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Ask QuestionPosted by Adarsh Agarwal 6 years, 3 months ago
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Posted by Aman Deep 6 years, 3 months ago
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Gaurav Seth 6 years, 3 months ago
or
Given,
Side a=18cm
Side b=10cm
Perimeter=42cm=a+b+c
:. Putting value
42=18+10+c
42=28+c
42-28=c
14=c
Now,
S=(a+b+c)/2
:. Putting value
S=42/2
S=21
Now according to Heron's formula-
Area of a triangle
=√{s(s-a)(s-b)(s-c)}
:. Putting value
=√{21(21-18)(21-10)(21-14)}
=√{21(3)(11)(7)}
=√4851
=21√11cm²
Posted by Aman Deep 6 years, 3 months ago
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Posted by Diya Lalwani 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
Given: PQ = PR
To prove: PS > PQ
Proof: In {tex}\triangle{/tex}PRQ, we have
PR = PQ [Given]
{tex}\Rightarrow \;\angle 1 = \angle R{/tex}
[{tex}\therefore{/tex} Angles opposite to the equal side of the triangle are equal]
But, {tex}\angle 1 > \angle S{/tex} [{tex}\therefore{/tex} Exterior angle of a triangle is greater than each of the remote interior angles]
{tex} \Rightarrow \;\angle R > \angle S{/tex} {tex}[\because \angle 1 = \angle R]{/tex}
{tex}\Rightarrow{/tex} PS < PR [{tex}\because{/tex} In a triangle, side opposite to the large is longer]
Hence, proved.
Posted by Anuj Kumar 6 years, 3 months ago
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Muskan Chauhan 6 years, 3 months ago
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Gaurav Seth 6 years, 3 months ago
Question: If f(x) = x4 - 2x3 + 3x2 - ax + b is divided by(x - 1) and (x + 1), it leaves the remainder 5 and 19 respectively. Find 'a' and 'b'.
Answer:
Given f(x) = x4 - 2x3 + 3x2 - ax + b
When f(x) is divided by (x-1), it leaves a remainder 5
f(1) = 5
1 - 2(1)3 + 3(1)2 - a(1) + b = 5
1 - 2 + 3 - a +b = 5
-a + b = 3 … (i)
When f(x) is divided by (x+1), it leaves a remainder 19
f(-1) = 19
(-1)4 - 2(-1)3 + 3(-1)2 - a(-1) + b = 19
1 + 2 + 3 + a + b = 19
a +b = 13 … (ii)
Adding (i) and (ii),
2b = 16 b = 8
(i) a = b - 3 = 8 - 3 = 5
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Desheeba Nehal Odakkal 6 years, 3 months ago
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