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Gorika Singhal 4 years, 3 months ago
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Bangtan Army Forever 4 years, 3 months ago
Posted by Vidya Meshram 4 years, 3 months ago
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Yogita Ingle 4 years, 3 months ago
Diagonals of a rhombus bisect each other at right angles.
Let ABCD be the rhombus, Diagonal AC= 16 cm and side AB = 10 cm.
In right triangle AOB, AB = 10 cm, AO = 8 cm
By Pythagoras theorem, AB2 = AO2 + BO2
(10)2 = (8)2 + BO2
BO2 = (10)2 – (8)2
BO = 6 cm
Diagonal BD = 2 x 6 = 12 cm
Area of rhobus = 1/2 × product of the diagonal
= 1/2 × 16× 12
= 96 cm2
Hence length of other diagonal = 12 cm; Area of rhombus = 96 cm2
Posted by Vidya Meshram 4 years, 3 months ago
- 1 answers
Yogita Ingle 4 years, 3 months ago
We know that the diagonal of a parallelogram divides it into two congruent triangles. Also, congruent triangles hae equal areas.
So, Area of parallelogram = 2(Area of triangle made by two adjacent sides and diagonal).
Given sides = (a) 13 cm and (b) 14 cm and Diagonal = (c) 15 cm.
So, Semiperimeter (s) = (a+b+c)/2 = (13+14+15)/2 = (42)/2 = 21 cm
So, Area of triangle by heron's formula
Thus, Area of parallelogram = 2*84 = 168 cm²
Posted by Vidya Meshram 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
For triangle
a = 26 cm
b = 28 cm
c = 30 cm
Area of the triangle
Let the height of the parallelogram be h cm.
Then, area of the parallelogram
= Base x Height = 28 x h cm2
According to the question,
Hence, the height of the parallelogram is 12 cm.
Posted by Vidya Meshram 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
area of quadrilateral ABCD= Area of triangle ABC + Area of triangle ADC
Area of trianlge= sqrt(s(s-a)(s-b)(s-c))
FOR area of triangle ABC
s=(7+6+9)/2=11
area of triangle ABC=sqrt(11(11-7)(11-6)(11-9))
=sqrt(440)
= 20.9761
similarly,
area of triangle ADC=54
therefore area of quadrilateral ABCD=20.9761+ 54
=74.9761
Posted by Vidya Meshram 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
Ratio of sides = 3:5:7
Let sides be 3x, 5x, 7x
So 3x + 5x + 7x = 300m
15x = 300m
x = 20 m
Sides are 60m, 100m, 140m
s = 
Posted by Sakshi ? Prajapat ? 4 years ago
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Posted by Rajnandini Rao 4 years, 3 months ago
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Yogita Ingle 4 years, 3 months ago
{tex}\frac35=\frac{3\times7}{5\times7}=\frac{21}{35}\\\frac57=\frac{5\times5}{7\times5}=\frac{25}{35}{/tex}
The rational number between 3 by 5 and 5by 7 are 22/35, 23/35, 24/35
Posted by Gaurav Mandal 4 years, 3 months ago
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Posted by Ismath Parvin 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
Let p(x) = x3 - 6x2 + 11x - 6
By trial, we find that
p(1) = (1)3 - 6(1)2 + 11(1) - 6 = 0
∴ By converse of factor theorem, (x - 1) is a factor of p(x).
Now, x3 - 6x2 + 11x - 6
= x2 (x - 1)- 5x (x - 1) + 6 (x - 1)
= (x - 1) (x2 - 5x + 6)
= (x - 1) {x2 - 2x - 3x + 6}
= (x - 1) {x(x - 2)-3 (x - 2)}
= (x - 1)(x - 2)(x - 3)
Posted by Veena Mahire 4 years, 3 months ago
- 5 answers
Gaurav Seth 4 years, 3 months ago
Real Number
Real number is a value that represents a quantity along the number line.
Real number includes all rational and irrational numbers.
Rational numbers are numbers which can be represented in the form p/q where, q is not equal to 0 and p,q are integers.
Therefore, rational number is a subset of real number.
Posted by Poonam Sharma 4 years, 3 months ago
- 2 answers
Gaurav Seth 4 years, 3 months ago
Step-by-step explanation:
-3 and -2
-3*3/1*3 and -2*3/1*3
-9/3 and -6/3
No. Are = -7/3 and -8/3
Posted by Sumit Pandey 4 years, 3 months ago
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Posted by Ankit Shah 4 years, 3 months ago
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Ujjawal Bhardwaj 4 years, 3 months ago
Yogita Ingle 4 years, 3 months ago
Given Equation is 9x2 + 18x + 8
= 9x2 + 6x + 12x + 8
= 3x(3x + 2) + 4(3x + 2)
= (3x + 4)(3x + 2).
Posted by Saikat Nandi 4 years, 3 months ago
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Posted by Hemali Parikh 4 years, 3 months ago
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Yogita Ingle 4 years, 3 months ago
A zero polynomial is the one where all the coefficients are equal to zero. So, the degree of the zero polynomial is either undefined, or it is set equal to -1.
Posted by Abhipsa Priyadarshini 4 years, 3 months ago
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Yogita Ingle 4 years, 3 months ago
25)1/3 × (5)1/3
=(5)2×1/3 × (5)1/3
= (5)2/3 × (5)1/3
= (5)2/3+1/3 ( same base powers are added)
= (5)3/3
= 51
= 5
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Priya Kainth 4 years, 3 months ago
Posted by Yash Malik 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
if we multiply or divide both sides of a linear equation by a non zero number, then the roots of linear equation will remain same.
Explanation :
Let a linear equation in one variable x is
3x = 15 ---(1)
i ) Multiply equation (1) by 2,we get
2×3x = 2×15
=> 6x = 30
Therefore,
If we multiply or divide both sides of a linear equation by a non zero number, then the roots of linear equation will remain same
Posted by Vijay Phadnis 4 years, 3 months ago
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Gaurav Seth 4 years, 3 months ago
Question : A triangular park has sides 120 m, 80 m, 50 m. A gardener has to put a fence all around it and also plant grass inside. How much area does he need to plant? Find the cost of fencing it with barbed wire at the rate of Rs 20 per meter leaving a space 3 m wide for a gate on one side.
Answer:
Area to be planted
Cost of the fencing = Rs.4940
Step-by-step explanation:
Given : A triangular park has side 120m ,80m, 50m.
Barbed wire at rate of Rs.20 per meter.
To find : The area of park he need to plant and the cost of fencing leaving a space of 3m wide for a gate on 1 side.
Solution : First we the area by Heron's formula,
Where s is
a= 120m, b=80m, c=50m
Substitute the value,
Now, The area to be planted is
Length of the fenced = Perimeter- space for the gate
Perimeter= a+b+c= 120+80+50=250
Space for the gate is = 3m
Length of the fenced = 250-3 = 247 m
Cost of the fencing = Length of the fence × Wire rate
Cost of the fencing = 247 × 20 = Rs.4940
Posted by Deepanshu Bhati 4 years, 3 months ago
- 1 answers
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Gorika Singhal 4 years, 3 months ago
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