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Find the area of field

Posted by Ajeet Singh 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 3 years ago

To find the area of a rectangle, multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area. This is the same as saying length2 or length squared.

ANSWER

420√5×2/35

Posted by Aarzoo Preet Kaur 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Laya Varshini.P ... 3 years ago

224.49

ANSWER

What is a maths

Posted by Hamsa J Buddiyavar 3 years ago

CBSE > Class 09 > Mathematics

2 answers

Bhagya Singla 3 years ago

Maths is everday life.

Ajeet Singh 3 years ago

What is math

ANSWER

2root 3 +root 3 is equals to what

Posted by Siya Siya 3 years ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 3 years ago

The expression is given to be : 2√3 + √3

We need to simplify this given expression and find the value of this expression.

The expression is : 2√3 + √3

Since, √3 is common factor in both the terms so taking √3 common we have,

⇒ √3 × (2 + 1)

Now using BODMAS rule we will simplify the bracket first

⇒ √3 × 3

⇒ 3√3

The approximate value of √3 correct to three places of decimal is 1.732

So, the value of the given expression is : 3 × 1.732 = 5.196

Sweety Yadav 2 years, 11 months ago

3root 3

ANSWER

in the given figure ab is parallel to cd .if angle oab is 124 degrees and ocd is 136 degrees .then aoc

Posted by Anu Anu 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Ishan Agarwal 3 years ago

100 degree

ANSWER

If x=2^1/3 + 2^2/3 show that x^3-6x=6

Posted by Titi Karmi 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 3 years ago

x = {tex}2^{1 / 3}+2^{2 / 3}{/tex}
x³ = {tex}\left(2^{1 / 3}+2^{2 / 3}\right)^{3}{/tex}
{tex}\Rightarrow{/tex} x³ = {tex}\left(2^{1 / 3}\right)^{3}{/tex} + {tex}\left(2^{2 / 3}\right)^{3}{/tex} + 3 {tex}\times{/tex} {tex}2^{1 / 3}{/tex} {tex}\times{/tex} {tex}2^{2 / 3}{/tex}{tex}\left(2^{1 / 3}+2^{2 / 3}\right){/tex}
{tex}\Rightarrow{/tex} x³ = 2 + 2² + 3 {tex}\times{/tex} 2{tex}\left(2^{1 / 3}+2^{2 / 3}\right.){/tex}
{tex}\Rightarrow{/tex} x³ = 6 + 6{tex}\left(2^{1 / 3}+2^{2 / 3}\right.){/tex}
{tex}\Rightarrow{/tex} x³ = 6 + 6x
{tex}\Rightarrow{/tex} x³ - 6x = 6

ANSWER

If 4 is the means of the observation x1,X2,x3.............X10 then the value of 10Sigma angle 1 (x-4) is equal to

Posted by Anamika Kumari Meena 3 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

What is the measure of straight angle?

Posted by Sunil Rathi 3 years ago

CBSE > Class 09 > Mathematics

5 answers

Shreya Jaiswal 3 years ago

180

I͓̽T͓̽S͓̽ M͓̽E͓̽ 3 years ago

180 degrees

Nikhil Reddy 3 years ago

180

Kunal Tiwari 3 years ago

The measure of straight angle is always 180 degree

Anjum Munir 3 years ago

180 degree

ANSWER

In this figure PQ and RS intersect each other at point 0.if x:y =5:7, find x, y, z and w

Posted by Tanu Baghel 3 years ago

CBSE > Class 09 > Mathematics

2 answers

Kunal Tiwari 3 years ago

5x + 7x = 180

Preet Chechani 3 years ago

Pata nahi ha

ANSWER

2x=36

Posted by Anita Pujar 3 years ago

CBSE > Class 09 > Mathematics

5 answers

Sunil Rathi 3 years ago

2x=36 Ans- x =36÷2=18 x = 18.

