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Posted by Eldin Santhosh 8 years, 5 months ago
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Shreya Ghosh 8 years, 5 months ago
It is possible. We can construct a triangle if it satisfy the below condition:
a+b>c
Posted by Manish Soni 8 years, 5 months ago
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Posted by Abhishek Gautam 8 years, 5 months ago
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Posted by Preeti Patil 8 years, 5 months ago
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Posted by Kashish Harjai 8 years, 5 months ago
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Posted by Anurag Sharma 8 years, 5 months ago
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Posted by Sunita Kumari 8 years, 5 months ago
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Posted by Amit Yadav 8 years, 5 months ago
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Posted by Srishti Gupta 8 years, 5 months ago
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Posted by Himanshu Choudhary 8 years, 5 months ago
- 3 answers
Veda Prakash Madhukalya 8 years, 5 months ago
Posted by Rohit Tiwari 8 years, 5 months ago
- 2 answers
Shubham S 8 years, 5 months ago
Posted by Sahil Varshney 8 years, 6 months ago
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Posted by Vanshikha Upadhyay 8 years, 6 months ago
- 2 answers
Harshavardhan Shinde 8 years, 6 months ago
Construction : Join A to E and B to E.
Proof :
i) In ΔADE and ΔBCE,
AD = BC (given)
∠ADE = ∠BCE (90° + 60°)
DE = CE (given)
Therefore, ΔADE is congruent to ΔBCE ( SAS rule)
AE = BE (CPCTC)
ii) ∠DAE + ∠ADE + ∠DEA = 180°
150° + ∠DAE + ∠DEA = 180°
∠DAE + ∠DEA = 180° -150°
2 ∠DAE = 30°
∠DAE = 15°
Hence Proved.
Harshavardhan Shinde 8 years, 6 months ago
∠DAE + ∠ADE + ∠DEA = 180°
150° + ∠DAE + ∠DEA = 180°
∠DAE + ∠DEA = 180° -150°
2 ∠DAE = 30°
∠DAE = 15°
Hence Proved.
Posted by Soumy Rai 8 years, 6 months ago
- 3 answers
Posted by Lavish Tomar 8 years, 6 months ago
- 1 answers
Posted by Nazmeen Mushtaque 8 years, 6 months ago
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Shreya Kesharwani 8 years, 6 months ago
Amar Kumar 8 years, 6 months ago
Coordinates of point will be (x,0) because line cuts x axis so y Coordinate is zero
2x+3x0=6
x=3
so point is (3,0)
Posted by Ratnadip Das 8 years, 6 months ago
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Posted by Vinayak Vijay 8 years, 6 months ago
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Posted by Sheldon Rodrigues 8 years, 6 months ago
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Posted by Game User 8 years, 6 months ago
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Amar Kumar 8 years, 6 months ago
{tex}\eqalign{ & Given\,that\,:ABC\,is\,a\,triangle\,\,in\,which\, \cr & AB = AC \cr & \angle ABC = \angle ACB\,\,\,\,\,\,\,(1) \cr & AB = AD \cr & join\,\,CD \cr & In\,\,\Delta ACD \cr & AC = AD \cr & \angle ACD = \angle ADC\,\,\,\,(2) \cr & In\,\,\Delta BCD\,from\,eq.\,\,(1)\,\,and\,\,(2) \cr} {/tex}
{tex}\eqalign{ & \angle DBC = \,\angle BDC \cr & \angle DBC + \angle BDC + \angle BCD = 180^\circ \cr & 2\angle BDC + \angle BCD = 180^\circ \cr & 2\angle BDC = \angle BCD \cr & 4\angle BDC = 180^\circ \cr & \angle BDC = 45^\circ \cr & \angle DBC = 45^\circ \cr & So\,\,\angle BCD = 90^\circ \cr}{/tex}
Posted by Madhav Bhopal 8 years, 6 months ago
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Posted by Prince Patel 8 years, 6 months ago
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Posted by Manisha Raghuwanshi 8 years, 6 months ago
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Amar Kumar 8 years, 6 months ago
Cartesian coordinate system :It is a coordinate system that specifies each point uniquely in a plane by a pair of numerical coordinates, which are the signed distances to the point from two fixed perpendicular directed lines, measured in the same unit of length.
Illustration of a Cartesian coordinate plane. Four points are marked and labeled with their coordinates: (2, 3) in green, (−3, 1) in red, (−1.5, −2.5) in blue, and the origin (0, 0) in purple.
Posted by Sneha Mahto 8 years, 6 months ago
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Posted by Rising Angel 8 years, 6 months ago
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Shubham S 8 years, 6 months ago
Posted by Arshiya Bano Adana 8 years, 6 months ago
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Posted by Shraddha Varshney 8 years, 6 months ago
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