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Ask QuestionPosted by Iqra ? 5 years ago
- 2 answers
Yogita Ingle 5 years ago
Given,
Capacity of the cuboidal water tank = 60,000 Litre
We know,
1000 Litre = 1m³
60,000 Litres = 60000/1000 m³= 60m³
Volume = 60m³
Length (l) = 2.5m
Height (or depth) (h)= 12m
Let the breadth be ' b '
Volume = l × b × h
60 = 25/10 × b × 12
60×1025×12=b
b = 2
Thus, the breadth of the tank is 2m
Posted by Manoj Kumar 5 years ago
- 1 answers
Yogita Ingle 5 years ago
Given, a river 3m deep and 40m wide is flowing at the rate of 2km per hour.
Area of cross section of the river = 3 * 40 = 120 m2
Now, volume of water flowing through this cross section in every minute = Area * rate
= 120 * 2 km/hr
= 120 * (2000/60) m/min
= 2 * 2000
= 4000 m3
Since 1 m3 = 1000 litres
So, 4000 m3 = 4000 * 1000 litres = 4000000 litres
So, in 1 minute, water will fall into the sea is 4000000 litres.
Posted by Prince Raj 5 years ago
- 1 answers
Yogita Ingle 5 years ago
Givenx4+4=(x2)2+22
Weknowthat,a2+b2=(a+b)2−2ab
Here, a=x2,b=2
=(x2+2)2−2×x2×2
=(x2+2)2−4×x2
=(x2+2)2−(2x)2
Weknowthat,a2−b2=(a+b)(a−b)
=(x2+2+2x)(x2+2−2x)
=(x2+2x+2)(x2−2x+2)
Therefore,.
x4+4=(x2+2x+2)(x2−2x+2)
Posted by Lucky Shandilya 5 years ago
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Posted by Iqra ? 5 years ago
- 2 answers
Posted by Iqra ? 5 years ago
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Posted by Alka Chauhan 5 years ago
- 1 answers
Yogita Ingle 5 years ago
Let r1 and r2 be radii of two cyclinder and V1, V2 be their volume .
Let h be height of the two cyclinders, then
V1 = πr2h and V2 = πr22h
∴ V1 / V2 = πr12h / πr22h = r12 / r22 = 16 / 25 .
Posted by Prathmesh Arage 5 years ago
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Posted by Iqra ? 5 years ago
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Harsh Kumar 5 years ago
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Harshita Walia 5 years ago
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Posted by Sontoshidevi Rajput 5 years ago
- 2 answers
Arpit Raj 5 years ago
Yogita Ingle 5 years ago
Let the ratio be 11x 19x and 24x
11x +19x+24x =540
54x =540 .: x = 540/54
Hence x=10
11x =11×10=110 19x= 19×10 =190
24x=24 × 10 =240
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Prince Raj 5 years ago
1Thank You