CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

You can find lcm and hcf like this : Ex 28 and 35 So , 28:7×4 35:7×5 In above you can see that 7 is common than its hcf. Now,. L.c.m in above 7 repeat in both so take 7 common 7×4×5=140 Try it after practice you will understand it.?

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Show that √2 is irrational?

Posted by Vivasvan Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Utkarsh Patel 7 years, 7 months ago

Let √2 is irrational number ,means √2 is a rational number . Let √2= p by q √2^2= p^2 by q^2 2 = p^2 by q^2 2q^2 = p^2 -------(1) q^2=p^2 by 2 ~2 divides p^2 ~2 divides p also. Let p by 2 =r ,for some integer r. p=2r ----------(2) On substituting eq.(2) in eq.(1). 2q^2=2^2.r^2 q^2 = 4r^2 q^2=2r^2 q^2 by 2= r^2 ~2 divides q^2. ~2 divides q also Thus, is a common factor of p and q but this contradict that p and q are coprime so our assumption is wrong . Hence ,√2 is an irrational number

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Utkarsh Patel 7 years, 7 months ago

Let route to be a rational number so it can be written in p by Q form where p and q are coprime numbers means it has only one factor that is 1 and where is not equal to zero

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√2 is irrtional

Posted by Vivasvan Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Triangle ODC congruent to triangle OBA , angle BOC

Posted by Sneha Maheshwari 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove that any consitive integers is divisible by 3

Posted by Sumit Tiwari 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let the three consecutive positive integers be n, n + 1 and n + 2, where n is any integer.
By Euclid’s division lemma, we have
a = bq + r; 0 ≤ r < b
For a = n and b = 3, we have
n = 3q + r ...(i)
Where q is an integer and 0 ≤ r < 3, i.e. r = 0, 1, 2.
Putting r = 0 in (i), we get
{tex}n = 3q{/tex}
∴ n is divisible by 3.
{tex}n + 1 = 3q + 1{/tex}
∴ n + 1 is not divisible by 3.
{tex}n + 2 = 3q + 2{/tex}
∴ n + 2 is not divisible by 3.
Putting r = 1 in (i), we get
{tex}n = 3q + 1{/tex}
∴ n is not divisible by 3.
{tex}n + 1 = 3q + 2{/tex}
∴ n + 1 is not divisible by 3.
{tex}n + 2 = 3q + 3 = 3(q + 1){/tex}
∴ n + 2 is divisible by 3.
Putting r = 2 in (i), we get
{tex}n = 3q + 2{/tex}
∴ n is not divisible by 3.
{tex}n + 1 = 3q + 3 = 3(q + 1){/tex}
∴ n + 1 is divisible by 3.
{tex}n + 2 = 3q + 4{/tex}
∴ n + 2 is not divisible by 3.
Thus for each value of r such that 0 ≤ r < 3 only one out of n, n + 1 and n + 2 is divisible by 3.

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When we prove the cross multiplication in linear equation in tow variable to find the value of y why we subtract equation 2 from 1 not 1 from 2

Posted by Avinash Maurya 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Poorva Sethi 7 years, 7 months ago

its rule of subtraction 2nd statement will always be put on 1st

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Kushagra Chaudhary 7 years, 7 months ago

It depends upon the question

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I want maths subject in Hindi

Posted by Abhishek Chaudhary 7 years, 7 months ago

CBSE > Class 10 > Mathematics

4 answers

Abhishek Chaudhary 7 years, 6 months ago

It is possible.

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Silviya Malik 7 years, 7 months ago

????????????????????

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#Aditi~ Angel???? 7 years, 7 months ago

But its not possible here dear

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#Aditi~ Angel???? 7 years, 7 months ago

Hi abhishek

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What is the requirement of the chapter introduction to trigonometry

Posted by Sachin Sharma 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Anupam Kumar 7 years, 7 months ago

Firstly you want to learn the value of trignometric value.

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#Aditi~ Angel???? 7 years, 7 months ago

Solutions?

