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In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle when the length of all three sides are known. Unlike other triangle area formulae, there is no need to calculate angles or other distances in the triangle first.

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Abcd is a cycli quadrlateral whose diagonals intersect at point E.if angle dbc =70 angle bac =30 find angle bcd .further if ab =bc,find angle ecd

Posted by Roja Gowda 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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In chapter Heron's formula do we have to find the square root upto 3 decimal places or 2 decimal places?

Posted by Niharika Gureja 4 years, 11 months ago

CBSE > Class 09 > Mathematics

2 answers

Ash Ketchum 4 years, 11 months ago

You can leave the answer either in root or sometimes if i want to know complete exact answer then i need to solve root to 5-6 decimals by calculators..so it can vary....

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Vashu Tyagi 4 years, 11 months ago

1.73

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How to draw a triangle of angle 50 60 70

Posted by Ikram Malikgc 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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How many sides are in heptacetagon

Posted by Aman Kumar 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Girish Karhana 4 years, 11 months ago

In geometry, a hectogon or hecatontagon or 100-gon is a hundred-sided polygon.

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The sum of the probability of all staff events of a trial is

Posted by Vedanta Kachhawa 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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What is the formula of rectangle of a perimeter, area and volume this is class 5 th question you have 10 min to answer this question

Posted by Varun Singh 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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How is actresses found

Posted by Varun Singh 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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What is a non colliner

Posted by Paplu Boro 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Anurag Choudhary 4 years, 11 months ago

Three or more points which are in a line is called non collinear points

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pqrs is a trapezium with PQ parallel to SR and PS equal to QR prove that the trapezium is cyclic

Posted by Akib Knox 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Gaurav Rana 4 years, 11 months ago

Construction =draw pn perpendicular sr and qm perpendicular sr Proof =In triangle psn and triangle qmr PS =QR (given) Angle PNS =Angle QMR ( each 90°) PN= QM(perpendicular distance between two ll lines always equal) Triangle PSN =~(means congurent to) triangle QMR ( by RHS ) Angle SPN =Angle RQM(by CPCT) Adding 90° both sides Angle P= Angle Q Angle S +Angle P=180°( by co- interior) Angle S+Angle Q=180°( angle P = Angle Q) Angle R +Angle Q =180°(by co -interior ) Angle R+Angle P =180°(Angle P=Angle Q) Since sum of the opposite angle of the trapezium is 180° hence it is a cyclic trapezium

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Gaurav Rana 4 years, 11 months ago

Given=PQRS is a trapezium in which PS =QR and PQ ||SR To prove = angle p+ angle R = 180°and angle S + angle Q=180°

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Chapter 9 excrcise 9.2 q3

Posted by Anand Kishor 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Girish Karhana 4 years, 11 months ago

Proof = ΔAPB and //gm ABCD are on same base AB and b/w same parllels AB and DC. So,area(ΔAPB)=1/2 area (//gm ABCD) -1 ΔBQC of //gm ABCD have same base BC and b/w same parllels BC and AD So,area(ΔBQC)=1/2 area (//gm ABCD) -2 From eq. 1 and 2 area(ΔAPB)=area(ΔBQC) Hence Proved

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A:B=5:6 and b:c=9:10 a:b:c=?

Posted by Vinod Kumar 4 years, 11 months ago

CBSE > Class 09 > Mathematics

1 answers

Anurag Choudhary 4 years, 11 months ago

15:18:20

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Decimal expension of a rational number is terminating

Posted by Nikhat Parveen 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Proof mid point theorem and converse of mid point theorem

Posted by Rajesh Kumar 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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€&_8

Posted by Vashu Tyagi 4 years, 11 months ago

CBSE > Class 09 > Mathematics

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Girish Karhana 4 years, 11 months ago

632.48 Indian rupee 8 Euro

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ABCD is s rhombus. EABF is a straight line such that EA=AB=BF. Prove that ED and FC ,when produced ,meet at right angles.

Posted by Ramesh Tiwari 4 years, 11 months ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 4 years, 11 months ago

SinceΔEAD=ΔABC
(Corresponding angles),&AD=BC(sides of the rhombus)
By side angle side congrugency,the triangles
Therefore the corresponding parts of the triangle are also equal.
ΔCBF & ΔDAB
Since the sides
BF=AB
∠CBF∠DAB(corresponding angles)
ΔCBF&ΔDAB are congrugent
ΔAOB
∠ABO+∠BAO+∠AOB=180°
∠ABO+∠BAO=90°
∠CFB+∠AED=90°
∠XFE+∠XEF=90°

Read more on Brainly.in - https://brainly.in/question/987606#readmore

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3rd route of 24 divided by (4th root of 2 multiplied by 3rd root of 3

Posted by Krishna Hegde 4 years, 11 months ago

CBSE > Class 09 > Mathematics