Preet Chechani 3 years ago

X=18

Kamal Kumar 3 years ago

X=18

Ravi Shankar 3 years ago

a2+2a+2x(2÷4)

Chaithanya Kumar 8Th Class 3 years ago

x = 18

ANSWER

A field is in the shape of a Trapezium whose parallel sides are 25m and 10m the non parallel sides are 14 and 13 find the area of the field

Posted by Nira Verma 3 years ago

CBSE > Class 09 > Mathematics

3 answers

Vinay Dhanuka 3 years ago

196 m s^2

Shreya Chawla 3 years ago

Given: AB || CD AB = 25m CD = 10m BC = 14m AD = 13m From point C draw CE || DA. Hence ADCE is a llgrm having CD II AE & ADIICE AE= CD= 10m CE= AD = 13m BE= AB- AE =25-10-15 m BE= 15m In ABCE BC= 14m, CE= 13m, BE = 15rr Semiperimeter (s) = (a + b + c) / 2 Semiperimeter * (s) = (14 + 13 + 15) / 2 s= 42/2= 21m s = 21m Area of ABCE=√ s(s-a)(s-b)(s-c) Area of ABCE=√ 21(21-14)(21-13)(21-15) Area of ABCE=√ 21x7x 8×6 Area of ABCE= √ 7×3× 7×2 4×2×2×3 Area of ABCE=√7×7×3×3×2×2×4 Area of ABCE= 7×3×2×2= 21x 4= 84m² Area of ABCE= 84m² Area of ABCE=√ 7×3× 7× 4×2×2×3 Area of ABCE=√7x7×3×3×2×2×4 Area of ABCE= 7×3×2×2= 21x 4= 84m² Area of BCE = 84m ^ 2 Area of Delta*B * C * E = 1/2 * b * a × altitude Area of Delta*B * C * E = 1/2 * B * E * C * L 84 = 1/2 * 15 * C * l 84 * 2 = 15CL 168 = 15CL CL = 168/15 CL = 56/5 * m Height of trapezium= 56/ 5m Area of trapezium= 1/2( sum of Il sides) (height) Area of trapezium=1/2(25+10)(56/5) Area of trapezium= 1/2(35)(56/5) Area of trapezium= 7x28=196m² Hence the area of field is 196m²

Jiya Kumari 3 years ago

Area of the field is 196m^2

ANSWER

A rhombus shaped field has green grass for 18 cows to graze if each side of the Rhombus is 30 and its longer diagonal is 48 how much area of grass field will eat cow be getting

Posted by Nira Verma 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Shreya Chawla 3 years ago

We will divide the given rhombus into two triangles, and by using Heron’s formula, we can calculate the area of triangles. Heron formula for the area of a triangle = √s(s - a)(s - b)(s - c) Where a, b and c are the sides of the triangle, and s = Semi-perimeter = Half the Perimeter of the triangle = (a + b + c)/2 A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting Let the longer diagonal AC divides the rhombus ABCD into two congruent triangles. For ∆ABC, a = b = 30 m, c = 48 m And Semi Perimeter(s) = (a + b + c)/2 s = (30 + 30 + 48)/2 s = 108/2 s = 54 m By using Heron’s formula, Area of ΔABC = √s(s - a)(s - b)(s - c) = √54(54 - 30)(54 - 30)(54 - 48) = √54 × 24 × 24 × 6 Area of ΔABC = 432 m2 Area of rhombus = 2 × Area of a ΔABC = 2 × 432 m2 = 864 m2 Since, number of cows = 18 The area of grass field will each cow get = (Total area of the rhombus) / 18 = 864 m2/18 = 48 m2 Thus, each cow will be getting a 48 m2 area of the grass field.

ANSWER

Findthe area of rectangle ABCD in cordinate geometry

Posted by Pavni Chhabra 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Ayush Kumar 3 years ago

L x b

ANSWER

If the point (5,3) lies on the graph of equation 6y=ax + 3 then find the value of a

Posted by Tanish Rawal 3 years ago

CBSE > Class 09 > Mathematics

3 answers

Kamal Kumar 3 years ago

A=3

Ayush Kumar 3 years ago

5

Trisha Kashyap 3 years ago

x=5 and y=3 => 6 x 3 =a x 5 + 3 => 18=5a+3 => 5a =18 - 3 => 5a =15 .•. a = 3

ANSWER

If access and why our lady appear and toys of X is 30 less than Y then find the value of x and y

Posted by Ashok Upadhyay 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Ashwani Kumar 3 years ago

Can you type the question right (again).

