac { A C } { P R } = \frac { A B } { P Q } = k{/tex}(say) ...... (i)
{tex} \Rightarrow {/tex} AC = kPR and AB = kPQ .....(ii)
Using Pythagoras theorem in triangles ABC and PQR, we obtain 
AB2 = AC2 + BC2 and PQ2 = PR2 + QR2
{tex} \Rightarrow \quad B C = \sqrt { A B ^ { 2 } - A C ^ { 2 } } \text { and } Q R = \sqrt { P Q ^ { 2 } - P R ^ { 2 } }{/tex}
{tex} \Rightarrow \quad \frac { B C } { Q R } = \frac { \sqrt { A B ^ { 2 } - A C ^ { 2 } } } { \sqrt { P Q ^ { 2 } - P R ^ { 2 } } } = \frac { \sqrt { k ^ { 2 } P Q ^ { 2 } - k ^ { 2 } P R ^ { 2 } } } { \sqrt { P Q ^ { 2 } - P R ^ { 2 } } }{/tex} [ using (ii) ]
{tex} \Rightarrow \quad \frac { B C } { Q R } = \frac { k \sqrt { P Q ^ { 2 } - P R ^ { 2 } } } { \sqrt { P Q ^ { 2 } - P R ^ { 2 } } } = k{/tex}...(iii)
From (i) and (iii), we get
{tex} \frac { A C } { P R } = \frac { A B } { P Q } = \frac { B C } { Q R }{/tex}
{tex} \Rightarrow \quad \Delta A C B - \Delta P R Q{/tex} [By S.A.S similarity]
{tex} \therefore \quad \angle B = \angle Q{/tex} 
Hence proved.

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Sia ? 6 years, 5 months ago

Let the number be (3q + r)
{tex}n = 3 q + r \quad 0 \leq r < 3{/tex}
{tex}\text { or } 3 q , 3 q + 1,3 q + 2{/tex}
{tex}\text { If } n = 3 q \text { then, numbers are } 3 q , ( 3 q + 1 ) , ( 3 q + 2 ){/tex}
{tex}3 q \text { is divisible by } 3{/tex}.
{tex}\text { If } n = 3 q + 1 \text { then, numbers are } ( 3 q + 1 ) , ( 3 q + 3 ) , ( 3 q + 4 ){/tex}
{tex}( 3 q + 3 ) \text { is divisible by } 3{/tex}.
{tex}\text { If } n = 3 q + 2 \text { then, numbers are } ( 3 q + 2 ) , ( 3 q + 4 ) , ( 3 q + 6 ){/tex}
{tex}( 3 q + 6 ) \text { is divisible by } 3{/tex}.
{tex}\therefore \text { out of } n , ( n + 2 ) \text { and } ( n + 4 ) \text { only one is divisible by } 3{/tex}.

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Sia ? 6 years, 5 months ago

  1. Let us find HCF of 396 and 231 using Euclid’s division algorithm

    {tex}\begin{array}{l}396=231\times1+165\\231=165\times1+66\\165=66\times2+33\\66=33\times2+0\\So\;HCF(396,231)=33\\\end{array}{/tex}

    So 33 is common factor of 396 and 231

    and co-prime numbers have common factor of 1 only.
    ∴ The 396 and 231 are not co-prime.

  2. Here we have to find out HCF of 2160 and 847 by Using Euclid’s division Lemma, we get
    2160 = 847{tex}\times{/tex}2 + 466
    Also 847 = 466{tex}\times{/tex}1 + 381
    466 = 381{tex}\times{/tex}1 + 85
    381 = 85{tex}\times{/tex}4 + 41
    85 = 41{tex}\times{/tex}2 + 3
    41=3{tex}\times{/tex}13 + 2
    3 = 2{tex}\times{/tex}1 + 1
    2 = 1{tex}\times{/tex}2 + 0
    {tex}\therefore{/tex}HCF = 1.
    Hence the numbers are co-prime.

  • 2 answers

Yuv Raj Singh 7 years, 8 months ago

Pair of two prime numbers are called to prime

Komal Arora 7 years, 8 months ago

Co prime are those pair of numbers which have a common factor as 1 ex- 15=3×5×1 16=4×3×1
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Khushi Mahal 7 years, 8 months ago

The chemical equation represented by the name of reactant and product then it is called as equation .

Khushi Mahal 7 years, 8 months ago

These are called balanced equation

Raghav Sharma 7 years, 8 months ago

L. H. S. = R. H. S. A statement in which many variables along with numerous numbers gives out the terms of rhs.. Such that LHS=RHS...
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Punjabi And 7 years, 8 months ago

Punjabi
  • 7 answers

Diksha Gyamnani 7 years, 8 months ago

Hello guys

Diksha Gyamnani 7 years, 8 months ago

I think yuvraj tum abhi class 10 mai aaye ho kyonki Mene class 10 ka paper de Diya h

Yuv Raj Singh 7 years, 8 months ago

Paper hone ke baad

Aashu Singh 7 years, 8 months ago

Second week of may

Diksha Gyamnani 7 years, 8 months ago

Thanks jashan

Jashan Judge 7 years, 8 months ago

Abhi tak date final nhi hui

Diksha Gyamnani 7 years, 8 months ago

Koi mere question ka bhi jawab do
  • 1 answers

Lipsa Rani 7 years, 8 months ago

180-(B+C)=A Cos(90-(B+C)÷2=Cos (A÷2) Sin (B+C÷2)=Cos (A÷2)
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Lovely Khatri 7 years, 8 months ago

Yes you are genius
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Lipsa Rani 7 years, 8 months ago

Let greater number is x and smaller number is y, 7y=2x, Y=2x÷7, X-y=30, X-2x÷7=30, 7x-2x=210, 5x=210, X=210÷5, X=42, y=42-30=12.

Srushti Kunkolienkar 7 years, 8 months ago

Please answer my question
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Ritik Madan 7 years, 8 months ago

Alpha also stands for thermal expansion coefficient of a compound in physical chemistry. It is also commonly used in mathematics in algebraic solutions representing quantities such as angles.
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Adithya Sreeram 7 years, 8 months ago

Since, Y is equal to MX + 3,. 3x+ 4y = 3x+4{mx+3} and 4x-5{mx+3} 3x+4mx+12 and 4x-5mx-15 24-11=13 Therefore, 13=4x-5mx-15-3x-4mx-12 =X-9mx-27
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Sowmya S 7 years, 8 months ago

I think 1+tan squareA ÷ 1+cot square A = sec square A÷cos square A ( according to trigonometric identity second)

Satvik Bhati 7 years, 8 months ago

Your gùùuuuuu

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