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  • 2 answers

Sontoshidevi Rajput 4 years, 7 months ago

Set1 last year ke paper ka solution

Seema Chandel 4 years, 7 months ago

You see on this site
  • 1 answers

Manish Jha 4 years, 7 months ago

L^2= H^2+r^2 5^2=H^2+3^2 (radius =diameter/2) 25=H^2+9 25-9=H^2 16=H^2 H=4
  • 1 answers

Alok Kumar 4 years, 7 months ago

Spelling wrong hai polynomial ki?
  • 1 answers

Ravinder Yadav 4 years, 7 months ago

Friction is a force that holds back the movement of a sliding object.
  • 1 answers

Gudiya Rajpoot 4 years, 7 months ago

√9 =3
  • 1 answers

Aditya Srivastava 4 years, 7 months ago

Hi , Perimeter of Triangle = a+b+c /2 Perimeter = 540 cm Let the side be x 12x , 17x , 25x ATQ , 12x +17x +25x = 540 54x = 540 x = 10 Sides 12x = 120 17x = 170 25x = 250 Now The Perimeter = 540 /2 = 270 cm Area =square root of S(s-a)(s-b)(s-c) 270 (270 - 120)(270- 170)(270-250) 270 × 150 × 100 × 20 √40500×100×20 = ​√81000000 = 9000 cm ^2 ​​
  • 1 answers

Mishty Sharma 4 years, 7 months ago

Quotient:x^3-3x^2+3x-1 and Remainder:2
  • 5 answers

Mishty Sharma 4 years, 7 months ago

5√5

Technical Saurav 4 years, 7 months ago

√8²+6²=10 Triangle in which base is 10cm,and height is 6cm and the diagonal of cuboid

Technical Saurav 4 years, 7 months ago

Find base diagonal

Technical Saurav 4 years, 7 months ago

So first l=8,b=6

Technical Saurav 4 years, 7 months ago

The maximum length of pencil is put in diagonal so you find diagonal
  • 1 answers

Ruturaj Rahul Hod 4 years, 7 months ago

2×2=4.1
  • 1 answers

Ravinder Yadav 4 years, 7 months ago

256cm square
  • 1 answers

Shreepriya Sahoo 4 years, 7 months ago

A polynomial of degree three is called cubic polynomial
  • 2 answers

Harsh Kumar 4 years, 7 months ago

625

Seema Chandel 4 years, 7 months ago

125×25/5 =25×25 =625
  • 1 answers

Gaurav Seth 4 years, 7 months ago

Given:In quadrilateral ABCD

P,Q,R,S are mid point of sides AB,BC,CD and DA respectively

T.P: 1

2

3

In triangle ADC,

SR is a line segment joining the mid point of DA and DC respectively

:. SR||AC ( mid point therom)

In triangle BAC

PQ is a line segment joining the mid point of BA and BC respectively.

PQ||AC (mid point therom)

pQ = half of AC

From 1 &2

SR=PQ

SR ||PQ

:. PQRS is a ||gram.

  • 2 answers

Seema Chandel 4 years, 7 months ago

-1,0,1,2,3,4

Rita Devi 4 years, 7 months ago

-1 0 1 2 3 4
  • 1 answers

Yogita Ingle 4 years, 7 months ago

{tex}2y ^{3} + y ^{2} - 2y - 1 \\ \\ = y ^{2}(2y + 1) -1 (2y + 1) \\ \\ = (2y + 1)(y ^{2} - 1) \\ \\ = (2y + 1)(y + 1)(y - 1){/tex}

  • 1 answers

Pappuyadav Pappu 4 years, 7 months ago

Plic giv answer
  • 2 answers

Ks Mallah 4 years, 7 months ago

Thanks

Yash Raj 4 years, 7 months ago

Anything divide by 100 into actual value

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