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Prabjeet Singh 7 years, 5 months ago
Here, AB is a straight line and ray OC stands on line AB, such that {tex}\Delta AOC \cong \Delta COB.{/tex}
By c.p.c.t, {tex}\angle AOC=\angle COB{/tex}
Now, {tex}\angle AOC+\angle COB=180^{\circ} (\because \text {linear pair}){/tex}
{tex}\Rightarrow \angle AOC + \angle AOC = 180^{\circ}{/tex}
{tex}\Rightarrow 2\angle AOC=180^{\circ}{/tex}
{tex}\Rightarrow\angle AOC = \cfrac{180^{\circ}}{2}{/tex}
{tex}\Rightarrow \angle AOC = 90^ {\circ}{/tex}
Proved
Posted by Rohan Krishna 7 years, 5 months ago
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Prabjeet Singh 7 years, 5 months ago
{tex}x^{\circ} = 1{/tex}
Because, anything raise to the power of 0 is always 1.
Prabjeet Singh 7 years, 5 months ago
{tex}x^0 = 1{/tex}
{tex}\text {anything raise to the power something is always 1}{/tex}
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Raj Rath 7 years, 5 months ago
0Thank You