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Prabjeet Singh 7 years, 5 months ago
{tex}\text {Value of } \sqrt3 = 1.732... \text { and value of } \sqrt2 = 1.414...{/tex}
{tex}\text {Rational number between } \sqrt 3 \text { and } \sqrt 2 \text { is } \cfrac {3}{2} \text { or } 1.5{/tex}
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Sia ? 6 years, 6 months ago
6x2- x - 2 = 0
or, 6x2 + 3x - 4x - 2 = 0
or, 3x(2x + 1) -2(2x + 1) = 0
or, (2x + 1)(3x - 2) = 0
{tex}\Rightarrow{/tex} either 3x - 2 = 0 or 2x + 1 = 0
{tex}\therefore \quad x = \frac { 2 } { 3 } \text { or } x = - \frac { 1 } { 2 }{/tex}
Therefore, Roots of equation are {tex}\frac { 2 } { 3 } \text { and } - \frac { 1 } { 2 }{/tex}.
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Sia ? 6 years, 6 months ago
Here we have to find HCF of 1190 and 1445 and express the HCF in the form 1190m + 1445n.
1445 = 1190 × 1 + 255
1190 = 255 × 4 + 170
255 = 170 × 1 + 85
170 = 85 × 2 + 0
So, now the remainder is 0, then HCF is 85
Now,
85 = 255 - 170
= (1445 - 1190) - (1190 - 255 × 4)
= 1445 - 1190 - 1190 + 255 × 4
= 1445 - 1190 × 2 + (1445 - 1190) × 4
= 1445 - 1190 × 2 + 1445 × 4 - 1190 × 4
= 1445 × 5 - 1190 × 6
= 1190 × (- 6) + 1445 × 5
= 1190m + 1445n , where m = - 6 and n = 5
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Sia ? 6 years, 6 months ago
Whenever you are required to find a number that is divisible by more than one number, you have to find LCM.
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