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Ask QuestionPosted by Tanishka Kushwaha 5 years, 3 months ago
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Posted by Shreyansh Kanare 5 years, 3 months ago
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Posted by Yuvraj Bhikane 5 years, 3 months ago
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Posted by Utkarsh Tiwari 5 years, 3 months ago
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Posted by Manu Bhat 5 years, 3 months ago
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Posted by Vivek Mahato 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
(a+b+c)2 = a2+b2+c2+2ab+2bc+2ca
⇒(2x−y+z)2=(2x)2+(−y)2+(z)2+2(2x×−y)+2(−y×z)+2(z×2x)
=4x2 + y2+z2−4xy−2yz+4xz
Posted by Chitralekha Khaund 5 years, 3 months ago
- 2 answers
Chaitanya Saini 5 years, 3 months ago
Pratibha Kushwah 5 years, 3 months ago
Posted by Chitralekha Khaund 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Total surface area of a cube = 726 cm2
6 × (side)2 = 726
(side)2 = 121
side = 11 cm
Hence, the length of the edge of cube is 11 cm.
Posted by Chitralekha Khaund 5 years, 3 months ago
- 2 answers
Chaitanya Saini 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
Let the length be 4x
Let the breadth be 2x
Let the height be x
Surface area=2(lb+bh+hl)
=2(8x²+2x²+4x²)
=28x²=1372
so x²=49
and x=7
So length=4x=28cm
breadth=2x=14cm
&. height=x=7cm
Posted by Arya Dixit 5 years, 3 months ago
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Posted by Rishi Singh 5 years, 3 months ago
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Divya Khola 5 years, 2 months ago
Posted by Hani Soni 5 years, 3 months ago
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Posted by Ritika Date 5 years, 3 months ago
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Posted by Darshan Patel 5 years, 3 months ago
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Posted by Risha Mavi 5 years, 3 months ago
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Gaurav Seth 5 years, 3 months ago
Prove that if the diagonals of a quadrilateral bisect each other, then it is a parallelogram.
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OA = OC and OB = OD [Given]
AOB = DOC [vertically opp. angles]
[SAS congruence]
Therefore 
ABO = CDO (cpct)
From this, we get AB||CD ...(i)
Similarly BC||AD ...(ii)
From (i) and (ii) ABCD is a ||gm.
Posted by Aditya Kumar Saha 5 years, 3 months ago
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Posted by Aiswarya Raanee .K 5 years, 3 months ago
- 2 answers
Posted by Priram Senthil 5 years, 3 months ago
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Posted by Aiswarya Raanee .K 5 years, 3 months ago
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Posted by Aiswarya Raanee .K 5 years, 3 months ago
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Posted by Gurkaran Deep Singh Gill 5 years, 3 months ago
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Posted by Arti Rajput 5 years, 3 months ago
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Arpit Bareth 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
Given:
⇒l=30,b=25,h=25
(i) Total S.A of green house
=2(lb+bh+lb)
=2(30×25+30×25+25×25)
=4250 cm2
(ii) For 12 edges: Total length
=4l+4b+4h
=4(30+25+25)
=320 cm
Posted by Darshit Chandra 5 years, 3 months ago
- 5 answers
Posted by Priya Padhan 5 years, 3 months ago
- 1 answers
Posted by Harsh Maurya 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
In △ADF and △ECF , we have
∠ADF = ∠ECF [alt.int.∠s]
AD = EC [∵ AD = BC and BC = EC]
∠DFA = ∠CFE [vert. opp. ∠s]
∴ By AAS congruence rule ,
△ADF ≅ △ECF
⇒ DF = CF [c.p.c.t.]
⇒ ar(△ADF) = ar(△ECF)
Now, DF = CF
⇒ BF is a median in △BDC
⇒ ar(△BDC) = 2 ar(△DFB)
= 2 × 3 = 6 cm2 [∵ar(△DFB) = 3 cm2]
Thus, ar(||gm ABCD) = 2 ar(△BDC)
= 2 × 6 = 12 cm2
Posted by Mamta Patidar 5 years, 3 months ago
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Posted by Mamta Patidar 5 years, 3 months ago
- 3 answers
Posted by Jahanvi Thakur 5 years, 3 months ago
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Chaitanya Saini 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
(x + a) ( x + b) = x2 + (a+b)x + ab
(x+4) (x+10) = x2 + ( 4 + 10)x + 4(10)
= x2 + 14x + 40
Yaduvanshi## Vansh$$ 5 years, 3 months ago
Posted by Aiswarya Raanee .K 5 years, 3 months ago
- 4 answers
Khushi Gupta 5 years, 3 months ago
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