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Gaurav Seth 4 years, 7 months ago
Given:In quadrilateral ABCD
P,Q,R,S are mid point of sides AB,BC,CD and DA respectively
T.P: 1
2
3
In triangle ADC,
SR is a line segment joining the mid point of DA and DC respectively
:. SR||AC ( mid point therom)
In triangle BAC
PQ is a line segment joining the mid point of BA and BC respectively.
PQ||AC (mid point therom)
pQ = half of AC
From 1 &2
SR=PQ
SR ||PQ
:. PQRS is a ||gram.
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Yogita Ingle 4 years, 7 months ago
{tex}2y ^{3} + y ^{2} - 2y - 1 \\ \\ = y ^{2}(2y + 1) -1 (2y + 1) \\ \\ = (2y + 1)(y ^{2} - 1) \\ \\ = (2y + 1)(y + 1)(y - 1){/tex}
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