CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

we have, 2x² + 3x + k = 0.
a = 2, b = 3 and, c= k
The given equation will have real and equal roots, if
D = 0
{tex}\therefore{/tex} D = b²- 4ac =0
{tex}\Rightarrow{/tex} 9 - 4 {tex}\times{/tex} 2 {tex}\times{/tex} k =0
{tex}\Rightarrow{/tex}9 - 8k = 0
{tex} \Rightarrow k= \frac { 9 } { 8 }{/tex}

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5 odd number that add up to get 30. You can repeat the numbers

Posted by Aman Singh Rajput 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Divide x2-5 by x4-3x2-20x-15

Posted by Vinita Bajaj Bajaj 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Kkk Kkk 7 years, 7 months ago

I know ? the answer

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£2×5

Posted by Aakriti Chandra 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the product of the smallest and the largest 4 digit number made with the digits 2,5,8,0

Posted by Anubhuti Arora 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashwin Edakkara 7 years, 7 months ago

8520 ×2058=17534160

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Class 10 ncert 3.6 ques no 3

Posted by Aaditya Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Aaditya Kumar 7 years, 4 months ago

Fb chlati ho

1Thank You

Aaditya Kumar 7 years, 4 months ago

Hyy

1Thank You

Somali Bohidar 7 years, 7 months ago

There's no question three...?? Its till q.2

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The difference between two numbers is 26 and one number is three times the other.

Posted by Sushmita Rawat 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Ileesha Mittal 7 years, 7 months ago

Let one no.be X and oter beY So, X-Y=26 X=3Y X-3Y=0or we put it in eq 1 2Y=26 So Y=13 X=3*13 X=39

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Priyanshu Kumar 7 years, 7 months ago

X=13 Y=39

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Is it necessary to solve LHS firstly?

Posted by Ram Ratan Thakur 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Lakhwinder Gill 7 years, 7 months ago

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Ileesha Mittal 7 years, 7 months ago

No it is not nessesiry it depends on eq.

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Somali Bohidar 7 years, 7 months ago

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A fraction becomes 9/11,if 2 is added to numerator and denomenator .if,3 is addedto both the numerator and denomerator it becomes 5/6 . Find the fraction

Posted by Mumaiz Peer 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Mumaiz Peer 7 years, 4 months ago

X=7,Y=9

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Somali Bohidar 7 years, 7 months ago

X=7, y=9.....glad I could help...?

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ANSWER

39 ÷9=÷45+33

Posted by Pratham Kanyal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepak Prasad 7 years, 7 months ago

123?&+#

1Thank You

ANSWER

Cos 60*

Posted by Himanshu Agrawal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Aisha Jain 7 years, 7 months ago

1/2

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Ncert solution for class 10th exercise 3.6

Posted by Jayanti Shrivastava 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Nagendra Verma 7 years, 7 months ago

The answer of 3.6 is available in study ranker

2Thank You

ANSWER

f(x)=x2+px+45=144 find p.sum of squras of solution

Posted by Prince Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

If the squared difference of the zeroes of the quadratic polynomial f(x) = x² + px + 45 is equal to 144, then ,we have to find the value of p.
Let {tex}\alpha{/tex} and {tex}\beta{/tex} be the zeroes of the given quadratic polynomial.
{tex}\therefore{/tex} {tex}\alpha{/tex} + {tex}\beta{/tex} = - p and {tex}\alpha\beta{/tex}= 45 ...(i)
Given, ({tex}\alpha{/tex} - {tex}\beta{/tex})² = 144
or, ({tex}\alpha{/tex} + {tex}\beta{/tex})²- 4{tex}\alpha{/tex} {tex}\beta{/tex} = 144
or, (-p)² - 4 {tex}\times{/tex} 45 = 144 [Using (i)]
p²- 180 = 144
p² = 144 + 180 = 324
{tex}\therefore{/tex} p = ± {tex}\sqrt{324}{/tex}= ± 18
Hence, the value of p is ± 18.