Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Aayush Tiwari 5 years, 5 months ago
- 2 answers
Posted by Ñoßi Ţä 5 years, 5 months ago
- 2 answers
Gaurav Seth 5 years, 5 months ago
Given a circle with centre O and chords AB = CD
Draw OP⊥ AB and OQ ⊥ CD
Hence AP = BP = (1/2)AB and CQ = QD = (1/2)CD
Also ∠OPA = 90° and ∠OQC = 90°
Since AB = CD
⇒ (1/2) AB = (1/2) CD
⇒ AP = CQ
In Δ’s OPA and OQC,
∠OPA = ∠OQC = 90°
AP = CQ (proved)
OA = OC (Radii)
∴ ΔOPA ≅ ΔOQC (By RHS congruence criterion)
Hence OP = OQ (CPCT)
Rohit Kumar 5 years, 5 months ago
Posted by Aditya Kumar 5 years, 5 months ago
- 5 answers
Posted by Shaleen Jain 5 years, 5 months ago
- 1 answers
Rohit Singh 5 years, 5 months ago
Posted by Lokesh Dhiman 5 years, 5 months ago
- 0 answers
Posted by Vedant Godhwani 5 years, 5 months ago
- 1 answers
Posted by Reena Yadav 5 years, 5 months ago
- 3 answers
Diya Tomar 5 years, 5 months ago
Posted by Mamta Panchal 5 years, 5 months ago
- 1 answers
Partap Gupta 5 years, 5 months ago
Posted by Roushan Kumar 5 years, 5 months ago
- 0 answers
Posted by Nandini Kannojia 5 years, 5 months ago
- 0 answers
Posted by Manjugouda Patil 5 years, 5 months ago
- 6 answers
Posted by Deepa Lunthi 5 years, 5 months ago
- 1 answers
Posted by Nirmal Choudhary 5 years, 5 months ago
- 1 answers
Posted by Kanika Pandey 5 years, 5 months ago
- 0 answers
Posted by Prerna Sinha 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
a-b=7 ⇒a=7+b .....(i)
a²+b²=85 ....(ii)
Substitution of equation 1 to equation 2.
(7+b)²+b² =85
49+14b +b²+b² =85
2b²+14b-36 =0
b² +7b -18 =0
(b+9)(b-2) =0
b=-9 v b=2
Find value of a
a-b=7
⇒if b=-9
a-(-9)=7
a =7-9
=-2
⇒if b=2
a-2=7
a = 7+2
=9
So value of a³ - b³ there are 2 options
⇒if (a,b) = (-2,-9)
a³-b³ = -2³ - (-9)³
= -8 +729
= 721
⇒if (a,b) = (2,9)
a³-b³ = 2³ - 9³
= 8-729
= -721
Posted by Prerna Sinha 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
a-b=7 ⇒a=7+b .....(i)
a²+b²=85 ....(ii)
Substitution of equation 1 to equation 2.
(7+b)²+b² =85
49+14b +b²+b² =85
2b²+14b-36 =0
b² +7b -18 =0
(b+9)(b-2) =0
b=-9 v b=2
Find value of a
a-b=7
⇒if b=-9
a-(-9)=7
a =7-9
=-2
⇒if b=2
a-2=7
a = 7+2
=9
So value of a³ - b³ there are 2 options
⇒if (a,b) = (-2,-9)
a³-b³ = -2³ - (-9)³
= -8 +729
= 721
⇒if (a,b) = (2,9)
a³-b³ = 2³ - 9³
= 8-729
= -721
Posted by Priya Jha 5 years, 5 months ago
- 0 answers
Posted by Charanjit Singh 5 years, 5 months ago
- 2 answers
Yogita Ingle 5 years, 5 months ago
Given a quadrilateral ABCD in which ∠C = 90º, AB = 9 m, BC = 12 m, CD = 5 m & AD = 8 m.
Join the diagonal BD which divides quadrilateral ABCD in two triangles i.e ∆BCD & ∆ABD.
In ΔBCD,
By applying Pythagoras Theorem
BD²=BC² +CD²
BD²= 12²+ 5²= 144+25
BD²= 169
BD = √169= 13m
∆BCD is a right angled triangle.
Area of ΔBCD = 1/2 ×base× height
=1/2× 5 × 12= 30 m²
For ∆ABD,
Let a= 9m, b= 8m, c=13m
Now,
Semi perimeter of ΔABD,(s) = (a+b+c) /2
s=(8 + 9 + 13)/2 m
= 30/2 m = 15 m
s = 15m
Using heron’s formula,
Area of ΔABD = √s (s-a) (s-b) (s-c)
= √15(15 – 9) (15 – 9) (15 – 13)
= √15 × 6 × 7× 2
=√5×3×3×2×7×2
=3×2√35
= 6√35= 6× 5.92
[ √6= 5.92..]
= 35.52m² (approx)
Area of quadrilateral ABCD = Area of ΔBCD + Area of ΔABD
= 30+ 35.5= 65.5 m²
Hence, area of the park is 65.5m²
Posted by Arjun Tomar 5 years, 5 months ago
- 0 answers
Posted by Dipika Pal 5 years, 5 months ago
- 0 answers
Posted by Nikki Poojar 5 years, 5 months ago
- 1 answers
Dipika Pal 5 years, 5 months ago
Posted by Nikki Poojar 5 years, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Avisha Joseph 5 years, 5 months ago
1Thank You