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Ask QuestionPosted by Aman Singh 8 years, 4 months ago
- 1 answers
Posted by Khushi Joshi 8 years, 4 months ago
- 1 answers
Arpita Banerjee 8 years, 3 months ago
(a+b)2
= (a+b) (a+b)
=a(a+b) + b(a+b)
=a2 +ab +ab +b2
= a2 + 2ab +b2 = a2 +b2 + 2ab
Therefore,(a+b)2 = a2 +b2 + 2ab
Posted by Zaid Zaidi 8 years, 4 months ago
- 0 answers
Posted by Lavish Kumar 8 years, 4 months ago
- 1 answers
Arpita Banerjee 8 years, 3 months ago
In a triangle ABC ,X and Y are the points on AB and BC respectively such that AB =BC, if BX =½ ABand BY=½BC, show that BX =BY
In the triangle ABC,
BX = 1/2 AB ___________________[1]
BY = 1/2 BC ___________________[2]
Since AB = BC
[2] can be written as BY = 1/2 AB
So BY = 1/2 AB = BX
thus BY = BX
Posted by Aakash Chauhan 8 years, 4 months ago
- 2 answers
Posted by Lavish Kumar 8 years, 4 months ago
- 1 answers
Posted by Saurabh Kumar 8 years, 4 months ago
- 0 answers
Posted by Kartik Dangi 8 years, 4 months ago
- 0 answers
Posted by Shagun Sh 8 years, 4 months ago
- 2 answers
Sumit Kumar 8 years, 4 months ago
Posted by Abhishek Sisodiya 8 years, 4 months ago
- 0 answers
Posted by Rajnish Kumar 8 years, 4 months ago
- 1 answers
Posted by Harish Singla 8 years, 4 months ago
- 1 answers
Posted by Hrithik Jyani 8 years, 4 months ago
- 1 answers
Arpita Banerjee 8 years, 3 months ago
According to ASA congruence rule when two angles and included side of one triangle is equal to two angles and included side of another side they the two triangles are congruent.
But according to AAS, two angles and one side of a triangle are equal to two angles and one side of another triangle then they are congruent.
Both ASA and AAS are same as if two angles of one triangle are equal to two angles of another triangle then obviously the third angles will also be same.
Posted by Dipesh Kumar 8 years, 4 months ago
- 0 answers
Posted by Reena Karim 8 years, 4 months ago
- 2 answers
Payal Singh 8 years, 4 months ago
Given : x = {tex}3+\sqrt 2{/tex}
Then {tex}{1\over x} = {1\over 3+\sqrt 2}{/tex}= {tex}{1\over 3+ \sqrt 2}\times {3-\sqrt 2 \over 3-\sqrt 2 }{/tex}= {tex}3-\sqrt 2 \over 7{/tex}
To find : {tex}x +{1\over x}{/tex}
= {tex}3+\sqrt 2+{3-\sqrt 2 \over 7}{/tex}
{tex}={ 21+7\sqrt 2+ 3-\sqrt 2 \over 7}{/tex}
{tex}= {24-6\sqrt 2\over 7}{/tex}
Posted by Reena Karim 8 years, 4 months ago
- 1 answers
Payal Singh 8 years, 4 months ago
Given : {tex}x = \sqrt 2-\sqrt 3{/tex}
Then {tex}{1\over x} = {1\over \sqrt 2-\sqrt 3}{/tex}= {tex}{1\over \sqrt 2-\sqrt 3}\times {\sqrt 2+\sqrt 3\over \sqrt 2+\sqrt 3}{/tex}
= {tex}{\sqrt 2+\sqrt 3\over 2-3} ={\sqrt 2+\sqrt 3\over -1}{/tex}= {tex}-\sqrt 2-\sqrt 3{/tex}
To find : {tex}x+{1\over x}{/tex}= {tex}\sqrt 2-\sqrt 3-\sqrt 2-\sqrt 3=-2\sqrt 3{/tex}
Posted by Pranav Kumar 8 years, 4 months ago
- 0 answers
Posted by Pranav Kumar 8 years, 4 months ago
- 0 answers
Posted by Sahil Ujal 8 years, 4 months ago
- 1 answers
Posted by Surjeet Kumar 8 years, 4 months ago
- 4 answers
Mayakuntala Sheshadri 8 years, 4 months ago
Hans Raj 8 years, 4 months ago
(3 + {tex} \sqrt{3}{/tex})(3 - {tex} \sqrt{3}{/tex})
= 9 - 3{tex} \sqrt{3}{/tex} + 3{tex} \sqrt{3}{/tex} - 3
= 6
Sparsh Agarwal 8 years, 4 months ago
Posted by Karan Sethi 8 years, 4 months ago
- 1 answers
Posted by Shubham Sahare 8 years, 4 months ago
- 0 answers
Posted by Tarachand Gurjar 8 years, 4 months ago
- 1 answers
Posted by Ravi Singh 8 years, 4 months ago
- 3 answers
Sahdev Sharma 8 years, 3 months ago
Posted by Lovleen Brar 8 years, 4 months ago
- 2 answers
Lovleen Brar 8 years, 4 months ago
Sahdev Sharma 8 years, 4 months ago
- Distance is a numerical description of how far apart objects are. In physics, distance may refer to a physical length or estimation based on other criteria. In mathematics, a distance function or metric is a generalization of the concept of physical distance.
- Length most commonly refers to the longest dimension of an object. Length may be distinguished from height, which is vertical extent, and width or breath, which is the distance from side to side, measuring across the object at the right angles to the length.
Posted by Mayank Kumari 8 years, 4 months ago
- 3 answers
Posted by Manon Ranjan Srivastava 8 years, 4 months ago
- 1 answers
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Apurva Gaurav 8 years, 4 months ago
1Thank You