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Posted by Nishant Yadav 1 year, 9 months ago

CBSE > Class 09 > Mathematics

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Give me extra questions of ch 13 maths

Posted by Shreya Pandey 1 year, 10 months ago

CBSE > Class 09 > Mathematics

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An isosceles triangle has the perimeter is 42cm and the third side is 10cm. Find the perimeter of the triangle

Posted by Naman Jee Kale 1 year, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Dhananjay Patil 1 year, 10 months ago

Perimeter of triangle is 42 cm

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Simplify (5(8¹/²+27¹/²)³)¼

Posted by Anand Parkash 1 year, 10 months ago

CBSE > Class 09 > Mathematics

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Himanshu Tiwari 1 year, 10 months ago

Answer=5

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Theorem 10.8 of circles

Posted by Prachi Bohra 1 year, 10 months ago

CBSE > Class 09 > Mathematics

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Preeti Dabral 1 year, 10 months ago

Theorem 10.8 The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle. Given : A circle with center at O. Arc PQ of this circle subtends angles POQ at centre O & ∠ PAQ at a point A remaining part of circle.

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Find the area of the triangle whose base measures 24cm and the corresponding height measures 14.5cm

Posted by Vasti Darlong 1 year, 10 months ago

CBSE > Class 09 > Mathematics

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Preeti Dabral 1 year, 10 months ago

Area of given triangle ={tex}\frac { 1 } { 2 } \times \text { Base } \times \text{height}{/tex}
{tex}= \left( \frac { 1 } { 2 } \times 24 \times 14.5 \right) \mathrm { cm } ^ { 2 } = 174 \mathrm { cm } ^ { 2 }{/tex}

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What is calculated triangle ? Write it's criteria?

Posted by Shilpa Das 1 year, 10 months ago

CBSE > Class 09 > Mathematics

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Srishti Gupta 1 year, 9 months ago

Criteria are ASA SSS RHS AAS SAS

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State and prove degree measure theorem

Posted by Avni Rajput 1 year, 10 months ago

CBSE > Class 09 > Mathematics

3 answers

Prachi Bohra 1 year, 10 months ago

This is theorem 10.8 of circles

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Prachi Bohra 1 year, 10 months ago

Proof : There will be three cases as (i) PQ⌢is a minor arc (ii)PQ⌢ is a semi-circle (iii)PQ⌢ is a major arc [Image Here ] In each of these three cases, the exterior angle of a triangle is equal to the sum of two interior opposite angles. Therefore, ∠POM=∠PRO+∠RPO ............ (1) ∠MOQ=∠ORQ+∠RQO.......... (2) In △OPR and △OQR Now, OP = OR and OR = OQ (radii of the same circle) ∠PRO=∠RPO and ∠ORQ=∠RQO (angles opposite to the equal sides are equal) Hence, ∠POM=2∠PRO .......... (3) And ∠MOQ=2∠ORQ ............ (4) Case (1) : adding equations (3) and (4) we get ∠POM+∠MOQ=2∠PRO+2∠ORQ ∠POQ=2(∠PRO+∠ORQ)=2∠PRQ ∠POQ=2∠PRQ Hence Proved.

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Prachi Bohra 1 year, 10 months ago

Degree Measure Theorem states that angle subtended by an arc of a circle at the centre is twice the angle subtended by it at any point on the circle

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(5^-1 x 7^2/5^2 x 7^-4)^7/2 x (5^-2 x 7^3/5^3 x 7^-5)^-5/2

Posted by Abhikriti Rani 1 year, 10 months ago

CBSE > Class 09 > Mathematics