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How can we find coinsistent

Posted by Himanshu Sharma 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Avisha Chandak 7 years, 7 months ago

Unique solution that is a1/a2is not equal to b1/b2 And Infinitly many solution that is a1/a2 = b1/b2 = c1/c2 From this we can find consistent And to find in consistent its No solution that is a1/a2 =b1/b2 is not equal to c1/c2

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Method of cross multiplication method

Posted by Anuvart Chaudhary 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Avisha Chandak 7 years, 7 months ago

Given in NCeRT

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3x-y=4 9x-3y=9 Use elemenation methods

Posted by Aryan Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Azhad Jamal 7 years, 7 months ago

Multiply by 3 both side in equation 1 then substract equation 1&2 Ok dear

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Two numbers are in ratio 5:6 if 8 is subtracted from each if the number the ratio become 4:5 find the number

Posted by Paridhi Agrawal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

#Aditi~ Angel???? 7 years, 7 months ago

Where is phone no virat

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Virat Thakur 7 years, 7 months ago

Let the two no be x and y therefore x / y = 5 / 6 6 * x = 5 * y 6 * x - 5 * y = 0 * 5 30 * x - 25 * y = 0 ..................(i) also (x - 8)/(y - 8) = 4 / 5 5 * x - 40 = 4 * y - 32 5 * x - 4 * y - 8 = 0 *6 30 * x - 24 * y - 48 = 0 .....................(ii) subtracting (i) from (ii) y - 48 = 0 y = 48 putting y = 48 in x/y = 5/6 x/48 = 5/6 x = 5 * 48 / 6 x = 5 * 8 x = 40 therefore the two numbers are 40 and 48. Ans.. (Any problem so contact me)???

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2x-2=3

Posted by Eshaan Kundra 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Tanvi Jindal 7 years, 7 months ago

2x-2=3 2x=3+2 x=5/2 x=2.5

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Aryan Abrol 7 years, 7 months ago

2x=3+2 2x=5 X=5÷2 X=2.5

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Aditya Kumar 7 years, 7 months ago

Then,,

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3x-5y-19=0 -7x+3y+1=0

Posted by Ashfaquealam Alam 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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My maths is very weak

Posted by Sidharth Pandey 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Chaudhary 7 years, 7 months ago

Do more practice

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If cot theta =3\4, show that[sectheta -cosec theta \SEC Theta +cosec theta]in root=1\root7

Posted by Mohit Yadav 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let us draw a triangle ABC such that, {tex}\angle{/tex}B = 90°.

Let {tex}\angle{/tex}A = {tex}\theta{/tex}°.

We have, {tex}\cot \theta = \frac { 3 } { 4 }{/tex}
Then, {tex}\cot \theta = \frac { \text { Base } } { \text { Perpendiaular } } = \frac { A B } { B C } = \frac { 3 } { 4 }{/tex}
Let AB = 3 and BC = 4,
By Pythagoras' theorem, we know that
AC² = AB²+ BC²
= 3² + 4² = 9 + 16 = 25
{tex}\Rightarrow \quad AC = 5{/tex}
Now,
{tex}\sec \theta = \frac { \text { Hypotenuse } } { \text { Base } } = \frac { A C } { A B } = \frac { 5 } { 3 }{/tex}
{tex}\text{cosec} \theta = \frac { \text { Hypotenuse } } { \text { Perpendicular } } = \frac { A C } { B C } = \frac { 5 } { 4 }{/tex}
L.H.S = {tex}\sqrt { \frac { \sec \theta - \text{cosec} \theta } { \sec \theta + \text{cosec} \theta } }{/tex}
{tex}= \sqrt { \frac { 5 / 3 - 5 / 4 } { 5 / 3 + 5 / 4 } }{/tex}
{tex}= \sqrt { \frac { \frac { 20 - 15 } { 12 } } { \frac { 20 + 15 } { 12 } } }{/tex}
{tex}= \sqrt { \frac { 5 } { 35 } }{/tex}
{tex}= \sqrt { \frac { 1 } { 7 } }{/tex}
{tex}= \frac { 1 } { \sqrt { 7 } }{/tex}
= R.H.S

therefore, {tex}\sqrt { \frac { \sec \theta - \text{cosec} \theta } { \sec \theta + \text{cosec} \theta } }{/tex}{tex}= \frac { 1 } { \sqrt { 7 } }{/tex}

Hence proved.

