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  • 2 answers

Prince Raj 4 years, 7 months ago

2

Yogita Ingle 4 years, 7 months ago

Given,
Capacity of the cuboidal water tank = 60,000 Litre
We know,
1000 Litre = 1m³
60,000 Litres = 60000/1000 m³= 60m³

Volume = 60m³

Length (l) = 2.5m
Height (or depth) (h)= 12m
Let the breadth be ' b '

Volume = l × b × h

60 = 25/10 × b × 12

{tex}\frac{60 \times 10}{25 \times 12} = b{/tex}
b = 2

Thus, the breadth of the tank is 2m

  • 1 answers

Yogita Ingle 4 years, 7 months ago

Given, a river 3m deep and 40m wide is flowing at the rate of 2km per hour.

Area of cross section of the river = 3 * 40 = 120 m2

Now, volume of water flowing through this cross section in every minute = Area * rate

  = 120 * 2 km/hr

 = 120 * (2000/60) m/min

 = 2 * 2000

  = 4000 m3

Since 1 m3 = 1000 litres

So, 4000 m3 = 4000 * 1000 litres = 4000000 litres

So, in 1 minute, water will fall into the sea is 4000000 litres.

  • 1 answers

Yogita Ingle 4 years, 7 months ago

{tex}Given \: x^{4}+4\\=\big(x^{2}\big)^{2}+2^{2}{/tex}

{tex}We \: know \: that ,\\\boxed {a^{2}+b^{2}=(a+b)^{2}-2ab}{/tex}

Here, {tex}\\a = x^{2},\:b = 2{/tex}

{tex}=\left(x^{2}+2\right)^{2}-2\times x^{2}\times 2{/tex}

{tex}=\left(x^{2}+2\right)^{2}-4\times x^{2} {/tex}

{tex}=\left(x^{2}+2\right)^{2}-(2x)^{2}{/tex}

{tex}We \: know \: that ,\\\boxed { a^{2}-b^{2}=(a+b)(a-b)}{/tex}

{tex}=(x^{2}+2+2x)(x^{2}+2-2x){/tex}

{tex}=(x^{2}+2x+2)(x^{2}-2x+2){/tex}

Therefore,.

{tex}x^{4}+4=(x^{2}+2x+2)(x^{2}-2x+2){/tex}

  • 1 answers

Lucky Shandilya 4 years, 7 months ago

How
  • 2 answers

Akshit Chauhan 4 years, 7 months ago

0

Prince Raj 4 years, 7 months ago

0 will be the answer
  • 1 answers

Yogita Ingle 4 years, 7 months ago

Let r1 and r2 be radii of two cyclinder and V1, Vbe their volume . 

Let h be height of the two cyclinders, then  

 V1 = πr2h and V=  πr22

∴  V/  V2 =  πr12h /  πr22h  = r12 / r22 = 16 / 25 . 

  • 1 answers

Prince Raj 4 years, 7 months ago

It is scalne
  • 2 answers

Mishty Sharma 4 years, 7 months ago

AC=MN and angle B is equals to angle O

Vaibhav Roy 4 years, 7 months ago

AC=MN and
  • 1 answers

Rajeevan Rajkumar 4 years, 7 months ago

Definitely infinity
  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Be Unique Suman 4 years, 7 months ago

Rationalize the dinomineter 1/3√8*3√8/3√8 Solve it
  • 1 answers

Vedvir Singh 4 years, 7 months ago

10 x square - 3 x minus 6 ka factors Karen
10x
  • 0 answers
  • 1 answers

Harsh Kumar 4 years, 7 months ago

Y-2=0 Y=0+2 Y=2
  • 1 answers

Mohinderjeet Singh 4 years, 7 months ago

0
  • 2 answers

Harsh Kumar 4 years, 7 months ago

X=0 and y=k Let put the value of x and y in equation 5x-3y=3 So,5*0-3*k=3 0-3k=3 3k=3-0 3k=3 K=3/3 K=3

Syed Ammar 4 years, 7 months ago

Yes
  • 3 answers

Harshita Walia 4 years, 7 months ago

The line segment joining the mid points of two sides of a triangle is parallel to the third side

Be Unique Suman 4 years, 7 months ago

And it is 1/2 of third side

Syed Ammar 4 years, 7 months ago

The mid point of two sides of triangle is parallel to third side
  • 1 answers

Ayush Tahenguriya 4 years, 6 months ago

5398-588- 856
  • 2 answers

Arpit Raj 4 years, 7 months ago

Let the ratio be 11x,19x,24x 11x +19x+24x =540 54x=540 x=10 11x= 11×10=110 19x=19×10=190 24x=24×10=240 Semi perimeter=a+b+c/2 (scalence triangle) 110+190+240/2=570/2=270 Area of scalence triangle = √s(s-a)(s-b)(s-c). (Heronce formula) (s-a)=270-110=160cm (s-b)=270-190=60cm (s-c)=270-240=30cm √270×160×60×30 √3×3×3×10×2×2×2×2×10×3×2×10×3×10 √(3×3×10×2×2×10)^2×6 9×100×4×6 24×9×100 21600cm^2 Therefore the area of triangle is 21600cm^2

Yogita Ingle 4 years, 7 months ago

Let the ratio be 11x 19x and 24x

11x +19x+24x =540

54x =540 .: x = 540/54

Hence x=10

11x =11×10=110 19x= 19×10 =190

24x=24 × 10 =240

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