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A parachute is assembled using 16 congruent isosceles triangles, the sides of each triangle are 2.5m each for equal sides and 1.4mk for the base. Based on the given information answer the following questions (I) What is the height of each triangle ?

Posted by Anamika . 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Factorise 3x ki power 3 - x ki power2 - 3x + 1

Posted by Shreya Gupta 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Convert into p/q form 4.36 bar

Posted by Shubhangi Rawat 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Explain Inertia.

Posted by Anupoma Bor.Gohain 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Rivaa Jhawar 1 year, 3 months ago

A property of matter by which it remains at the state of rest or in uniform motion in the same straight line unless acted upon by some external force.

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Piyush Verma 1 year, 3 months ago

The tendency of a body to resist any change in its condition of uniform motion is referred to as inertia of motion.

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10% of x +20% of y=24 3x-y=20

Posted by Niyukti Patle 1 year, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Nikhil Kumar 1 year, 3 months ago

10% of x +20% of y=24 3x-y=20

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2-√3/2√3-√2 rationalize

Posted by Priyanshi Jangid 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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0.24 bar in p/q form

Posted by Chetan Patel 1 year, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Monali Samanta 1 year, 3 months ago

x=0.2444.... (1) 10x= 2.4444.... (2) Subtracting (2) from (1). 9x= 2.2 x= 2.2/9 Or, x= 22/90

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What is the representation of 2.513 with 13 bar as a rational number in the form p/q?

Posted by Rumpa Biswas 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Swastik Jat 1 year, 3 months ago

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Draft an article about mathematics which …

Posted by Saksham Gupta 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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(2×2³)⁴

Posted by Keerthana Rajesh 1 year, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Aqsa Fatima 1 year, 3 months ago

When base are same so we will multiply the degree 2³×⁴=2¹²

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Krishna Sahni 1 year, 3 months ago

0.59bad

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X cube plus 3 X square + 32 X + 20 factorise by synthetic

Posted by Navindharan Balu 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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The linear equation 3x=2y when expressed in the form of ax+by+c=0 then a,b,c are respectively

Posted by Saai Abijith 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Om Kumar Jha 1 year, 3 months ago

A=3B=2C=0

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An Angle is 2/3 of its supplementary angle ,the measure of the angle is

Posted by Lakshay Vashisth 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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1+secA/cosecA + cosecA/1+secA =2cosec^3A(secA-1) prove

Posted by Radhakrushna Nath 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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for rationalising the denominator of the expression 1/√12, we multiply and divide by

Posted by Jignyasa Sahu 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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cosecA/1+SecA + 1+SecA)CisecA =2cosec^3A(SecA-1)

Posted by Radhakrushna Nath 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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questions please

Posted by Priya Yati 1 year, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Namasvi Chouhan 1 year, 3 months ago

consider an integer 5. We can express 5 as the sum of squares of two numbers. So, we have 5 = 2² + 1² ⇒ (√5)2 = 2² + 1² The above equation follows the Pythagoras theorem with √5 as the hypotenuse, 2 and 1 as the other two sides of the right triangle respectively. This shows that we need to construct a right triangle with sides 2 units and 1 units so that the hypotenuse becomes √5 units on the number line. Observe the figure and the steps given below to represent root 5 on the number line. Let us see how to draw root 5 on number line. Step 1: On the number line, take 2 units from 0 and represent this point as A. Therefore, segment AB = 2 units Step 2: At point B, draw a perpendicular and mark C such that BC = 1 unit. Join A to C. Using the Pythagoras theorem, we can see that AC is the hypotenuse because ABC is a right-angled triangle and the side opposite to the right angle is the hypotenuse. In △ABC, using Pythagoras theorem, we have AC² = AB² + BC² = 2² + 1² = 5 ∴ AC = √5 units Step 3: Now, with A as the center and AC as radius, draw an arc of radius AC to cut the number line at D. Since AC = AD, point D represents √5 on the number line. Since, AC = AD = √5 units, therefore, point D represents √5 on the number line. So, we learnt how to draw root 5 on number line. In this way, we can also locate root 5 on number line.

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Aksh Singh 1 year, 3 months ago

Show how root5 can be represented on the number line

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Question 🙋 please

Posted by Priya Yati 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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c) Find the value of overline 23 +0. overline 22 -0.6 overline 7

Posted by Ayesha Khan 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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The decimal expansion of 13/50 is?

Posted by Sreelekshmi Rs 1 year, 3 months ago

CBSE > Class 09 > Mathematics

3 answers

Neeraj Singh 1 year, 3 months ago

Bdjkbl

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Prisha . 1 year, 3 months ago

13/50 13 is decided by 50 13/50 = 0.26

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Bhumesh Garg 1 year, 3 months ago

0.26

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Which of these numbers is a rational number but not whole number a)_2 b) 3.5 c)√16 d)0

Posted by Manikanta A 1 year, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Bhumesh Garg 1 year, 3 months ago

B) 3.5

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Splitting middle term 4×^2-13×+10

Posted by Aman Sharma 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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x^3+13^2+32×+20

Posted by Rashi Punjabi 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Factorise: (2y + x) ^ 2 * (y - 2x) + (2x + y) ^ 2 * (2x - y)

Posted by Abhi Singh 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Represent each of the following rational numbers on the number line 1,5/7

Posted by Pranav Sai 1 year, 3 months ago

CBSE > Class 09 > Mathematics

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Bvh

Posted by Katta Bhavith Bhavith 1 year, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Tharun Kumar 1 year, 3 months ago

Chapter 1

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Represent 5 on number line and explain

Posted by Jesu Raj 1 year, 3 months ago

CBSE > Class 09 > Mathematics

3 answers

Namasvi Chouhan 1 year, 3 months ago

consider an integer 5. We can express 5 as the sum of squares of two numbers. So, we have 5 = 2² + 1² ⇒ (√5)2 = 2² + 1² The above equation follows the Pythagoras theorem with √5 as the hypotenuse, 2 and 1 as the other two sides of the right triangle respectively. This shows that we need to construct a right triangle with sides 2 units and 1 units so that the hypotenuse becomes √5 units on the number line. Observe the figure and the steps given below to represent root 5 on the number line. Let us see how to draw root 5 on number line. Step 1: On the number line, take 2 units from 0 and represent this point as A. Therefore, segment AB = 2 units Step 2: At point B, draw a perpendicular and mark C such that BC = 1 unit. Join A to C. Using the Pythagoras theorem, we can see that AC is the hypotenuse because ABC is a right-angled triangle and the side opposite to the right angle is the hypotenuse. In △ABC, using Pythagoras theorem, we have AC² = AB² + BC² = 2² + 1² = 5 ∴ AC = √5 units Step 3: Now, with A as the center and AC as radius, draw an arc of radius AC to cut the number line at D. Since AC = AD, point D represents √5 on the number line. Since, AC = AD = √5 units, therefore, point D reprline. So, we learnt how to draw root 5 on number line. In this way, we can also locate root 5 on number line.

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Mehak Kaur 1 year, 3 months ago

Sir math ka holiday homework send krdoo answer maa

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Mehak Kaur 1 year, 3 months ago

Hlo

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If x=1/2-√3 Then solve x³-2x²-7x+5

Posted by Samruddhi Solanki 1 year, 3 months ago

CBSE > Class 09 > Mathematics