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Divide Xpower4-3xsquare+2x+1 by x-1

Posted by Rasagna Rasagna 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Milind Patel 7 years, 8 months ago

Remainder=1 and ans is Xpower3+Xsquare-2x

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Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively

Posted by Tushar Nagar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Tarun Kumar 7 years, 8 months ago

As they both leave remainders . So to maje tgem exactly dividible we will subtract remainders from the numbers . Therefore , 2053-5 , 967-7 Tge nubers eill be 3048 , 960 Now , find their H.C.F .

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Which book we read during board exam except ncert

Posted by Tanuja Dasgupta 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Big Boss 7 years, 8 months ago

Full marks guide

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Make graph for (x^2+1)&(x^3+1)

Posted by Das Ritesh 7 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Simplify x+2y=3÷4;2x+y=3÷4

Posted by Pragya Patidar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Milind Patel 7 years, 8 months ago

give me thanks plz

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Milind Patel 7 years, 8 months ago

x=y=1/4

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How to write a linear equation of the given statement?

Posted by Ritesh Kumar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Nainwal Harsh 7 years, 8 months ago

But where is given statement

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A solid sphere of radius 6 cm is melted and then recast into small spherical balls each of diameter 0.4cm the number of small balls thus obtained is Plzzz anss corect and fasst plzzz doston

Posted by Mohit Chaudhary 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Milind Patel 7 years, 8 months ago

27000 balls

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Y= √x+2√x+2√......

Posted by Rohit Sharma 7 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Y = √1+2√1+2√1+2√....

Posted by Rohit Sharma 7 years, 8 months ago

CBSE > Class 10 > Mathematics

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Prove that 0/0=equal to 2 HOW??

Posted by Harsh Sharma 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Milind Patel 7 years, 8 months ago

never

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Express that one and only one out of n,n+4,n+8,n+12,n+16 is divisible by 5 where n is any positive integer

Posted by Bhushan Mahtto 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

By Euclid’s division lemma, we have
a = bq + r; 0 ≤ r < b
For a = n and b = 5, we have
n = 5q + r …(i)
Where q is an integer
and 0 ≤ r < 5, i.e. r = 0, 1, 2, 3, 4.
Putting r = 0 in (i), we get
n = 5q
⇒ n is divisible by 5.
n + 4 = 5q + 4
⇒ n + 4 is not divisible by 5.
n + 8 = 5q + 8
⇒ n + 8 is not divisible by 5.
n + 12 = 5q + 12
⇒ n + 12 is not divisible by 5.
n + 16 = 5q + 16
⇒ n + 16 is not divisible by 5.
Putting r = 1 in (i), we get
n = 5q + 1
⇒ n is not divisible by 5.
n + 4 = 5q + 5 = 5(q + 1)
⇒ n + 4 is divisible by 5.
n + 8 = 5q + 9
⇒ n + 8 is not divisible by 5.
n + 12 = 5q + 13
⇒ n + 12 is not divisible by 5.
n + 16 = 5q + 17
⇒ n + 16 is not divisible by 5.
Putting r = 2 in (i), we get
n = 5q + 2
⇒ n is not divisible by 5.
n + 4 = 5q + 9
⇒ n + 4 is not divisible by 5.
n + 8 = 5q + 10 = 5(q + 2)
⇒ n + 8 is divisible by 5.
n + 12 = 5q + 14
⇒ n + 12 is not divisible by 5.
n + 16 = 5q + 18
⇒ n + 16 is not divisible by 5.
Putting r = 3 in (i), we get
n = 5q + 3
⇒ n is not divisible by 5.
n + 4 = 5q + 7
⇒ n + 4 is not divisible by 5.

n + 8 = 5q + 11
⇒ n + 8 is not divisible by 5.
n + 12 = 5q + 15 = 5(q + 3)
⇒ n + 12 is divisible by 5.
n + 16 = 5q + 19
⇒ n + 16 is not divisible by 5.
Putting r = 4 in (i), we get
n = 5q + 4
⇒ n is not divisible by 5.
n + 4 = 5q + 8
⇒ n + 4 is not divisible by 5.
n + 8 = 5q + 12
⇒ n + 8 is not divisible by 5.
n + 12 = 5q + 16
⇒ n + 12 is not divisible by 5.
n + 16 = 5q + 20 = 5(q + 4)
⇒ n + 16 is divisible by 5.
Thus for each value of r such that 0 ≤ r < 5 only one out of n, n + 4, n + 8, n + 12 and n + 16 is divisible by 5.

