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1+tan^2a=sec^2a

Posted by Ambika Shigarkanti 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

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Types ofquadratic equation

Posted by Ankit Raj 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Shriya Bhattacharya 7 years, 6 months ago

The equations which have 2 as the degree of polynimial... i.e. in the equation highest degree must be 2 then the equation can be known as quadratic.... Like... ax2+bx+c=0

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Excercise 5.1

Posted by Sumit Tomar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sumit Tomar 7 years, 6 months ago

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Sin 60° cos 30°+cos 60°sin 30° evaluate

Posted by Srushti Kunkolienkar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Abhishek Singh 7 years, 6 months ago

Sin 60° cos 30°+cos 60° sin 30°=0 sin 60° sin (90-60) +cos 60° cos (90-60)=0 sin 60° sin 60°+cos 60° cos 60°=0 1+1= 2.

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Lavanshi Bansal 7 years, 6 months ago

Sin 60° cos(90-30) + cos 60° sin(90-30). =). Sin60°cos60° + cos 60° sin60° =). Sin^260° + cos^260° =). 1 Bcz, sin^2theeta +cos^2theeta =1

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Hou to represent pairs of linear equations in two variables on the graph

Posted by Amar Bind 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Shriya Bhattacharya 7 years, 6 months ago

From the equations find out the values of x and y, from both the equations by making a box and putting any value in x and then finding out the value of y. In this way find out three values of x and y from both the equations. Then plot the points on the graph.

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Using quadratic formula solve x²– 2ax+3x–6a= 0

Posted by Nihal Alam 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

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Real nunber

Posted by Ajeet Gurjar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

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theoram 10.2

Posted by Marigold Dynamic 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

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Given ∆ABC-∆PQR if AB/PQ =1/3 then find arear ∆ABC/area∆PQR

Posted by Vaibhavpal Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given: {tex}\Delta ABC \sim \Delta PQR{/tex}
Since we know that ,the ratio of area of two similar triangles is equal to the square of ratio of their corresponding sides. Thus,
{tex}\frac{\text { ar } \triangle \mathrm{ABC}}{\text { ar } \triangle \mathrm{PQR}}{/tex} = {tex}\frac{\mathrm{AB}^{2}}{\mathrm{PQ}^{2}}{/tex} = {tex}\left(\frac{1}{3}\right)^{2}{/tex} = {tex}\frac{1}{9}{/tex}

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If one zero of the polynomial (a2+9)x2+13x+6a is reciprocal of the other , find the value of a.

Posted by Rishika Verma 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let {tex} \alpha{/tex} and {tex} \frac { 1 } { \alpha }{/tex} be the zeros of (a²+ 9)x²+ 13x + 6a.
Then, we have
{tex} \alpha \times \frac { 1 } { \alpha } = \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
⇒ 1 = {tex} \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
⇒ a² + 9 = 6a
⇒ a² - 6a + 9 = 0
⇒ a² - 3a - 3a + 9 = 0
⇒ a(a - 3) - 3(a - 3) = 0
⇒ (a - 3) (a - 3) = 0
⇒ (a - 3)²= 0
⇒ a - 3 = 0
⇒ a = 3
So, the value of a in given polynomial is 3.

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Sir mere maths me compartment aa gyi h.. aur mera additional subject fit replace ni hua hai.. kya hoga.. kya krey

Posted by Sudhanshu Choudhary 7 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Adarsh Kumar 7 years, 6 months ago

Work hard...

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Swati Tripathi 7 years, 6 months ago

studay again aur Kay

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Find the zeroes of the polynomial : 1.x2+x-a (a+1)

Posted by Rishika Verma 7 years, 6 months ago

CBSE > Class 10 > Mathematics

4 answers

Rishika Verma 7 years, 6 months ago

How the zeroes are a and a+1 can u plz give detailed answer

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Adarsh Kumar 7 years, 6 months ago

Zeros are:- -(a+1) and a.

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Shriya Bhattacharya 7 years, 6 months ago

Is a+1 a part of the whole equation??

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Rishika Verma 7 years, 6 months ago

Plz someone answer it?

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Sir mara maths MA compartment Aya hai aur mara pass additional subject hai to ya replace ho Sakta hai

Posted by Swati Tripathi 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

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Sir mere maths mai comprment ai hai or mere pai additional subject hai to kya uskai number judaigai

Posted by Robin Singh 7 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Robin Singh 7 years, 6 months ago

Sir manai suna hai ki 33number karai pass kar dai gai

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Jitesh Kamboj 7 years, 6 months ago

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What is 2 multiplied by three

Posted by Nikhil Kumar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Ankita ?? Arpita☺️ 7 years, 6 months ago

2×3=6

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Abhinab Jain 7 years, 6 months ago

2#3=6 My child

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Susmita Mandal 7 years, 6 months ago

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What is the value of pie?

