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Yogita Ingle 6 years, 4 months ago
For an equilateral triangle, we know that all 3 sides of the triangle are equal. Accordingly, all the 3 sides of the equilateral triangle hold equal angles.
Since, we know, that the sum of all angles of any triangle be 180°.
Let each angle be a.
Thus, {tex}a+a+a=180^{\circ}{/tex}
{tex}\begin{array}{l}{\Rightarrow \quad 3 a=180^{\circ}} \\ {\Rightarrow a=\frac{180^{\circ}}{3}} \\ {\Rightarrow a=60^{\circ}}\end{array}{/tex}
Hence, we can show that all the 3 angles of an equilateral triangle hold equal angles; i.e. 60°.
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Sia ? 6 years, 4 months ago
→ x = 164/99
Step-by-step explanation:
0.38 + 1.27 = 1.65(bar on 65)
Let,
x = 1.656565 __(1)
Multiply with 100
100x = 165.6565 __(2)
Now,
Equation (2) - Equation (1)
we get,
99 x = 164
x = 164/99
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Sia ? 6 years, 4 months ago
Let the age of father is x years and that of son is y years.
Then by the given question,
Two years ago father was five times as old as his son
{tex}x-2=5(y-2){/tex}
or, {tex}x-5y=-10+2{/tex}
or, {tex}x-5y=-8{/tex}
or, {tex}x=5y-8{/tex}
Two years later, his age will be 8 years more than three times the age of the son
{tex}x+2=3(y+2)+8{/tex}
or, {tex}x-3y=6+8-2{/tex}
or, {tex}5y-8-3y=12{/tex}
or, {tex}2y=12+8{/tex}
or, {tex}y=\frac{20}{2}{/tex}
or, {tex}y=10{/tex}
then x=5y-8=50-8=42
Then, the age of father is 42 yrs. and the age of son is 10 yrs.
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