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Amar Kumar 8 years, 6 months ago
The midpoint theorem states that: In a triangle, the line segment that joins the midpoints of the two sides of a triangle is parallel to the third side and is half of it.
Let us consider ABC is a triangle as shown in the following figure:
Mid Point Theorem
Let D and E be the midpoints of AB and AC. Then line DE is parallel to BC and DE is half of BC;
i.e. DE ∥ BC
DE = 1/2 BC
The converse of midpoint theorem states that: If a line segment is drawn passing through the midpoint of any one side of a triangle and parallel to another side, then this line segment bisects the remaining third side.
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Anjali Sharma 8 years, 6 months ago
Complementary angle are pair of angles whose sum is 90o
let an angle x
ATQ complementary is also x
x + x = 90
2x = 90
x = 45o
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Hans Raj 8 years, 6 months ago
let ABC a right ld triangle rt ld at B and side AB = BC=a
Area=1/2 x ABXBC = 1/2Xa2 = 200
a= root 400 = 20 cm
AC2 = a2+a2
= 400 + 400 = 800
AC=root 800 = 20root2
perimeter = AB+BC+AC = 20+20+20root2
= 20 x 2 root2 cm
= 20 x 2{tex} \sqrt2{/tex} cm
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Manisha Raghuwanshi 8 years, 6 months ago
1Thank You