Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Jas Noor 7 years, 5 months ago
- 1 answers
Posted by Kishan Kumar 7 years, 5 months ago
- 8 answers
Posted by Ajay Parihar 7 years, 5 months ago
- 1 answers
Posted by Anushalini Rajput 7 years, 5 months ago
- 2 answers
Posted by Aman Bedi 7 years, 5 months ago
- 1 answers
Janani Srinivasan 7 years, 5 months ago
Posted by Akhil Kodalapuram 7 years, 5 months ago
- 1 answers
Janani Srinivasan 7 years, 5 months ago
Posted by Sush Singh 7 years, 5 months ago
- 2 answers
Posted by Reema Kothari 7 years, 5 months ago
- 1 answers
Posted by Account Deleted 7 years, 5 months ago
- 1 answers
Posted by Sachidananda Mohanty 7 years, 5 months ago
- 1 answers
Posted by Sunny Pal 7 years, 5 months ago
- 0 answers
Posted by Manu Ka 7 years, 5 months ago
- 1 answers
Devashish Sharma 7 years, 5 months ago
Posted by Ayush Dubey 7 years, 5 months ago
- 0 answers
Posted by Rinda Maibam Maibam 7 years, 5 months ago
- 1 answers
Account Deleted 7 years, 5 months ago
Posted by Rma Narwal 7 years, 5 months ago
- 1 answers
Posted by Suraj Prasad Raj 7 years, 5 months ago
- 0 answers
Posted by Purnanand Pandey 7 years, 5 months ago
- 1 answers
Posted by Purnanand Pandey 7 years, 5 months ago
- 0 answers
Posted by Prashant Sharma 7 years, 5 months ago
- 7 answers
Shweta Yadav 7 years, 5 months ago
Posted by Md Vali Vali 7 years, 5 months ago
- 0 answers
Posted by Md Vali Vali 7 years, 5 months ago
- 0 answers
Posted by Durgesh Patle 7 years, 5 months ago
- 1 answers
Posted by Prakash Wareek 7 years, 5 months ago
- 2 answers
Posted by Nagesh Ms 7 years, 5 months ago
- 3 answers
Posted by Aditya Patel 7 years, 5 months ago
- 1 answers
Posted by Varenya Choksi 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
Let the cost price of a saree be Rs. x and the list price of a sweater be Rs. y.
We know that, Selling Price is given by :-{tex}S\cdot P\cdot=C\cdot P\cdot\left(1+\frac{profit\;percentage}{100}\right){/tex}
{tex}\Rightarrow{/tex} S.P. of saree at 8% profit = {tex}x(1+\frac8{100}){/tex}
{tex}= \left( {x + \frac{{8x}}{{100}}} \right) = \left( {\frac{{108x}}{{100}}} \right){/tex}
Also, Selling Price is given by :-
{tex}S.P.\;=\;L.P.(1-\frac{discount\;percentage}{100}){/tex}
{tex}\Rightarrow{/tex} S.P. of sweater at 10% discount {tex} = \left( {y - \frac{{10y}}{{100}}} \right) = \left( {\frac{{90y}}{{100}}} \right){/tex}
According to question,
{tex}\frac{{108x}}{{100}} + \frac{{90y}}{{100}} = 1008{/tex}
{tex}\Rightarrow{/tex} 108x + 90y = 100800 ...(i)
Now, S.P. of saree at 10% profit {tex}= \left( {x + \frac{{10x}}{{100}}} \right) = \left( {\frac{{110x}}{{100}}} \right){/tex}
S.P. of sweater at 8% discount {tex} = \left( {y - \frac{{8y}}{{100}}} \right) = \left( {\frac{{92y}}{{100}}} \right){/tex}
According to question,
{tex}\frac{{110x}}{{100}} + \frac{{92y}}{{100}} = 1028{/tex}
{tex}\Rightarrow{/tex} 110x + 92y = 102800 ...(ii)
Subtracting equation (i) from equation (ii), we get ;
(110x + 92y) -(108x + 90y)=102800 -100800.
{tex}\Rightarrow{/tex}2x + 2y = 2000
{tex}\Rightarrow{/tex} x + y = 1000
{tex}\Rightarrow{/tex} x = 1000 - y ...(iii)
Substituting x = 1000 - y from equation (iii) in equation (i), we get
108(1000 - y) + 90y = 100800
{tex}\Rightarrow{/tex} 108000 - 108y + 90y = 100800
{tex}\Rightarrow{/tex} -18y = -7200
{tex}\Rightarrow{/tex} y = 400
Putting value of y in equation (iii)
{tex}\Rightarrow{/tex} x = 1000 - 400 = 600
Thus, the cost price of saree is x = Rs.600
and the list price of sweater is y = Rs.400.
Posted by Vansh Dudani 7 years, 5 months ago
- 0 answers
Posted by Mayuri Hiremath 7 years, 5 months ago
- 1 answers
Posted by Pushp Verma 5 years, 8 months ago
- 1 answers
Sia ? 6 years, 6 months ago
Given, {tex}\left( x ^ { 2 } + y ^ { 2 } \right) \left( a ^ { 2 } + b ^ { 2 } \right) = ( a x + b y ) ^ { 2 }{/tex}
or,{tex}x ^ { 2 } a ^ { 2 } + x ^ { 2 } b ^ { 2 } + y ^ { 2 } a ^ { 2 } + y ^ { 2 } b ^ { 2 } = a ^ { 2 } x ^ { 2 } + b ^ { 2 } y ^ { 2 } + 2 a b x y{/tex}
or, {tex}x ^ { 2 } b ^ { 2 } + y ^ { 2 } a ^ { 2 } - 2 a b x y = 0{/tex}
or,{tex}( x b - y a ) ^ { 2 } = 0{/tex} {tex}\left[ \because ( a - b ) ^ { 2 } = a ^ { 2 } + b ^ { 2 } - 2 a b \right]{/tex}
or, xb = ya
{tex}\therefore \quad \frac { x } { a } = \frac { y } { b }{/tex} Hence Proved.
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Geetesh Rathore 7 years, 5 months ago
1Thank You