ANSWER

If triangle ABC is similar to triangle DEF such that 3AB=DE and BC=9cm than EF is equal to

Posted by Avantika Shrivastava 3 years ago

CBSE > Class 09 > Mathematics

2 answers

Chaithanya Kumar 8Th Class 3 years ago

27

Neha Kanchan 3 years ago

EF=BC=9cm

ANSWER

Anyone have CBSE class 9 old questions paper

Posted by Virendra Patil 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Annabelle ✨ 3 years ago

Yes I've of term I and of my school

ANSWER

part 2 13.1

Posted by Khalid Shaik Khalid 3 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

(√6-√5) (√3+√2)

Posted by Jinali Jain 3 years ago

CBSE > Class 09 > Mathematics

3 answers

Ananya Mishra 2 years, 11 months ago

√5

Brahmchari Yadav 3 years ago

(/6-/)(/3+/2(

Abhishek Mishra 3 years ago

√5

ANSWER

Vast app because some question automatically answer change of test mcq

Posted by Shourya Mishra 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Shivam Kumar Prajapati 3 years ago

Sk g

ANSWER

Thank you for this wonderful app ❤️ I haven't seen this type of app ❤️? I love this app ❤️❤️? nice app for all subjects but computer is not their

Posted by Manthan Raut 3 years ago

CBSE > Class 09 > Mathematics

2 answers

Neil :) 3 years ago

Information technology is there I guess I have also taken IT❤️

Neil :) 3 years ago

Yes , wonderful platform❤️❤️

ANSWER

IN A TRAINGLE ABC ,IF ∠A+ ∠B = 50 & ∠B - ∠C = 40, THEN ∠B = _____

Posted by Madhura Kori 3 years ago

CBSE > Class 09 > Mathematics

4 answers

Prince Mishra 3 years ago

90

Sonu Kumari 3 years ago

90

Soncy Sharma 3 years ago

90

Anil Tikyani 3 years ago

90

ANSWER

On simplifying 4 root 3root 3 square

Posted by Kim Nelina 3 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

if x-1/x=2/3 then find the value of x⁴-1/x⁴

Posted by Oorja Jain 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Chaithanya Kumar 8Th Class 3 years ago

80/81

ANSWER

The graph of which of the following equation does not pass through the origin?

Posted by Anjum Munir 3 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

write the p/q form of 0.01

Posted by Moksha Shetty 3 years ago

CBSE > Class 09 > Mathematics

5 answers

Monica ✨☄️ 3 years ago

1 100-¹?

Piyush Raj 3 years ago

1/100

Ansh Kumar 3 years ago

1/10

Divyanshi Prajapati 3 years ago

1 100

Divyanshi Prajapati 3 years ago

1 10

ANSWER

the length of the three sides of a triangular field are 40 m 24 mand 32m respectively the area of the triangle is

Posted by Samira Ali 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Pratik Kumar 3 years ago

576sq.m

ANSWER

Check whether the equation (x-5)x+6y-y2=0 is an equation of the form ax+by+c=0 or not.

Posted by ●⃝Bʜᴀsᴋᴀʀ ⚡ 3 years ago

CBSE > Class 09 > Mathematics

1 answers

Chaithanya Kumar 8Th Class 3 years ago

No

ANSWER

The rational number between 1/7 and 2/7

Posted by Adarsh M Patil Patil 3 years ago

CBSE > Class 09 > Mathematics

3 answers

Anil Tikyani 3 years ago

3/14

Mahesh Kumar 3 years ago

3/14

Saniya Garg 3 years ago

3/14

ANSWER

Write each of the following as an equation in two variables x and y A) x= -3

Posted by Niyati Singh 3 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

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