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  • 2 answers

Shyam Jaat 7 years, 10 months ago

Sahi baat h

Prashant Chaudhary 7 years, 10 months ago

Bhai question toh pura likha Karo
  • 1 answers

Shyam Jaat 7 years, 10 months ago

₹79.09
  • 1 answers

Ankit Kaushik 7 years, 10 months ago

Theoram 10.7 says that chords of circles are equidistant from the centre of the circle are both equal to length. For more sure see example 2 pg 178 it gives some guide to solve 10.7 theorem based questions.
  • 2 answers

Shyam Jaat 7 years, 10 months ago

(n/2) and (n/2+1)

Gurkomal Kaur 7 years, 10 months ago

((N/2)^th term+(N/2+1/1)^th term)/2
  • 1 answers

Abhishek Sangwan 7 years, 10 months ago

See in your book
  • 1 answers

Ishita Tiwari 7 years, 10 months ago

Kya likho aap
  • 2 answers

Khushi Delio 7 years, 10 months ago

3178/10000

Sadaf Fatima 7 years, 10 months ago

3178/10000
  • 1 answers

Aditya Dutta 7 years, 10 months ago

44
  • 0 answers
  • 1 answers

Gurkomal Kaur 7 years, 10 months ago

His hat hid every inch of his face
  • 1 answers

Gurkomal Kaur 7 years, 10 months ago

ph=So
  • 1 answers

Khushi Delio 7 years, 10 months ago

15/2 or 7.5
  • 1 answers

Osama Khan 7 years, 10 months ago

When the four vertices of quadrilateral lies on the circumference(ineer circumference) of the circle then that quadrilateral is called cyclic quadrilateral
  • 2 answers

Diksha Arora 7 years, 10 months ago

By using the mid points of histogram

Arohi Chaudhary 7 years, 10 months ago

Hello
  • 1 answers

Khushi Delio 7 years, 10 months ago

Not possible on this app
  • 1 answers

Shivam Sahu 7 years, 10 months ago

Pier1sq. - pier2sq.
  • 1 answers

Chandrashekhar Wankhede 7 years, 10 months ago

Let perpendicular height is PS, Draw PS = 12.5 CM horizontally. Construct 90 degree at point S. Extend vertical arm of angle at S on opposite side. Construct 30 degree at point P and allow it to intersect with vertical arm of angle at S. This intersection point will be Q. Similarly construct 60 degree at point P below PS line and allow it to intersect with vertical arm of angle at point S.This intersection point will be R.
  • 1 answers

Chandrashekhar Wankhede 7 years, 10 months ago

Let triangle is PQR and PQ = PR = 5.5cm and angle PQR is 120 degree. First draw PQ = 5.5 cm, at point Q construct 120 which is Obtuse angle. Then mark a point At a distance of 5.5 on arm of angle at point Q other than PQ. This point will be R. Join PR to complete triangle..

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