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Ask QuestionPosted by . . 4 years, 2 months ago
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Gaurav Seth 4 years, 2 months ago
AB = AC
Therefore, ∠B =∠C ( Angles Opposite to equal sides are equal )
∠A+∠B+∠C = 180° (Angle Sum Property)
or, ∠A+50°+50° = 180°
or, ∠A+100° = 180°
or, ∠A = 180°-100°
or, ∠A=80°
Therefore, ∠A=80°
Posted by . . 4 years, 2 months ago
- 1 answers
Posted by . . 4 years, 2 months ago
- 1 answers
Gaurav Seth 4 years, 2 months ago
This ΔABC is an isosceles triangle. In this kind of triangle, two of the sides are equal.
So if AB=AC,
Then vertex= angle A and
Base angles= angle B and angle C which are equal.
Let the base angles angle B and angle C be x.
Since the sum of the angles of a triangle=180°,
Therefore,
angle A + angle B + angle C = 180°
= 120° + x+x= 180°
= 120° + 2x= 180°
= 2x = 180°-120°
= 2x = 60°
= x = 60°/2 =30°
Therefore,
Angle A= 120°
Angle B= 30°
Angle C= 30°.
Posted by Angad Bhati 4 years, 2 months ago
- 2 answers
Arman Parihar 4 years, 2 months ago
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- 2 answers
Yogita Ingle 4 years, 2 months ago
(a)2x + y = 7......(1)
On putting x=0 in equation 1
2x+y=7
2×0+y=7
0+y=7
y=7
So( 0, 7) is a solution of given equation.
let y=0
2x+y=7
2x+0=7
2x=7
X= 7/2
So(7/2,0) is a solution of given equation.
let x = 1
2x+y=7
2×1+y=7
2+y=7
Y= 7-2
Y=5
(1,5) is the solution.
let x = 2
2x+y=7
2×2+y=7
4+y=7
Y= 7-4
Y= 3
The solution is (2,3)
Hence, 4 out of the infinitely many solutions of the given equation are(0,7), (7/2,0),(1,5),(2,3)
(b) πx + y = 9
let x = 0
πx + y = 9
π×0+y =9
0+y= 9
Y=9
(0,9) is the solution.
Let y = 0
πx + y = 9
πx+0=9
πx=9
x= 9/π
(9/π,0) is the solution.
Let x = 1
πx + y = 9
π×1+y=9
π+y=9
Y= 9-π
(1,9-π) is the solution.
Let x = -1
πx + y = 9
π×-1+y=9
-π+y=9
Y= 9+π
(-1,9+π) is the solution.
Hence, 4 out of the infinitely many solutions of the given equation are(0,9), (9/π,0),(1,9-π),(-1,9+π)
(c) x= 4y
Let x = 0
X=4y
0=4y
Y=0/4=0
Y=0
(0,0) is the solution.
Let x= 1
X=4y
1=4y
Y= 1/4
(1,1/4) is the solution.
Let y = 1
X=4y
X=4×1
X=4
(4,1) is the solution.
Let x = 2
X=4y
2=4y
Y=2/4
Y=1/2
(2,1/2) is the solution.
Hence, 4 out of the infinitely many solutions of the given equation are(0,0), (1,1/4),(4,1),(2,1/2)
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Put x=2 and y=3
3x+2y=t
t = 3(2) + 2 (3)
t = 6 + 6
t = 12
Posted by Rohan Patil 4 years, 2 months ago
- 1 answers
Yogita Ingle 4 years, 2 months ago
Put x=1,y=0
[k+2/k-1]x -[3k-2/k+2]y-3=0
(k2 + 2 - k)/k] 1 -[3k-2/k+2]0-3=0
(k2 + 2 - k)/k] = 3
k2 + 2 - k = 3k
k2 + 2 - k -3k = 0
k2 -4k+ 2= 0
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Gaurav Seth 4 years, 2 months ago
a n s w e r :
two lines are
L1 : 2x+3y=9
L² : x=4
then x coordinat of point where they meet is 4
8+3y=9
y=1/3
point of interestion is (4,1/3)
Or
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