Posted by Raiyan Aziz 5 years, 8 months ago

CBSE > Class 10 > Mathematics

6 answers

Shiva Yadav Shiva Yadav 7 years, 6 months ago

The exact value of pie in between 22/7 and 3.14

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Manish Raj 7 years, 6 months ago

22/7

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Ankita ?? Arpita☺️ 7 years, 6 months ago

3.14or22/7

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Sachin Joshi 7 years, 6 months ago

The value of pie does not give us completely

1Thank You

Shriya Bhattacharya 7 years, 6 months ago

3.14 also

1Thank You

Sanjana Yadav 7 years, 6 months ago

22/7

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Sccfgb13566

Posted by Ashya Shamim 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sanjana Yadav 7 years, 6 months ago

What happens

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In triangle, angle B=90,ifAB=2cm and AC=3cm,than find all trigonometric ratio

Posted by Himanshu Kumar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Shriya Bhattacharya 7 years, 6 months ago

What Cc??

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Priyanshu Upadhyay 7 years, 6 months ago

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Shriya Bhattacharya 7 years, 6 months ago

After finding the side BC.....(root 5) Sin theta = 2/3 Cos theta = root 5/3 Tan theta = 2/root 5 Cot theta = root 5/2 Sec theta = 3/root 5 Cosec theta = 3/2

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Playing with number

Posted by Sanjay Das 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Khera 7 years, 6 months ago

Dont woery u are in merit list

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Find quadric equation ax2+dx+c

Posted by Ifra Siddiqui 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Koi easy trick nahi h exercise 3 ka

Posted by Priyanshu Kumar Singh 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Kannu Kranti Yadav 7 years, 6 months ago

Hey, have you changed your last name

1Thank You

Kannu Kranti Yadav 7 years, 6 months ago

Which chapter priyanshu

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Aryan Khera 7 years, 6 months ago

Konsi ch ki exercise

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5 year questions paper with solutions

Posted by Deepak Maitry 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Rupesh Kumar 7 years, 6 months ago

You can take out from internet

0Thank You

Priyanshu Upadhyay 7 years, 6 months ago

Zy.

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Shikayna Panday 7 years, 6 months ago

But how

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How to see our checked answers sheet of cbse class10 2018 online

Posted by Deepak Kumar 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Prove that _/2+/3 is irrational no

Posted by Khushi Patel 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 6 months ago

Please do itself Mai ise phone pe Nahi bata sakta. U know this is Too long

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A chemist has one solution which contains 50% acid and a second which contains 25% acid. How much of each should be mixed to make 10 litres of a 40% acid solution.

Posted by Ragul Sv 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Suppose x litres of 50% solution be mixed with y litres of 25% solution.
According to the question,
50% of x + 25% of y = 40% of 10
{tex}\Rightarrow \frac { 50 } { 100 } x + \frac { 25 } { 100 } y = \frac { 40 } { 100 } ( 10 ){/tex}
{tex}\Rightarrow{/tex} {tex}50x + 25y = 40(10){/tex}
{tex}\Rightarrow{/tex} {tex}2x + y = 16{/tex}..........(i)
The amount of each solution adds to {tex}10\ litres{/tex},
{tex}x + y = 10{/tex}.......(ii)
Subtract (ii) from (i),
{tex}\Rightarrow{/tex} {tex}x = 6{/tex}
Substituting {tex}x = 6{/tex} in (i), we get {tex}y = 4{/tex}
{tex}\therefore{/tex}{tex}6\ litres{/tex} of 50% solution is to be mixed with {tex}4\ litres{/tex} of 25% solution

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Find roots if 3x2+2x+3=0

Posted by Aman Bhatt 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have,
3x² + 2x + 3
Here, a = 3, b = 2 and c = 3
{tex}\therefore{/tex} {tex}D = b^2 - 4ac{/tex}
= (2)² - 4 {tex}\times 3 \times 3{/tex}
= 4 - 36
= 32 > 0
{tex}\therefore{/tex} D > 0
So, the given equation has real and distinct roots.

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Prove root 5 is irrational

Posted by Arjun Arjun 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Shriya Bhattacharya 7 years, 6 months ago

Let us assume that root 5 is rational. Let p and q be real number and co primes. Now, let p and q have another factor other than 1. Now, root 5 = p/q Root 5q= p.....................(i) (Squaring both side) Root 5q whole square = p square 5q square = p square P square is divisible by 5.. Hence, p is divisible by 5.. Let us take p = 5k where k is an integer From eq (i)... P = root 5q 5k = root 5 q (Squaring both side) 25k square = 5q 5k square = q square So, q square is divisible by 5 Hence, q is divisible by 5 Hence, p and q have other factors other than 1, that is 5... Hence our assumption is wrong that p and q are co primes... This contradicts the fact that root 5 is irrational. So, root 5 is irrational.. This sum is looking so lengthy but its actually not..???????

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If 7cossec - 3cot = 7 prove that 7cot - 3cossec =3 ?

Posted by Deepak Bhatt 7 years, 6 months ago

CBSE > Class 10 > Mathematics