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Sia ? 5 years, 7 months ago
We have, x2+1x2=34
Also,
⇒(x+1x)2=x2+1x2+2x2×1x2
⇒(x+1x)2=34+2
⇒ n+1n=√36=6
Now,
⇒(x+1x)3=x3+1x3+3x×1x(x+1x)
⇒63=x3+1x3+3×6
⇒x3+1x3= 216 - 18
x3+1x3−9= 216 - 18 - 9
= 216 - 27
=189
Posted by Shivraj Patil 5 years, 7 months ago
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Sia ? 5 years, 7 months ago
Given: A quadrilateral ABCD.
To prove: AB + BC + CD + DA > AC + BD
Proof: In ΔABC, we have
AB + BC > AC…(1) [∵ Sum of the lengths of any two sides of a triangle must be greater than the third side]
In ΔBCD, we have
BC + CD > BD...(2) [Same reason]
In ΔCDA, we have
CD + DA > AC…(3) [Same reason]
In ΔDAB, we have
AD + AB > BD…(4) [Same reason]
Adding (1), (2), (3) and (4), we get
AB + BC + BC + CD + CD + DA + AD + AB > AC + BD + AC + BD
⇒ 2AB + 2BC + 2CD + 2DA > 2AC + 2BD
⇒ 2(AB + BC + CD + DA) > 2(AC + BD)
⇒ AB + BC + CD + DA > AC + BD
Hence, proved.
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Gaurav Seth 5 years, 7 months ago
Question: In a ∆ABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find the area of ∆ABC and hence its altitude on AC.
Answer
The triangle sides are
Let a = AB = 15 cm, BC = 13 cm = b, c = AC = 14 cm say
Now,
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Badal Sahu 5 years, 6 months ago
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