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Posted by Nishant Yadav 2 years ago

CBSE > Class 09 > Mathematics

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Give me extra questions of ch 13 maths

Posted by Shreya Pandey 2 years, 1 month ago

CBSE > Class 09 > Mathematics

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An isosceles triangle has the perimeter is 42cm and the third side is 10cm. Find the perimeter of the triangle

Posted by Naman Jee Kale 2 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Dhananjay Patil 2 years, 1 month ago

Perimeter of triangle is 42 cm

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Simplify (5(8¹/²+27¹/²)³)¼

Posted by Anand Parkash 2 years, 1 month ago

CBSE > Class 09 > Mathematics

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Himanshu Tiwari 2 years, 1 month ago

Answer=5

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Theorem 10.8 of circles

Posted by Prachi Bohra 2 years, 1 month ago

CBSE > Class 09 > Mathematics

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Preeti Dabral 2 years, 1 month ago

Theorem 10.8 The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle. Given : A circle with center at O. Arc PQ of this circle subtends angles POQ at centre O & ∠ PAQ at a point A remaining part of circle.

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Find the area of the triangle whose base measures 24cm and the corresponding height measures 14.5cm

Posted by Vasti Darlong 2 years, 1 month ago

CBSE > Class 09 > Mathematics

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Preeti Dabral 2 years, 1 month ago

Area of given triangle ={tex}\frac { 1 } { 2 } \times \text { Base } \times \text{height}{/tex}
{tex}= \left( \frac { 1 } { 2 } \times 24 \times 14.5 \right) \mathrm { cm } ^ { 2 } = 174 \mathrm { cm } ^ { 2 }{/tex}

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What is calculated triangle ? Write it's criteria?

Posted by Shilpa Das 2 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Srishti Gupta 2 years, 1 month ago

Criteria are ASA SSS RHS AAS SAS

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State and prove degree measure theorem

Posted by Avni Rajput 2 years, 1 month ago

CBSE > Class 09 > Mathematics

3 answers

Prachi Bohra 2 years, 1 month ago

This is theorem 10.8 of circles

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Prachi Bohra 2 years, 1 month ago

Proof : There will be three cases as (i) PQ⌢is a minor arc (ii)PQ⌢ is a semi-circle (iii)PQ⌢ is a major arc [Image Here ] In each of these three cases, the exterior angle of a triangle is equal to the sum of two interior opposite angles. Therefore, ∠POM=∠PRO+∠RPO ............ (1) ∠MOQ=∠ORQ+∠RQO.......... (2) In △OPR and △OQR Now, OP = OR and OR = OQ (radii of the same circle) ∠PRO=∠RPO and ∠ORQ=∠RQO (angles opposite to the equal sides are equal) Hence, ∠POM=2∠PRO .......... (3) And ∠MOQ=2∠ORQ ............ (4) Case (1) : adding equations (3) and (4) we get ∠POM+∠MOQ=2∠PRO+2∠ORQ ∠POQ=2(∠PRO+∠ORQ)=2∠PRQ ∠POQ=2∠PRQ Hence Proved.

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Prachi Bohra 2 years, 1 month ago

Degree Measure Theorem states that angle subtended by an arc of a circle at the centre is twice the angle subtended by it at any point on the circle

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(5^-1 x 7^2/5^2 x 7^-4)^7/2 x (5^-2 x 7^3/5^3 x 7^-5)^-5/2

Posted by Abhikriti Rani 2 years, 1 month ago

CBSE > Class 09 > Mathematics