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in a comperative exam 1 mark awarded for each correct ans. while 1/2 marks reducted for every incorrect ans.a student answered 120 qst and got 90 mark. how many did she ans. correctly ....

Posted by Shivani Pradhan 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Shivani Pradhan 7 years, 7 months ago

Harsh kumar , can u plz explain me the process...

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Harsh Kumar 7 years, 7 months ago

1OO CORRECT 20 INCORRECT

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What is the value of the root 3

Posted by Nitin Saini 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Nidhi Kumari 7 years, 7 months ago

1.732 is the value of root3

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Harsh Kumar 7 years, 7 months ago

1.732

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There are some lotus flowers on a lake if one butterfly sit on each flower one butterfly will left and if two butterfly will sit on one flower one flower will left. Find the no. of flowers and butterfly. Chapter- polynomial

Posted by Shradha Joshi 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Kumar 7 years, 7 months ago

THREE lotus flowers and FOUR butterflies

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Obtain all other zeroes of the polynomial x⁴-17x²-36x-20 if to of its zeroes are 5 and -2

Posted by Manthan Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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holiday homework

Posted by Deepak Jha 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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In exercise 2.3 que 1(1) how x(square) comes below -4x(square)?

Posted by Maheshwari Damor 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Show that any positive odd integer is in form of 4m+1 or 4m+3

Posted by Prajjwal Kapri 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let a be the positive integer and b = 4.
Then, by Euclid’s algorithm, a = 4q + r for some integer q ≥ 0 and r = 0, 1, 2, 3 because 0 ≤ r < 4.
So, a = 4q or 4q + 1 or 4q + 2 or 4q + 3.
{tex}(4q)^3\;=\;64q^3\;=\;4(16q^3){/tex}
= 4m, where m is some integer.
{tex}(4q+1)^3\;=\;64q^3+48q^2+12q+1=4(\;16q^3+12q^2+3q)+1{/tex}
= 4m + 1, where m is some integer.
{tex}(4q+2)^3\;=\;64q^3+96q^2+48q+8=4(\;16q^3+24q^2+12q+2){/tex}
= 4m, where m is some integer.
{tex}(4q+3)^3\;=\;64q^3+144q^2+108q+27{/tex}

=4×(16q³+36q²+27q+6)+3
= 4m + 3, where m is some integer.
Hence, The cube of any positive integer is of the form 4m, 4m + 1 or 4m + 3 for some integer m.

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In ∆ABC,angle C=3angleB,angleC=2(angleA+angleB),then find all the angles

Posted by Ashok Choudhary 7 years, 7 months ago

CBSE > Class 10 > Mathematics

4 answers

Ashok Choudhary 7 years, 7 months ago

It has been taken from practice papers from cbse guide only

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Shivani Pradhan 7 years, 7 months ago

<A+<B+<C=180 <A+<B+2(<a+<b)=180 3(<a+<b)=180 <a+<b=60....... i again , <a+<b+<c=180 <a+<b+3<b=180 <a+4<b=180......ii subtracting eq.i from eq. ii we get , <B=40 putting the value of B we can find the value of angle A and C.. A=20 , C= 120

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Shivani Pradhan 7 years, 7 months ago

< A+<B+<C=180

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Prashant Chaudhary 7 years, 7 months ago

I am not understanding your question..

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If the difference between the circumstances and the radius of circle is 37 cm then find the circumstances of the circles

Posted by Sarita Yadla 7 years, 7 months ago

CBSE > Class 10 > Mathematics