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  • 1 answers

Sia ? 6 years, 6 months ago

Given: A circle with centre O and AOB is diameter.
CAD is a tangent at A. Chord EF || tangent CAD

To prove: AB bisects any chord EF || CAD.
Proof: OA radius is perpendicular to tangent CAD.
{tex}\therefore{/tex} {tex}\angle{/tex}1 = 90°
CAD || EF [Given]
{tex}\therefore{/tex} {tex}\angle{/tex}1 = {tex}\angle{/tex}2 = 90° [alternate interior angles]
Point M is on diameter which passes through centre O.
{tex}\because{/tex} Perpendicular drawn from centre to chord bisect the chord.
Hence, AB bisect any chord EF || CAD.

  • 2 answers

Ansh Vats 7 years, 8 months ago

No need because the whole paper comes from NCERT only we should read each and every part of NCERT books even example to score 98%

Tarun Kumar 7 years, 8 months ago

Our first priority should me NCERT book but for proper practice of physics numericals and maths sum we need a refrence book .
  • 10 answers

Janvi Dahre 7 years, 8 months ago

Ok Anya???

Anya Sharma 7 years, 8 months ago

I am also interested in bio and my aim is doctor u choose ur 11 subject according to ur aim it's help in future and u interested in bio then u give best scoring in boards 12 and keeps promise to ur parents for best scoring

Naman Mittal 7 years, 8 months ago

Choice bio

Jay Vaghasiya 7 years, 8 months ago

Jo baka takalif to revani ho

Janvi Dahre 7 years, 8 months ago

Ok guys

Sourish D Great 7 years, 8 months ago

Choose comas its easy

Priya Tomar 7 years, 8 months ago

Choose bio because you are interested in bio....

Pawan Kumar 7 years, 8 months ago

First what do you want to be?

Meraj Ahmed 7 years, 8 months ago

It's depend on ur interest no one can force u

Janvi Dahre 7 years, 8 months ago

Answer do koi
  • 2 answers

Jay Vaghasiya 7 years, 8 months ago

No it wiil not be in mid of may Tt wiil be on end of may

Pawan Kumar 7 years, 8 months ago

Mid of may
  • 1 answers

Sia ? 6 years, 6 months ago

{tex}\frac{{n(n + 1)}}{{\sqrt 2 }}{/tex}

  • 1 answers

Sia ? 6 years, 5 months ago

Let the points A (2, 3), B{tex}\left( {4,k} \right){/tex} and C{tex}\left( {6, - 3} \right){/tex} be collinear.
If the points are collinear then area of triangle ABC formed by these three points is 0.
{tex}\therefore {/tex}{tex}{\text{ar}}\left( {\Delta {\text{ABC}}} \right) = \frac{1}{2}\left[ {{x_1}\left( {{y_2} - {y_3}} \right) + {x_2}\left( {{y_3} - {y_1}} \right) + {x_3}\left( {{y_1} - {y_2}} \right)} \right]{/tex}= 0
{tex} \Rightarrow {/tex}{tex}\frac{1}{2}\left[ {2\left( {k + 3} \right) + 4\left( { - 3 - 3} \right) + 6\left( {3 - k} \right)} \right] = 0{/tex}
{tex} \Rightarrow {/tex}{tex}\left[ {2k + 6 - 24 + 18 - 6k} \right] = 0{/tex}
{tex} \Rightarrow {/tex}{tex}\left[ { - 4k} \right] = 0{/tex}
{tex} \Rightarrow {/tex}{tex}k = 0{/tex}

  • 2 answers

Jay Vaghasiya 7 years, 8 months ago

Circle no radio kem kadhvo

Harsh Nainwal Harsh 7 years, 8 months ago

I think yur question is wrong
  • 4 answers

Ileesha Mittal 7 years, 8 months ago

No pie is not rational but its values are rational like 3.14,22/7 because they are not in their complete form so pie is irrational

Shivani K 7 years, 8 months ago

Ya ri8 pie is not rational....

Kesharwani Aditya 7 years, 8 months ago

No

Vishal Sharma 7 years, 8 months ago

No pie is irrational
  • 1 answers

Prem Choudhary 7 years, 8 months ago

<hr />

Draw a triangle ABC in which BC should be Base and triangle is at right angle at ang.C

Now in triangle ABC

Cos A= side adjacent A/Hypotenuse

= AC/AB

Similarly,

COS B = side adjacent B/Hypotenuse

= BC/AB

Given that

COS A= COS B

AC/AB=BC/AB

AC=BC

IN A TRIANGLE OPPOSITE SIDES ARE EQUAL

ANG B= ANG A

PROVED..

 

  • 1 answers

Ileesha Mittal 7 years, 8 months ago

Of which book
  • 1 answers

Jashan Judge 7 years, 8 months ago

2(x^2 - 25)
  • 2 answers

Ileesha Mittal 7 years, 8 months ago

Let two consecutive + ve integer r n and n+1 n*n+1=n2+ n Let n=2q so (2q)2 + 2q Then we take common from it 2 then we have 2(2q2+q) Divide by 2 then we have 2q2+q Remainder is 0 so it is completely divisible Hence prooved...

Ileesha Mittal 7 years, 8 months ago

Take a example 2*1=2and then divive by 2 so 2/2=1 So it is completely devisible
  • 2 answers

Saurabh Singh 7 years, 8 months ago

Ya but it is process for such type of guestion but I want whole solution

Abhilasha Rajput 7 years, 8 months ago

By assuming root 6 as a rational number
  • 1 answers

Vishesh Kathuria 7 years, 8 months ago

Ex 1/4 ,-1 sum of zeroes= 1/4 ,product of zeroes=-1,p(x)=K(x²-(sum of zeroes)x + (product of zeroes),p(x)=K(x²-¼x+-1),p(x)=(4x²-1x-4)
  • 1 answers

Yashdeep Yadav 7 years, 8 months ago

Alpha+beta and product of zero =alpha*beta
  • 0 answers
  • 3 answers

Naman Mittal 7 years, 8 months ago

Motivasional math

Yashdeep Yadav 7 years, 8 months ago

R.D Sharma

Sourabh Suman 7 years, 8 months ago

R.D.sharma
  • 0 answers
  • 2 answers

Divya Yadav 7 years, 8 months ago

Sorry i haven't read the ques carefully.

Divya Yadav 7 years, 8 months ago

Since 2 and 3 are 0s of polynomial then (x-2) and (x-3) are factors. Then, (x-2)×(x-3) is also a factor. X^2-5x+6 is also a factor. Now divide the given polynomial px by the new factor. U'll get some quotient. Now do middle term split of the quotient and u will get other 0s
ho
  • 0 answers
  • 1 answers

Sia ? 6 years, 5 months ago

No, By the usual definition of prime for integers, negative integers can not be prime.

  • 1 answers

Sia ? 6 years, 5 months ago

x = 6 + 3y
x - 6 = 3y
y = x - 6/3

  • 1 answers

Sia ? 6 years, 5 months ago

Check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html

  • 1 answers

Harsh Raj Raja 7 years, 8 months ago

Let

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