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Posted by Mohd Kashan 7 years, 5 months ago
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Posted by Arjun Mishra 7 years, 5 months ago
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Yogita Ingle 7 years, 5 months ago
Given √2 is irrational number.
Let √2 = a / b wher a,b are integers b ≠ 0
we also suppose that a / b is written in the simplest form
Now √2 = a / b
⇒ 2 = a2 / b2
⇒ 2b2 = a2
∴ 2b2 is divisible by 2
⇒ a2 is divisible by 2
⇒ a is divisible by 2
∴ let a = 2c
a2 = 4c2
⇒ 2b2 = 4c2
⇒ b2 = 2c2
∴ 2c2 is divisible by 2
∴ b2 is divisible by 2
∴ b is divisible by 2
∴ a are b are divisible by 2 .
This contradicts our supposition that a/b is written in the simplest form
Hence our supposition is wrong
∴ √2 is irrational number.
Posted by Priyanshu Birhman 7 years, 5 months ago
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Tanishka Hira 7 years, 5 months ago
step 2: secondly tell that the difference of two irrationals are irrational.
Posted by Adish Khatak 7 years, 5 months ago
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Vikash Kumar 7 years, 5 months ago
Posted by Harsh Gupta 7 years, 5 months ago
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Posted by Gowri P 7 years, 5 months ago
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Rajnish Kumar 7 years, 5 months ago
root 2 divided by 3root2 - 2root3 = by rationalising the denominator we get
root 2 x (3root2+2root3)/(3root2-2root3)x(3root2+2root3)
(root2x3root2)+(root2x2root3)/(3root2)2-(2root3)2
3x2+2root6/18-12
6+2root6/6
Posted by Mohit Rana 7 years, 5 months ago
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Vikash Kumar 7 years, 5 months ago
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