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If tan thita equal x square minus y square by x square plus y square find all the trigonometrical ratios

Posted by Aman Kumar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Show that tha squre of an odd positive intrger is of the form 8m+1 for whole number m

Posted by Amrita Singh 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Since, any odd positive integer n is of the form 4m + 1 or 4m + 3.

if n = 4m + 1
n² = (4m + 1)²
= 16m² + 8m + 1
= 8(2m² + m) + 1
So n² = 8q + 1 ........... (i)) (where q = 2m² + m is a positive integer)

If n = (4m + 3)
n² = (4m + 3)²
= 16m² + 24m + 9
= 8(2m² + 3m + 1) + 1
So n² = 8q + 1 ...... (ii) (where q = 2m² + 3m + 1 is a positive integer)

From (i) and (ii) we conclude that the square of an odd positive integer is of the form 8q + 1, for some integer q.

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Can two number have16 as their hcf 380 as their LCM? Give reason

Posted by Rahul Kumar Kushwaha 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Milind Patel 7 years, 8 months ago

Noo because 380 is not divisible by16 but every lcm is divisible by hcf

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side AB and BC and median AD of a triangle ABC are propirtional to sidesPQand QR of triangle PQR.Show that triangle ABC us similar to trianglePQR

Posted by Heikhomba Ongnam 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

It is given that:
{tex}\frac { A B } { P Q } = \frac { B C } { Q R } = \frac { A D } { P M }{/tex}
{tex}\Rightarrow \quad \frac { A B } { P Q } = \frac { A D } { P M }{/tex}{tex}= \frac { B C } { Q R } = \frac { \frac { 1 } { 2 } B C } { \frac { 1 } { 2 } Q R } = \frac { B D } { Q M }{/tex} ....................................(i)
In {tex}\triangle ABD{/tex} and {tex}\triangle PQM{/tex}, we have
{tex}\frac { A B } { P Q } = \frac { A D } { P M } = \frac { B D } { Q M }{/tex} [from(i)]
{tex}\therefore \quad \triangle A B D \sim \triangle P Q M{/tex} [by SSS-similarity criteria].
And also, {tex}\angle B = \angle Q{/tex} [corresponding angles of similar triangles are equal].
Now, in {tex}\triangle ABC{/tex} and {tex}\triangle PQR{/tex}, we have
{tex}\angle B = \angle Q{/tex} [proved above]
and {tex}\frac { A B } { P Q } = \frac { B D } { Q M }{/tex} [from(i)].
{tex}\therefore \quad \triangle A B C \sim \triangle P Q R{/tex} [by SAS-similarity criteria].

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Find the smallest number which when increased by 75 is exactly divisible by 325 and 315

Posted by Shivansh Dutta 7 years, 8 months ago

CBSE > Class 10 > Mathematics

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For any integer a and 3,there exists unique integer q and r such that a=3q+r, find the possible value of r.

Posted by Sujal Bais 7 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Milind Patel 7 years, 8 months ago

jass if you donot know ans then never open your mouth

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Milind Patel 7 years, 8 months ago

r can be 0,1,2

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Gurleen Kaur Brar 7 years, 8 months ago

Search from Google madddd

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Easy explanation of substitution

Posted by Asmi Lamba 7 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Kanishka Singh . 7 years, 8 months ago

Substitution means subsituting the value of one variable in the other equation to find the value of other variable. For example : x+y=2 .......(1) x-y=3. ..........(2) We can write equation (2) as x=3+y. ........(3) Now put the value of x in eq. (1) x+y=2 (3+y)+y=2 3+2y=2 2y=2-3 y=-1/2 Substituting value of y in equation 2 x-y=3 x-(-1/2)=3 x+1/2=3 2x+1/2=3 2x+1=6 2x=5 x=5/2 Hence we get value of x and y by substituting value of x to find the value of y.

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Nipun Goyal 7 years, 8 months ago

Substitution is itself so easy.

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Without actually performing the long division state wether 13/3125 rational number terminating or non terminating repeting

Posted by Ayush Raj 7 years, 8 months ago

CBSE > Class 10 > Mathematics

4 answers

Nipun Goyal 7 years, 8 months ago

Convert the denominator in power form and then check whether it is in the form 2 power n×5 power m.if it is in this form then it is terminating and if it is not then it is non-terminating.

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Shweta Singh 7 years, 8 months ago

Means the LCM of 3125 contain 5 therefore it is terminated decimal expansion

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Shweta Singh 7 years, 8 months ago

Here denominator is of the form 2 and 5

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Tarun Kumar 7 years, 8 months ago

As denominator of 13/3125 cantains only facrors of 5 as 3125 = 5^4 Therefore it is non terminating

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If one zero of the polynomial 3x^2+(2k+7)x-4 is negative of the other find the value of k and hence find its zeroes

Posted by Kalidas R 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Tarun Kumar 7 years, 8 months ago

Let two zeros be m and n According to question , m = -n Therefore now two zeros are n, -n Sum of zeros = -b/a b + (-b) = 2k+7/3 0 = 2k+7/3 0×3 = 2k+7 -7 = 2k -7/2 = k

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Show that x^4 + x^2 +3 has no zeros?

Posted by Tarun Kumar 7 years, 8 months ago

CBSE > Class 10 > Mathematics