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Ask QuestionPosted by Almi Aami 4 years, 3 months ago
- 1 answers
Posted by Hardew Bhagat 4 years, 3 months ago
- 1 answers
Posted by Meenakshi Meenakshi 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Given :
- MN and PQ are parallel lines .
- ange M = 110° , and angle p = 120°
To Find :
- x = ?
Construction :
Draw a line lb bisecting angle O.
Procedure :
(Before proceeding , please refer to the attached file)
It is given that the the two lines MN and PQ are parallel to each other.
According to theorem of parallel lines :
Two lines which are parallel to the same given line e parallel to each other.
So ,
Now , all properties of parallel lines could be performed here.
Posted by Juluru Krupavaram 4 years, 3 months ago
- 1 answers
Neha Singh 4 years, 3 months ago
Posted by Harman Preet Bedi Bedi 4 years, 3 months ago
- 2 answers
Yogita Ingle 4 years, 3 months ago
Area of a ΔABC, given sides a, b, c by Heron’s formula (Also known as Hero’s Formula) :
Find semi perimeter (s ) = (a+b+c)/2
Area=√[s(s-a)(s-b)(s-c)]
This formula is helpful to find the area of a scalene triangle, given the lengths of all its sides.
Posted by Aditya Sahu 4 years, 3 months ago
- 1 answers
Almi Aami 4 years, 3 months ago
Posted by Ankit Behera 4 years, 3 months ago
- 4 answers
Posted by Rohini Nirwan 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Let p(x) = x5-a2x3+2x+a+3
Since, (x-a) is a factor of p(x), so p(a) = 0
Posted by Ridhima Choudhary 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
given the sides of the triangular park are 120m, 80m and 50m.
perimeter of the triangular park = 120m + 80m + 50m
= 250m
therefore it's semi-perimeter = 250/2
= 125m
hence, the gardener have to plant grass in 1452.36m²
now we have to find the cost of fencing the field with a barbed wire at the rate of rs 20 per m leaving a space of 3m wide for a gate.
therefore the gardener have to fence = 250 - 3
= 247m
so total cost of fencing at the rate of rs 20 per meter = 247 × 20
= rs 4940
Posted by Shubham Kumar 4 years, 3 months ago
- 5 answers
Posted by Babulal Dangayach 4 years, 3 months ago
- 1 answers
Posted by M B Singh M B Singh 4 years, 3 months ago
- 2 answers
Posted by Rishabh Maurya 4 years, 3 months ago
- 5 answers
Posted by Vijay Laxmi Sharma 4 years, 3 months ago
- 1 answers
Yogita Ingle 4 years, 3 months ago
31/16
= 31 /(2 * 2 * 2 * 2)
= 31 * 5 * 5 * 5 * 5 / ( 2 * 2 * 2 * 2 * 5 * 5 * 5 * 5)
= 31 * 625 / 10 * 10 * 10 * 10
= 19375/10000
= 1.9375
31/16= 1.9375
1.9375
16 _| 31.0000 |_
16
____
150
144
_____
60
48
_____
120
112
____
80
80
_____
0
Posted by Aayushi Sharma Pandit Ji 4 years, 3 months ago
- 4 answers
Indrani Sahu 4 years, 3 months ago
Posted by Harsh Patil 4 years, 3 months ago
- 1 answers
Posted by Prerna Chhillar 4 years, 3 months ago
- 0 answers
Posted by Muskan Yadav 4 years, 3 months ago
- 1 answers
Hardew Bhagat 4 years, 3 months ago
Posted by Amanullha Pathan 4 years, 3 months ago
- 0 answers
Posted by Shruti Agrawal 4 years, 3 months ago
- 4 answers
Posted by Almi Aami 4 years, 3 months ago
- 1 answers
Yogita Ingle 4 years, 3 months ago
Consider, 27x3 + y3 + z3 - 9xyz
= (3x)3 + y3 + z3 - 3 × (3x) × y × z
= [3x + y + z ][(3x)2 + y2 + z2 - (3x) × y − y × z − z(3x)] [Since (a + b + c )(a2 + y2 + z2 - ab−bc−ca)]
= [3x + y + z ][9x2 + y2 + z2 - 3xy − yz − 3zx]
Posted by Ayush Pal 4 years, 3 months ago
- 2 answers
Nandini Arora 4 years, 2 months ago
Posted by Arnav Yadav 4 years, 3 months ago
- 4 answers
Gaurav Seth 4 years, 3 months ago
Let given polynomial p(x)=ax³+bx²+x-6 ,
i) If x+2 is a factor of p(x) then
p(-2) = 0
By factor theorem
a(-2)³+b(-2)²+(-2)-6=0
=> -8a+4b-8=0
Divide each term by 4 , we get
=> -2a+b-2 =0
=> -2a+b = 2 ---(1)
ii) If p(x) divided by (x-2) the remainder is p(2)
According to the problem given,
p(2) = 4
=> a(2)³+b(2)²+2-6=4
=> 8a+4b-4=4
Divide each term by 4, we get
=> 2a+b-1=1
=> 2a+b=2 ---(2)
Add equation (1) and (2) , we get
2b = 4
Substitute b = 2 , in equation (2) ,we get
2a+2=2
=> 2a = 2-2
=> 2a = 0
=> a = 0
Therefore,
Posted by Vishal Ray 4 years, 3 months ago
- 0 answers
Posted by Vishal Ray 4 years, 3 months ago
- 3 answers
Yogita Ingle 4 years, 3 months ago
M and s are unit of time and kg unit of mass. SO, not possible to add.
Posted by Baby Singha 4 years, 3 months ago
- 2 answers
Posted by Purvi Singhal 4 years, 3 months ago
- 1 answers
Posted by Purvi Singhal 4 years, 3 months ago
- 1 answers
Posted by Vijay Songra 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Ab=bc=34
dc=20
ac=42
using herons formula AREA of ΔACD
√s(s-a)(s-b)(s-c)
√48(48-34)(48-20)(48-42)
√48*14*28*6
=336
AREA of Δabc=336
∵are of parellepgram abcd =336*2=672
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Hanshika (Honey) 4 years, 3 months ago
2Thank You