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Khushi Gadhavi 5 years, 8 months ago
Yogita Ingle 5 years, 8 months ago
A trapezium is a quadrilateral that has only one pair of parallel sides.
Area of trapezium ABCD = 1/2 (sum of parallel sides) × (perpendicular distance between them)
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Yogita Ingle 5 years, 8 months ago
Given,
Capacity of the cuboidal water tank = 60,000 Litre
We know,
1000 Litre = 1m³
60,000 Litres = 60000/1000 m³= 60m³
Volume = 60m³
Length (l) = 2.5m
Height (or depth) (h)= 12m
Let the breadth be ' b '
Volume = l × b × h
60 = 25/10 × b × 12
{tex}\frac{60 \times 10}{25 \times 12} = b{/tex}
b = 2
Thus, the breadth of the tank is 2m
Posted by Manoj Kumar 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
Given, a river 3m deep and 40m wide is flowing at the rate of 2km per hour.
Area of cross section of the river = 3 * 40 = 120 m2
Now, volume of water flowing through this cross section in every minute = Area * rate
= 120 * 2 km/hr
= 120 * (2000/60) m/min
= 2 * 2000
= 4000 m3
Since 1 m3 = 1000 litres
So, 4000 m3 = 4000 * 1000 litres = 4000000 litres
So, in 1 minute, water will fall into the sea is 4000000 litres.
Posted by Prince Raj 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
{tex}Given \: x^{4}+4\\=\big(x^{2}\big)^{2}+2^{2}{/tex}
{tex}We \: know \: that ,\\\boxed {a^{2}+b^{2}=(a+b)^{2}-2ab}{/tex}
Here, {tex}\\a = x^{2},\:b = 2{/tex}
{tex}=\left(x^{2}+2\right)^{2}-2\times x^{2}\times 2{/tex}
{tex}=\left(x^{2}+2\right)^{2}-4\times x^{2} {/tex}
{tex}=\left(x^{2}+2\right)^{2}-(2x)^{2}{/tex}
{tex}We \: know \: that ,\\\boxed { a^{2}-b^{2}=(a+b)(a-b)}{/tex}
{tex}=(x^{2}+2+2x)(x^{2}+2-2x){/tex}
{tex}=(x^{2}+2x+2)(x^{2}-2x+2){/tex}
Therefore,.
{tex}x^{4}+4=(x^{2}+2x+2)(x^{2}-2x+2){/tex}
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