CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle when the length of all three sides are known. Unlike other triangle area formulae, there is no need to calculate angles or other distances in the triangle first.

2Thank You

ANSWER

Abcd is a cycli quadrlateral whose diagonals intersect at point E.if angle dbc =70 angle bac =30 find angle bcd .further if ab =bc,find angle ecd

Posted by Roja Gowda 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

In chapter Heron's formula do we have to find the square root upto 3 decimal places or 2 decimal places?

Posted by Niharika Gureja 5 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Ash Ketchum 5 years, 3 months ago

You can leave the answer either in root or sometimes if i want to know complete exact answer then i need to solve root to 5-6 decimals by calculators..so it can vary....

3Thank You

Vashu Tyagi 5 years, 3 months ago

1.73

0Thank You

ANSWER

How to draw a triangle of angle 50 60 70

Posted by Ikram Malikgc 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

How many sides are in heptacetagon

Posted by Aman Kumar 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Girish Karhana 5 years, 3 months ago

In geometry, a hectogon or hecatontagon or 100-gon is a hundred-sided polygon.

1Thank You

ANSWER

The sum of the probability of all staff events of a trial is

Posted by Vedanta Kachhawa 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

What is the formula of rectangle of a perimeter, area and volume this is class 5 th question you have 10 min to answer this question

Posted by Varun Singh 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

How is actresses found

Posted by Varun Singh 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

What is a non colliner

Posted by Paplu Boro 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Anurag Choudhary 5 years, 3 months ago

Three or more points which are in a line is called non collinear points

0Thank You

ANSWER

pqrs is a trapezium with PQ parallel to SR and PS equal to QR prove that the trapezium is cyclic

Posted by Akib Knox 5 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Gaurav Rana 5 years, 3 months ago

Construction =draw pn perpendicular sr and qm perpendicular sr Proof =In triangle psn and triangle qmr PS =QR (given) Angle PNS =Angle QMR ( each 90°) PN= QM(perpendicular distance between two ll lines always equal) Triangle PSN =~(means congurent to) triangle QMR ( by RHS ) Angle SPN =Angle RQM(by CPCT) Adding 90° both sides Angle P= Angle Q Angle S +Angle P=180°( by co- interior) Angle S+Angle Q=180°( angle P = Angle Q) Angle R +Angle Q =180°(by co -interior ) Angle R+Angle P =180°(Angle P=Angle Q) Since sum of the opposite angle of the trapezium is 180° hence it is a cyclic trapezium

0Thank You

Gaurav Rana 5 years, 3 months ago

Given=PQRS is a trapezium in which PS =QR and PQ ||SR To prove = angle p+ angle R = 180°and angle S + angle Q=180°

0Thank You

ANSWER

Chapter 9 excrcise 9.2 q3

Posted by Anand Kishor 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Girish Karhana 5 years, 3 months ago

Proof = ΔAPB and //gm ABCD are on same base AB and b/w same parllels AB and DC. So,area(ΔAPB)=1/2 area (//gm ABCD) -1 ΔBQC of //gm ABCD have same base BC and b/w same parllels BC and AD So,area(ΔBQC)=1/2 area (//gm ABCD) -2 From eq. 1 and 2 area(ΔAPB)=area(ΔBQC) Hence Proved

1Thank You

ANSWER

A:B=5:6 and b:c=9:10 a:b:c=?

Posted by Vinod Kumar 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Anurag Choudhary 5 years, 3 months ago

15:18:20

0Thank You

ANSWER

Decimal expension of a rational number is terminating

Posted by Nikhat Parveen 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

Proof mid point theorem and converse of mid point theorem

Posted by Rajesh Kumar 5 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

€&_8

Posted by Vashu Tyagi 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Girish Karhana 5 years, 3 months ago

632.48 Indian rupee 8 Euro

2Thank You

ANSWER

ABCD is s rhombus. EABF is a straight line such that EA=AB=BF. Prove that ED and FC ,when produced ,meet at right angles.

Posted by Ramesh Tiwari 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

SinceΔEAD=ΔABC
(Corresponding angles),&AD=BC(sides of the rhombus)
By side angle side congrugency,the triangles
Therefore the corresponding parts of the triangle are also equal.
ΔCBF & ΔDAB
Since the sides
BF=AB
∠CBF∠DAB(corresponding angles)
ΔCBF&ΔDAB are congrugent
ΔAOB
∠ABO+∠BAO+∠AOB=180°
∠ABO+∠BAO=90°
∠CFB+∠AED=90°
∠XFE+∠XEF=90°

Read more on Brainly.in - https://brainly.in/question/987606#readmore

1Thank You

ANSWER

3rd route of 24 divided by (4th root of 2 multiplied by 3rd root of 3

Posted by Krishna Hegde 5 years, 3 months ago

CBSE > Class 09 > Mathematics