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Ask QuestionPosted by Usha Upadhyay 3 years, 10 months ago
- 1 answers
Posted by Nazneen Khan 3 years, 10 months ago
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Shivani Yadav 3 years, 10 months ago
Posted by K Sriprada 3 years, 10 months ago
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Shivani Yadav 3 years, 10 months ago
Posted by Řøýåľ Jāâţ 3 years, 10 months ago
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Gaurav Seth 3 years, 10 months ago
It can be observed that ΔADX and ΔACX lie on the same base AX and are between the same parallels AB and DC.
⊥ Area (ΔADX) = Area (ΔACX) ... (1)
ΔACY and ΔACX lie on the same base AC and are between the same parallels AC and XY.
⊥ Area (ΔACY) = Area (ACX) ... (2)
From equations (1) and (2), we obtain
Area (ΔADX) = Area (ΔACY)
Posted by Anesh Fernandez 3 years, 10 months ago
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Tanay Lathi 3 years, 10 months ago
Posted by Anesh Fernandez 3 years, 10 months ago
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Posted by R Divya Rajendran 3 years, 11 months ago
- 2 answers
Yogita Ingle 3 years, 11 months ago
5x-3y=3
x=0and y=k
5(0) - 3k = 3
0 - 3k = 3
k = 3/-3 = -1
Posted by Anshika Dubey 3 years, 11 months ago
- 1 answers
Romeo_ Gaming 3 years, 11 months ago
Posted by Abhishek Gautam 3 years, 11 months ago
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Posted by Sia Sharma 3 years, 11 months ago
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Gaurav Seth 3 years, 10 months ago
ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that
(i) D is the mid-point of AC
(ii) MD ⊥ AC
(iii) CM = MA = ½ AB
Solution:
(i) In ΔACB,
M is the midpoint of AB and MD || BC
, D is the midpoint of AC (Converse of mid point theorem)
(ii) ∠ACB = ∠ADM (Corresponding angles)
also, ∠ACB = 90°
, ∠ADM = 90° and MD ⊥ AC
(iii) In ΔAMD and ΔCMD,
AD = CD (D is the midpoint of side AC)
∠ADM = ∠CDM (Each 90°)
DM = DM (common)
, ΔAMD ≅ ΔCMD [SAS congruency]
AM = CM [CPCT]
also, AM = ½ AB (M is midpoint of AB)
Hence, CM = MA = ½ AB
Posted by Arun Kushwah 3 years, 11 months ago
- 1 answers
Yogita Ingle 3 years, 11 months ago
We have,
(99)3 =(100−1)3
We know that
(a−b)3=a3−b3−3ab(a−b)
Therefore,
=(100)3−13−3×100×1×(100−1)
=1000000−1−300(100−1)
=1000000−1−30000+300
=970299
Posted by Arun Kushwah 3 years, 11 months ago
- 2 answers
Posted by Arun Kushwah 3 years, 11 months ago
- 1 answers
Gaurav Seth 3 years, 10 months ago
Total number of families
= 475 + 814 + 211 = 1500
(i) Probability of a family, chosen at random,
having 2 girls = 
(ii) Probability of a family, chosen at random,
having 1 girl 
(iii) Probability of a family, chosen at random,
having no girl 
Sum of these probabilities
Hence, the sum is checked.
Posted by Arun Kushwah 3 years, 11 months ago
- 1 answers
Yogita Ingle 3 years, 11 months ago
Perimeter of isosceles triangle=30cm
Length of equal sides=12cm
Let third side of triangle=xcm
According to problem,
x+12+12=30
x+24=30
x=30−24
x=6
∴ Third side of triangle=6cm
Using Heron's formula
Area of triangle= √s(s−a)(s−b)(s−c) sq. units
where s= a+b+c/2
s= 30/2 =15
Area of triangle= √15(15−12)(15−12)(15−6) cm²
= √15×3×3×9 cm²
=3×3× √15cm²
=9√15cm²
∴ Area of triangle=9√15 cm
Posted by Arun Kushwah 3 years, 11 months ago
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Posted by Supriya Pattanayak 3 years, 11 months ago
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Punit Yadav 3 years, 11 months ago
Posted by Nidhi Shukla 3 years, 11 months ago
- 3 answers
Yogita Ingle 3 years, 11 months ago
If slant height is l and height is h and radius is r
As they form right angle triangle, By applying the Pythagorean Theorem,
then, the relation between them is represented as
l2 = h2 + r2
Punit Yadav 3 years, 11 months ago
Posted by Bom Tayeng 3 years, 11 months ago
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Posted by Hemu Prajapat Kumari 3 years, 10 months ago
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Gaurav Seth 3 years, 10 months ago
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Posted by Sweta Yadav 3 years, 11 months ago
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Punit Yadav 3 years, 11 months ago
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Posted by Tanshu Sharma 3 years, 11 months ago
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Yogita Ingle 3 years, 11 months ago
If the opposite angles of a quadrilateral are equal, it is a parallelogram. The diagonals of a parallelogram bisect each other. If the diagonals of a quadrilateral bisect each other, it is a parallelogram. If one pair of opposite sides of a quadrilateral is equal and parallel, then the quadrilateral is a parallelogram.
Posted by Chetan Choudhary 3 years, 11 months ago
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Posted by Zainab Bano 3 years, 11 months ago
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Hemu Prajapat Kumari 3 years, 11 months ago
Posted by Siddhant Gautam 3 years, 11 months ago
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Yogita Ingle 3 years, 11 months ago
Let ABCD be the parallelogram
Consider triangles ABC, BAD
AB=BA ... Common side
BC=AD ... Opp sides of llgm are equal
AC = BD ... Given
So triangles become cong by SSS rule.
Angle BAD = angle ABC ... CPCT
But sum of these angles is 180 as they are adjacent angles of llgm
So we can conclude that if each is equal to x
Therefore, 2x=180
Therefore, x=90
Thus ABCD is a parallelogram with one angle = 90 degrees
So, by the definition of parallelogram this is a rectangle.
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Gaurav Seth 3 years, 10 months ago
Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
Ask specific question which are clear and concise.
If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html
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