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Tharun Kumar 2 years, 4 months ago

Chapter 1
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Namasvi Chouhan 2 years, 4 months ago

consider an integer 5. We can express 5 as the sum of squares of two numbers. So, we have 5 = 2² + 1² ⇒ (√5)2 = 2² + 1² The above equation follows the Pythagoras theorem with √5 as the hypotenuse, 2 and 1 as the other two sides of the right triangle respectively. This shows that we need to construct a right triangle with sides 2 units and 1 units so that the hypotenuse becomes √5 units on the number line. Observe the figure and the steps given below to represent root 5 on the number line. Let us see how to draw root 5 on number line.  Step 1: On the number line, take 2 units from 0 and represent this point as A. Therefore, segment AB = 2 units Step 2: At point B, draw a perpendicular and mark C such that BC = 1 unit. Join A to C. Using the Pythagoras theorem, we can see that AC is the hypotenuse because ABC is a right-angled triangle and the side opposite to the right angle is the hypotenuse. In △ABC, using Pythagoras theorem, we have AC² = AB² + BC² = 2² + 1² = 5 ∴ AC = √5 units Step 3: Now, with A as the center and AC as radius, draw an arc of radius AC to cut the number line at D. Since AC = AD, point D represents √5 on the number line. Since, AC = AD = √5 units, therefore, point D reprline. So, we learnt how to draw root 5 on number line. In this way, we can also locate root 5 on number line.

Mehak Kaur 2 years, 4 months ago

Sir math ka holiday homework send krdoo answer maa

Mehak Kaur 2 years, 4 months ago

Hlo
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Ritu Jain 2 years, 4 months ago

Please answer
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Namasvi Chouhan 2 years, 4 months ago

Triangle have 3 sides let's take sides =a Sides = perimeter 3a = 180cm a = 180/3 a = 60 cm a=60 , b=60 , c=60 s=a+b+c/2 s = 180/2 s = 90 cm All are in square root √s(s-a)(s-b)(s-c) √90(90-60)(90-60)(90-60) cm² √90×30×30×30 cm² √30×3×30×30×30 cm² 30×30√3 cm² Answer is 900√3 cm²
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Nidhi Patel 2 years, 4 months ago

Hi
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Bhavya Singla 2 years, 4 months ago

Non terminating non recurring
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Bhavya Singla 2 years, 4 months ago

Q(y) = 4y³ +ky²-y-1 Y=-1 Q(-1) = 4(-1)³+k(-1)²-(-1)-1 = 4(-1)+k(1)+1-1 = -4+k+0 -4+k =0 K =4

Bhumesh Garg 2 years, 4 months ago

q(-1) =0 4(-1) ³+k(-1) ²-(-1) -1=0 4 x -1 +k x 1 +1 - 1=0 -4+k+0=0 -4+k=0 k=4
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Manikanta A 2 years, 4 months ago

√3-1÷√3+1*√3-1÷√3-1=(√3-1)™
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Sashwati Lahkar 2 years, 4 months ago

Yes it's a rational number because it is non terminating repeating number.. Hope it helps you
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Palaniappan N 2 years, 4 months ago

How to do spiral method
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Kanishka Verma 2 years, 4 months ago

Please help
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