CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

FIRST RATIONALISE 1/X 1/ 6 - root 35 × 6+ ROOT 35 =6+ ROOT35 /6²- ROOT 35 1/X = 6+ ROOT 35 SO X+1/X = 6- ROOT 35 + 6 + ROOT 35 X+1/X= 6+6 X+1/X = 12 ANS = 12

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A traffic signal board, indicating ‘ SCHOOL AHEAD ’ , is an equilateral triangle with side ‛a’ . Find the area of the signal board , using Heron ’s formola . If its perimeter is 180 cm , what will be the area of the signal board?

Posted by Rd Pandey 4 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Manish Meena 4 years, 2 months ago

Area of triangle = √(s(s−a)(s−b)(s −c)) Here, s is the semi-perimeter, and a, b, c are the sides of the triangle Given Perimeter = 180 cm Semi-Perimeter = s =Perimeter/2 s = 180/2 s = 90 cm Given that the triangle is equilateral Since all sides of equilateral triangle are equal ∴ a = b = c Perimeter = 180 cm a + a + a = 180 cm 3a = 180 cm a = 180/3 cm a = 60 cm Area of triangle = √(s(s−a)(s−b)(s −c)) Putting a = b = c = 60 cm , s = 90 cm Area of signal board = √(90(90−60)(90−60)(90 −60)) = √( 90(30)(30)(30) ) = √( (9×3×3×3)×(10)4) = √((9×9)×3×(10)4) = √((92)×3×(10)4) = √92×√3 × √((10)4) = 9×√3 ×(〖104)〗^(1/2) = 9 ×√3 × (102) = 9 × 100 × √3 = 900√3 Thus, Area = 900√3 cm2

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Silviya Shrivastav 4 years, 2 months ago

S=60+60+60/2 =90 Area=√90(90-60)(90-60)(90-60) =√90*30*30*30 =√3*3*10*30*30*3*10 =3*10*30√3 =900√3cm.sq HOPE IT HELPS

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Evaluate (64)1/6

Posted by Himanshu Sharma 4 years, 2 months ago

CBSE > Class 09 > Mathematics

4 answers

Ashok Jain 4 years, 2 months ago

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Ashvin Kharadi 4 years, 2 months ago

9.2581481533419209

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Manish Meena 4 years, 2 months ago

Rewrite 64 as 2 6 . ( 2 6 ) 1 6 Apply the power rule and multiply exponents, ( a m ) n = a m n . 2 6 ( 1 6 ) Cancel the common factor of 6 . Then ans. = 2

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Silviya Shrivastav 4 years, 2 months ago

Take LCM of 64=2*2*2*2*2*2 pair them in square =(2^6)1/6 =6and1/6 (will cancel each other) =2

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Check whether 7+3x is a factor of 3xcube +7x

Posted by Dhanush M 4 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Ashok Jain 4 years, 2 months ago

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Santosh Shukla 4 years, 2 months ago

Brainly.in What is your question? 1 salonisood salonisood 29.05.2017 Math Secondary School +5 pts Answered Check whether 7+3x is a factor of 3x³+7x 2 SEE ANSWERS Log in to add comment Answer Expert Verified 4.5/5 460 hukam0685 Genius 3.5K answers 846.9K people helped Answer: No , 7+3x is not factor of 3x³+7x Step-by-step explanation: To find whether is a factor of find the value of x from f(x) and put to g(x) ,if expression becomes zero than f(x) is a factor of g(x),otherwise not g(-7/3) is not zero,hence f(x) is not a factor of g(x) Hope it helps you.

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23 (/75)

Posted by Annu Kapasia 4 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Silviya Shrivastav 4 years, 2 months ago

0.3066666666666

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P(y) =y2-y+1

Posted by Kolli Pavan Kumar Reddy 4 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Ashok Jain 4 years, 2 months ago

Correct

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Meenu Gupta 4 years, 2 months ago

What we have do in this pls tell then only we are able to solve it

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The coefficient of x^2 in the expansion of (x+3)^4is

Posted by Suhani Rai 4 years, 2 months ago

CBSE > Class 09 > Mathematics

4 answers

Ashok Jain 4 years, 2 months ago

Any coeficient can be added

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Ashok Jain 4 years, 2 months ago

(X+3)⁴ = x⁴+4x³(3)+6x²(3)²+4(3)³x+(3)⁴ = x⁴+12x³+54x²+108x+243

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Manish Meena 4 years, 2 months ago

(X+3)⁴ = x⁴+4x³(3)+6x²(3)²+4(3)³x+(3)⁴ = x⁴+12x³+54x²+108x+243 I LIKE IT

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Parthav Udayasankar 4 years, 2 months ago

(X+3)⁴ = x⁴+4x³(3)+6x²(3)²+4(3)³x+(3)⁴ = x⁴+12x³+54x²+108x+243

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4. The abscissa and ordinate of the point with Co-ordinates (8, 12) is (a) abscissa 12 and ordinate 8 (b) abscissa 8 and ordinate 12 (c) abscissa 0 and ordinate 20 (d) none of these Ans. (a) abscissa 12 and ordinate The answer which is given above is right or wrong

Posted by Suhani Rai 4 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Silviya Shrivastav 4 years, 2 months ago

(b)abscissa8 and ordinate12 Basic concept: (x,y)where x=abscissa y=ordinate Hope it helps!!

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Find the coordinates of the vertices of the square ABCD (side 2a) (i)taking AB and AD as axes (ii)taking the centre of the square as origin and axis parallel to the sides AB and AD.

Posted by Manju Singh 4 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Santosh Shukla 4 years, 2 months ago

Here is your answer....... ABCD be a square Side = 2a Centre = (0,0) Origin Y-coordinates of AB = (0-2a)/2 = -a Y-coordinates of AD = (0+2a)/2 = a ∴ the coordinates are :- A(-a,-a) B (a,-a) C (a,a) D (-a,a) #Refer to the figure. I hope it helps you ^_^

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√15×√29

Posted by Diksha Sangolkar 4 years, 2 months ago

CBSE > Class 09 > Mathematics