No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 0 answers
  • 1 answers

Sia ? 6 years, 4 months ago

Let the ten's digit of the required number be x and its unit's digit be y.
As per given condition
A two-digit number is four times the sum of its digits
Then, 10x + y = 4(x + y)
{tex}\Rightarrow{/tex} 6x - 3y = 0
{tex}\Rightarrow{/tex} 2x - y = 0......... (i)
And A two-digit number is twice the product of its digits.
Also, 10x + y = 2xy. ....... (ii)
Putting y = 2x from (i) in (ii), we get
10x + 2x = 4x2
{tex}\Rightarrow{/tex} 4x2- 12 x = 0
{tex} \Rightarrow{/tex} 4x(x - 3) = 0
{tex}\Rightarrow{/tex} x - 3 = 0
{tex}\Rightarrow{/tex} x = 3 [ten's digit, x {tex}\ne{/tex} 0]
Putting x = 3 in (i), we get y = 6.
Thus, ten's digit = 3 and unit's digit = 6.
Hence, the required number is 36.

  • 1 answers

Sia ? 6 years, 4 months ago

According to question It is given that in {tex}\triangle {/tex}ABC, AE is the bisector of the {tex}\angle CAD{/tex}.

Also, BE = BC + CE = 12 + x

CE= x, AB = 10, AC = 6
Since, We know that, the external bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
{tex}\therefore \frac { B E } { C E } = \frac { A B } { A C }{/tex}
{tex}\Rightarrow \frac { 12 + x } { x } = \frac { 10 } { 6 }{/tex} 
{tex}\Rightarrow{/tex} 6(12 + x) = 10x
{tex}\Rightarrow{/tex} 72 + 6x = 10x
{tex}\Rightarrow{/tex} 4x = 72
{tex}\Rightarrow x = \frac { 72 } { 4 }{/tex}
= 18 cm
{tex}\Rightarrow{/tex} CE = 18 cm

  • 2 answers

Manu Prajapati 7 years, 7 months ago

Those numbers which is diveded by itself called prime no

Shreyas Vartak 7 years, 7 months ago

It is divisible by 1 and itself only
  • 1 answers

Amaira Desai 7 years, 7 months ago

B^2-4ac (-7)^2-4×2×3 49-24 25>0 so it's two roots exist. (x+b/2a)^2 - (b/2a)^2+c/a=0 (x+(-7/4))^2-(-7/4)^2+3/2=0 (x-7/4)^2-49/16+3/2=0 (x-7/4)^2=49/16-3/2 (x-7/4)^2=49-24/16 (x-7/4)^2=25/16 (x-7/4)= +-root 25/16 (x_7/4)=+-5/4 X=7/4+-5/4 Either X=7+5/4 X=12/4=3 Or x=7-5/4 X=2/4=1/2
  • 2 answers

Amaira Desai 7 years, 7 months ago

30th of may

Nishant Singh 7 years, 7 months ago

Yet not fixed but may be at last of may or starting of june month
  • 3 answers

Srushti Kunkolienkar 7 years, 7 months ago

What will be the answer

Vaishnavi Priya 7 years, 7 months ago

Find determinant (D) and compare the value of D with Zero if D=0 then it has only one root ,if D is greater than zero than it has many roots and if zero is greater than D then there is no any solutions of the given equation.

Srushti Kunkolienkar 7 years, 7 months ago

How to solve these equation?
  • 1 answers

Varada Menon 7 years, 7 months ago

-√5 and +√5
  • 0 answers
  • 2 answers

Arati Motivarash 7 years, 7 months ago

Xyz

Rashmi Bajpayee 7 years, 7 months ago

(√3/2)(√3/2) + (1/2)(1/2)
= (3/4) + (1/4)
= 4/4
= 1
  • 4 answers

Vivek Kohli 7 years, 7 months ago

0 according to BODMAS

Rahul Sharma 7 years, 7 months ago

0

Rashmi Bajpayee 7 years, 7 months ago

= 2 - 2 x 0.6 x 5 + 3
= 2 - 6 + 3
= 0

Renuka Tiwari 7 years, 7 months ago

3
  • 1 answers

Prachi Ghosh 7 years, 7 months ago

no answer of this question cause (d) is not constant. 69 - 72 = -17 , 66 - 69 = -95 . so, answer 0 .
  • 1 answers

Ujwal Mahajan 7 years, 7 months ago

1663200
  • 4 answers

Amaira Desai 7 years, 7 months ago

2

Priti Purohit 7 years, 7 months ago

2

Prabha Paul 7 years, 7 months ago

2

Adanan Hussain 7 years, 7 months ago

2
  • 0 answers
  • 1 answers

Sia ? 6 years, 4 months ago

If a and b are odd numbers then it should be in 2q+1 or 2q+3 form where q is a positive integer.

Let a = 2q + 3 , b = 2q + 1  and a > b
Now, {tex}\frac{a + b } {2} = \frac{ 2q + 3 + 2q + 1}{2}{/tex}
{tex}= \frac { 4 q + 4 } { 2 }{/tex}
= 2q + 2
{tex}\frac{a+b}{2}{/tex}=2(q+1) = an even number..........(1)
Now

 {tex}\frac { a - b } { 2 } = \frac { ( 2 q + 3 ) - ( 2 q + 1 ) } { 2 }{/tex}
{tex}= \frac { 2 q + 3 - 2 q - 1 } { 2 }{/tex}
{tex}\frac{a-b}{2}= \frac { 2 } { 2 }{/tex} = 1 = an odd number..........(2)
Hence From (1) and (2) {tex}\frac{a+b}{2}{/tex}   and {tex}\frac{a-b}{2}{/tex}   are even and odd numbers respectively

  • 1 answers

Sia ? 6 years, 4 months ago

You can check last year papers here : https://mycbseguide.com/cbse-question-papers.html

  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Sarthak Gupta 7 years, 7 months ago

CBSE Class 10 Syllabus CBSE Syllabus for Class 10 Maths CBSE Syllabus for Class 10 Science CBSE Syllabus for Class 10 English CBSE Syllabus for Class 10 Hindi CBSE Syllabus for Class 10 Social Science
  • 1 answers

Mohit Jangir 7 years, 7 months ago

According to Euclid Division Lemma ,HCF of any two positive integer a and b ,with a>b,is obtained as follow :STEP1:a=bq+r,0<r<b. STEP2:If r=0,the HCFis b. STEP3 :If remainder is 0 then stage will be HCF (a,b).Also ,HCF (a, b)=HCF (b,r).
  • 1 answers

Sia ? 6 years, 4 months ago

2 - √5

  • 1 answers

Sana Kauser 7 years, 7 months ago

{tex}\frac{\theta}{360}{/tex}X{tex} \pi{r^2}{/tex}

  • 0 answers
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App